結果
問題 | No.1695 Mirror Mirror |
ユーザー |
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提出日時 | 2021-10-01 23:14:21 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 200 ms / 2,000 ms |
コード長 | 2,820 bytes |
コンパイル時間 | 4,766 ms |
コンパイル使用メモリ | 254,964 KB |
最終ジャッジ日時 | 2025-01-24 19:26:19 |
ジャッジサーバーID (参考情報) |
judge1 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 61 |
ソースコード
#include<bits/stdc++.h>#include<atcoder/all>using namespace std;using namespace atcoder;#define rep(i,n)for (int i = 0; i < int(n); ++i)#define rrep(i,n)for (int i = int(n)-1; i >= 0; --i)#define all(x) (x).begin(), (x).end()#define rall(x) (x).rbegin(), (x).rend()template<class T> void chmax(T& a, const T& b) {a = max(a, b);}template<class T> void chmin(T& a, const T& b) {a = min(a, b);}using ll = long long;using P = pair<int,int>;using VI = vector<int>;using VVI = vector<VI>;using VL = vector<ll>;using VVL = vector<VL>;template <class S, S (*op)(S, S), S (*e)()> struct SparseTable {int n;std::vector<int> floor_lg;std::vector<std::vector<S>> d;explicit SparseTable(std::vector<S>&& a): n(a.size()), floor_lg(n + 1) {if (n == 0) return;int frog = 0;for(int i = 1; i <= n; frog++) {int j = std::min(n + 1, 2 * i);for(; i < j; i++) floor_lg[i] = frog;}d.resize(frog);d[0] = std::move(a);for(int p = 0, w = 1; p < frog - 1; p++, w *= 2) {int last = n - 2 * w;d[p + 1].resize(last + 1);for(int i = 0; i <= last; i++) d[p + 1][i] = op(d[p][i], d[p][i + w]);}}explicit SparseTable(const std::vector<S>& a): SparseTable(std::vector<S>(a)) {}S query(int l, int r) {assert(0 <= l && l <= r && r <= n);if (l >= r) return e();int w = r - l;int p = floor_lg[w];return op(d[p][l], d[p][r - (1 << p)]);}};int op(int x, int y) { return min(x, y); }int e() { return 1001001001;}int op2(int x, int y) { return max(x, y);}int e2() { return -1; }int main() {ios::sync_with_stdio(false);cin.tie(0);int n, m;cin >> n >> m;string s, t;cin >> s >> t;constexpr int INF = 1001001001;int mx = 0;rep(_, 2) {int l = min(n, m);rep(i, l) {if (s[i] != t[i]) break;chmax(mx, i + 1);}reverse(all(s));}t += '$';rep(i, m) t += t[m - 1 - i];auto sa = suffix_array(t);VI sa_inv(2 * m + 1);rep(i, 2 * m + 1) sa_inv[sa[i]] = i;auto rmq = SparseTable<int, op, e>(lcp_array(t, sa));VI d(m + 1);for(int i = 1; i < m; i++) {int idx1 = sa_inv[i], idx2 = sa_inv[2 * m + 1 - i];if (idx1 > idx2) swap(idx1, idx2);d[i] = i + rmq.query(idx1, idx2);}d[m] = m;segtree<int, op2, e2> seg(d);int r = m;for(int t = 1;; t++) {int c = (r + 1) / 2;int nr = seg.max_right(c, [&](int x) { return x < r; });if (nr <= mx) {cout << t << endl;return 0;} else if (nr == r) {cout << -1 << endl;return 0;}r = nr;}}