結果
問題 | No.1706 Many Bus Stops (hard) |
ユーザー | PCTprobability |
提出日時 | 2021-10-08 22:16:27 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 5,206 bytes |
コンパイル時間 | 4,812 ms |
コンパイル使用メモリ | 273,308 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-07-23 04:44:57 |
合計ジャッジ時間 | 6,128 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
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testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
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testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
testcase_20 | WA | - |
testcase_21 | WA | - |
testcase_22 | WA | - |
testcase_23 | WA | - |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | WA | - |
testcase_27 | WA | - |
testcase_28 | WA | - |
testcase_29 | WA | - |
testcase_30 | WA | - |
testcase_31 | WA | - |
testcase_32 | WA | - |
testcase_33 | WA | - |
testcase_34 | WA | - |
testcase_35 | WA | - |
testcase_36 | WA | - |
testcase_37 | WA | - |
testcase_38 | WA | - |
testcase_39 | WA | - |
testcase_40 | WA | - |
testcase_41 | WA | - |
testcase_42 | WA | - |
ソースコード
#include <bits/stdc++.h> using namespace std; #if __has_include(<atcoder/all>) #include <atcoder/all> using namespace atcoder; #endif using ll = long long; using ld = long double; using ull = unsigned long long; #define endl "\n" typedef pair<int, int> Pii; #define REP(i, n) for (int i = 0; i < (n); ++i) #define REP3(i, m, n) for (int i = (m); (i) < int(n); ++ (i)) #define FOR(i,a,b) for(ll i=a;i<=(ll)(b);i++) #define rep(i,a,b) for(int i=(int)(a);i<(int)(b);i++) #define ALL(x) begin(x), end(x) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define fore(i,a) for(auto &i:a) #define all(s) (s).begin(),(s).end() #define drep2(i, m, n) for (int i = (m)-1; i >= (n); --i) #define drep(i, n) drep2(i, n, 0) #define rever(vec) reverse(vec.begin(), vec.end()) #define sor(vec) sort(vec.begin(), vec.end()) #define fi first #define se second #define pb push_back #define P pair<ll,ll> #define PQminll priority_queue<ll, vector<ll>, greater<ll>> #define PQmaxll priority_queue<ll,vector<ll>,less<ll>> #define PQminP priority_queue<P, vector<P>, greater<P>> #define PQmaxP priority_queue<P,vector<P>,less<P>> #define NP next_permutation typedef string::const_iterator State; class ParseError {}; //const ll mod = 1000000009; const ll mod = 998244353; //const ll mod = 1000000007; const ll inf = 4100000000000000000ll; const ld eps = ld(0.00000000001); //static const long double pi = 3.141592653589793; template<class T>void vcin(vector<T> &n){for(int i=0;i<int(n.size());i++) cin>>n[i];} template<class T,class K>void vcin(vector<T> &n,vector<K> &m){for(int i=0;i<int(n.size());i++) cin>>n[i]>>m[i];} template<class T>void vcout(vector<T> &n){for(int i=0;i<int(n.size());i++){cout<<n[i]<<" ";}cout<<endl;} template<class T>void vcin(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cin>>n[i][j];}}} template<class T>void vcout(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cout<<n[i][j]<<" ";}cout<<endl;}cout<<endl;} void yes(bool a){cout<<(a?"yes":"no")<<endl;} void YES(bool a){cout<<(a?"YES":"NO")<<endl;} void Yes(bool a){cout<<(a?"Yes":"No")<<endl;} void possible(bool a){ cout<<(a?"possible":"impossible")<<endl; } void Possible(bool a){ cout<<(a?"Possible":"Impossible")<<endl; } void POSSIBLE(bool a){ cout<<(a?"POSSIBLE":"IMPOSSIBLE")<<endl; } template<class T>auto min(const T& a){ return *min_element(all(a)); } template<class T>auto max(const T& a){ return *max_element(all(a)); } template<class T,class F>void print(pair<T,F> a){cout<<a.fi<<" "<<a.se<<endl;} template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0;} template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0;} template<class T> void ifmin(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}} template<class T> void ifmax(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}} ll fastgcd(ll u,ll v){ll shl=0;while(u&&v&&u!=v){bool eu=!(u&1);bool ev=!(v&1);if(eu&&ev){++shl;u>>=1;v>>=1;}else if(eu&&!ev){u>>=1;}else if(!eu&&ev){v>>=1;}else if(u>=v){u=(u-v)>>1;}else{ll tmp=u;u=(v-u)>>1;v=tmp;}}return !u?v<<shl:u<<shl;} ll modPow(ll a, ll n, ll mod) { if(mod==1) return 0;ll ret = 1; ll p = a % mod; while (n) { if (n & 1) ret = ret * p % mod; p = p * p % mod; n >>= 1; } return ret; } vector<ll> divisor(ll x){ vector<ll> ans; for(ll i = 1; i * i <= x; i++){ if(x % i == 0) {ans.push_back(i); if(i*i!=x){ ans.push_back(x / ans[i]);}}}sor(ans); return ans; } ll pop(ll x){return __builtin_popcountll(x);} ll poplong(ll x){ll y=-1;while(x){x/=2;y++;}return y;} P hyou(P a){ll x=fastgcd(abs(a.fi),abs(a.se));a.fi/=x;a.se/=x;if(a.se<0){a.fi*=-1;a.se*=-1;}return a;} P Pplus(P a,P b){ return hyou({a.fi*b.se+b.fi*a.se,a.se*b.se});} P Ptimes(P a,ll b){ return hyou({a.fi*b,a.se});} P Ptimes(P a,P b){ return hyou({a.fi*b.fi,a.se*b.se});} P Pminus(P a,P b){ return hyou({a.fi*b.se-b.fi*a.se,a.se*b.se});} P Pgyaku(P a){ return hyou({a.se,a.fi});} void cincout(){ ios::sync_with_stdio(false); std::cin.tie(nullptr); cout<< fixed << setprecision(15); } using mint = modint1000000007; vector<vector<mint>> multi(vector<vector<mint>> &a,vector<vector<mint>> &b){ vector<vector<mint>> c(a.size(),vector<mint>(b[0].size())); for(int i=0;i<int(a.size());i++){ for(int k=0;k<int(b.size());k++){ for(int j=0;j<int(b[0].size());j++){ c[i][j]+=a[i][k]*b[k][j]; } } } return c; } vector<vector<mint>> mul_exp(vector<vector<mint>> adj, ll k){ if (k == 1) return adj; vector<vector<mint>> res(int(adj.size()),vector<mint>(int(adj[0].size()))); for(int i=0;i<int(adj.size());i++){ res[i][i]=1; } while(k>0){ if(k&1) res=multi(adj,res); adj=multi(adj,adj); k/=2; } return res; } void solve(){ ll c,n,m; cin>>c>>n>>m; vector<vector<mint>> d(4,vector<mint>(4)); d[0][2]=1; d[1][3]=1; d[2][2]=1; d[3][3]=1; d[2][1]=c-1; d[3][0]=1; d[3][1]=c-2; d=mul_exp(d,n-1); mint now=d[2][0]+d[2][2]; //cout<<now.val()<<endl; now/=mint(c).pow(n); // cout<<now.val()<<endl; now=1-now; now=mint(now).pow(m); now=1-now; cout<<now.val()<<endl; } int main() { cincout(); ll t; t=1; while(t--){ solve(); } }