結果
問題 | No.1696 Nonnil |
ユーザー |
|
提出日時 | 2021-10-02 00:15:26 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 302 ms / 3,500 ms |
コード長 | 7,490 bytes |
コンパイル時間 | 2,324 ms |
コンパイル使用メモリ | 208,872 KB |
最終ジャッジ日時 | 2025-01-24 19:46:35 |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 39 |
ソースコード
#include <bits/stdc++.h>using namespace std;#define rep(i, n) for (int i = 0; i < n; i++)#define rep2(i, x, n) for (int i = x; i <= n; i++)#define rep3(i, x, n) for (int i = x; i >= n; i--)#define each(e, v) for (auto &e : v)#define pb push_back#define eb emplace_back#define all(x) x.begin(), x.end()#define rall(x) x.rbegin(), x.rend()#define sz(x) (int)x.size()using ll = long long;using pii = pair<int, int>;using pil = pair<int, ll>;using pli = pair<ll, int>;using pll = pair<ll, ll>;template <typename T>bool chmax(T &x, const T &y) {return (x < y) ? (x = y, true) : false;}template <typename T>bool chmin(T &x, const T &y) {return (x > y) ? (x = y, true) : false;}template <typename T>int flg(T x, int i) {return (x >> i) & 1;}template <typename T>void print(const vector<T> &v, T x = 0) {int n = v.size();for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' ');}template <typename T>void printn(const vector<T> &v, T x = 0) {int n = v.size();for (int i = 0; i < n; i++) cout << v[i] + x << '\n';}template <typename T>int lb(const vector<T> &v, T x) {return lower_bound(begin(v), end(v), x) - begin(v);}template <typename T>int ub(const vector<T> &v, T x) {return upper_bound(begin(v), end(v), x) - begin(v);}template <typename T>void rearrange(vector<T> &v) {sort(begin(v), end(v));v.erase(unique(begin(v), end(v)), end(v));}template <typename T>vector<int> id_sort(const vector<T> &v, bool greater = false) {int n = v.size();vector<int> ret(n);iota(begin(ret), end(ret), 0);sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; });return ret;}struct io_setup {io_setup() {ios_base::sync_with_stdio(false);cin.tie(NULL);cout << fixed << setprecision(15);}} io_setup;const int inf = (1 << 30) - 1;const ll INF = (1LL << 60) - 1;// const int MOD = 1000000007;const int MOD = 998244353;template <int mod>struct Mod_Int {int x;Mod_Int() : x(0) {}Mod_Int(long long y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}static int get_mod() { return mod; }Mod_Int &operator+=(const Mod_Int &p) {if ((x += p.x) >= mod) x -= mod;return *this;}Mod_Int &operator-=(const Mod_Int &p) {if ((x += mod - p.x) >= mod) x -= mod;return *this;}Mod_Int &operator*=(const Mod_Int &p) {x = (int)(1LL * x * p.x % mod);return *this;}Mod_Int &operator/=(const Mod_Int &p) {*this *= p.inverse();return *this;}Mod_Int &operator++() { return *this += Mod_Int(1); }Mod_Int operator++(int) {Mod_Int tmp = *this;++*this;return tmp;}Mod_Int &operator--() { return *this -= Mod_Int(1); }Mod_Int operator--(int) {Mod_Int tmp = *this;--*this;return tmp;}Mod_Int operator-() const { return Mod_Int(-x); }Mod_Int operator+(const Mod_Int &p) const { return Mod_Int(*this) += p; }Mod_Int operator-(const Mod_Int &p) const { return Mod_Int(*this) -= p; }Mod_Int operator*(const Mod_Int &p) const { return Mod_Int(*this) *= p; }Mod_Int operator/(const Mod_Int &p) const { return Mod_Int(*this) /= p; }bool operator==(const Mod_Int &p) const { return x == p.x; }bool operator!=(const Mod_Int &p) const { return x != p.x; }Mod_Int inverse() const {assert(*this != Mod_Int(0));return pow(mod - 2);}Mod_Int pow(long long k) const {Mod_Int now = *this, ret = 1;for (; k > 0; k >>= 1, now *= now) {if (k & 1) ret *= now;}return ret;}friend ostream &operator<<(ostream &os, const Mod_Int &p) { return os << p.x; }friend istream &operator>>(istream &is, Mod_Int &p) {long long a;is >> a;p = Mod_Int<mod>(a);return is;}};using mint = Mod_Int<MOD>;template <typename T>struct Combination {static vector<T> _fac, _ifac;Combination() {}static void init(int n) {_fac.resize(n + 1), _ifac.resize(n + 1);_fac[0] = 1;for (int i = 1; i <= n; i++) _fac[i] = _fac[i - 1] * i;_ifac[n] = _fac[n].inverse();for (int i = n; i >= 1; i--) _ifac[i - 1] = _ifac[i] * i;}static T fac(int k) { return _fac[k]; }static T ifac(int k) { return _ifac[k]; }static T inv(int k) { return fac(k - 1) * ifac(k); }static T P(int n, int k) {if (k < 0 || n < k) return 0;return fac(n) * ifac(n - k);}static T C(int n, int k) {if (k < 0 || n < k) return 0;return fac(n) * ifac(n - k) * ifac(k);}static T H(int n, int k) { // k個の区別できない玉をn個の区別できる箱に入れる場合の数if (n < 0 || k < 0) return 0;return k == 0 ? 1 : C(n + k - 1, k);}static T second_stirling_number(int n, int k) { // n個の区別できる玉を、k個の区別しない箱に、各箱に1個以上玉が入るように入れる場合の数T ret = 0;for (int i = 0; i <= k; i++) {T tmp = C(k, i) * T(i).pow(n);ret += ((k - i) & 1) ? -tmp : tmp;}return ret * ifac(k);}static T bell_number(int n, int k) { // n個の区別できる玉を、k個の区別しない箱に入れる場合の数if (n == 0) return 1;k = min(k, n);vector<T> pref(k + 1);pref[0] = 1;for (int i = 1; i <= k; i++) {if (i & 1) {pref[i] = pref[i - 1] - ifac(i);} else {pref[i] = pref[i - 1] + ifac(i);}}T ret = 0;for (int i = 1; i <= k; i++) ret += T(i).pow(n) * ifac(i) * pref[k - i];return ret;}};template <typename T>vector<T> Combination<T>::_fac = vector<T>();template <typename T>vector<T> Combination<T>::_ifac = vector<T>();using comb = Combination<mint>;int main() {int N, K, M;cin >> N >> K >> M;comb::init(K);vector<mint> c(K + 1); // ちょうどi要素が使われるrep(i, K + 1) c[i] = comb::second_stirling_number(N, i) * comb::fac(i);vector<int> l(M), r(M);rep(i, M) {cin >> l[i] >> r[i];// l[i]--, r[i]--;}vector<int> v(M);iota(all(v), 0);sort(all(v), [&](int i, int j) {if (l[i] != l[j]) return l[i] < l[j];return r[i] > r[j];});vector<int> L, R;L.eb(0), R.eb(0);each(e, v) {while (!empty(R)) {if (R.back() >= r[e]) {L.pop_back();R.pop_back();} else {break;}}L.eb(l[e]), R.eb(r[e]);}L.eb(K + 1), R.eb(K + 1);K++;vector<vector<mint>> dp(K + 1, vector<mint>(K + 1, 0));dp[0][0] = 1;vector<vector<mint>> s(K + 1, vector<mint>(K + 1, 0));s[0][0] = 1;rep2(i, 1, K) {int p = L[lb(R, i) - 1]; // pまで埋まってればOK// cout << i << ' ' << p << '\n';rep2(j, 1, K) dp[i][j] += s[j - 1][i - 1] - (p > 0 ? s[j - 1][p - 1] : 0);rep2(j, 0, K) s[j][i] = s[j][i - 1] + dp[i][j];}// print(c);mint ans = 0;rep2(j, 1, K) ans += dp[K][j] * c[j - 1];cout << ans << '\n';}