結果

問題 No.1702 count good string
ユーザー hamath
提出日時 2021-10-08 22:21:08
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 179 ms / 2,000 ms
コード長 5,326 bytes
コンパイル時間 2,650 ms
コンパイル使用メモリ 221,600 KB
最終ジャッジ日時 2025-01-24 22:30:26
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 47
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#ifdef LOCAL
//#define _GLIBCXX_DEBUG
#endif
//#pragma GCC target("avx512f,avx512dq,avx512cd,avx512bw,avx512vl")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<ll, ll> P;
typedef pair<int, int> Pi;
typedef vector<ll> Vec;
typedef vector<int> Vi;
typedef vector<string> Vs;
typedef vector<char> Vc;
typedef vector<P> VP;
typedef vector<vector<ll>> VV;
typedef vector<vector<int>> VVi;
typedef vector<vector<char>> VVc;
typedef vector<vector<vector<ll>>> VVV;
typedef vector<vector<vector<vector<ll>>>> VVVV;
#define endl '\n'
#define REP(i, a, b) for(ll i=(a); i<(b); i++)
#define PER(i, a, b) for(ll i=(a); i>=(b); i--)
#define rep(i, n) REP(i, 0, n)
#define per(i, n) PER(i, n, 0)
const ll INF=1e18+18;
const ll MOD=1000000007;
#define Yes(n) cout << ((n) ? "Yes" : "No") << endl;
#define YES(n) cout << ((n) ? "YES" : "NO") << endl;
#define ALL(v) v.begin(), v.end()
#define rALL(v) v.rbegin(), v.rend()
#define pb(x) push_back(x)
#define mp(a, b) make_pair(a,b)
#define Each(a,b) for(auto &a :b)
#define rEach(i, mp) for (auto i = mp.rbegin(); i != mp.rend(); ++i)
#ifdef LOCAL
#define dbg(x_) cerr << #x_ << ":" << x_ << endl;
#define dbgmap(mp) cerr << #mp << ":"<<endl; for (auto i = mp.begin(); i != mp.end(); ++i) { cerr << i->first <<":"<<i->second << endl;}
#define dbgset(st) cerr << #st << ":"<<endl; for (auto i = st.begin(); i != st.end(); ++i) { cerr << *i <<" ";}cerr<<endl;
#define dbgarr(n,m,arr) rep(i,n){rep(j,m){cerr<<arr[i][j]<<" ";}cerr<<endl;}
#define dbgdp(n,arr) rep(i,n){cerr<<arr[i]<<" ";}cerr<<endl;
#else
#define dbg(...)
#define dbgmap(...)
#define dbgset(...)
#define dbgarr(...)
#define dbgdp(...)
#endif
#define out(a) cout<<a<<endl
#define out2(a,b) cout<<a<<" "<<b<<endl
#define vout(v) rep(i,v.size()){cout<<v[i]<<" ";}cout<<endl
#define Uniq(v) v.erase(unique(v.begin(), v.end()), v.end())
#define fi first
#define se second
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }
template<typename T1, typename T2>
ostream &operator<<(ostream &s, const pair<T1, T2> &p) { return s<<"("<<p.first<<", "<<p.second<<")"; }
template<typename T>istream& operator>>(istream&i,vector<T>&v)
{rep(j,v.size())i>>v[j];return i;}
// vector
template<typename T>
ostream &operator<<(ostream &s, const vector<T> &v) {
int len=v.size();
for(int i=0; i<len; ++i) {
s<<v[i];
if(i<len-1) s<<" ";
}
return s;
}
// 2 dimentional vector
template<typename T>
ostream &operator<<(ostream &s, const vector<vector<T> > &vv) {
s<<endl;
int len=vv.size();
for(int i=0; i<len; ++i) {
s<<vv[i]<<endl;
}
return s;
}
//mint
struct mint {
ll x; // typedef long long ll;
mint(ll x=0):x((x%MOD+MOD)%MOD){}
mint operator-() const { return mint(-x);}
mint& operator+=(const mint a) {
if ((x += a.x) >= MOD) x -= MOD;
return *this;
}
mint& operator-=(const mint a) {
if ((x += MOD-a.x) >= MOD) x -= MOD;
return *this;
}
mint& operator*=(const mint a) { (x *= a.x) %= MOD; return *this;}
mint operator+(const mint a) const { return mint(*this) += a;}
mint operator-(const mint a) const { return mint(*this) -= a;}
mint operator*(const mint a) const { return mint(*this) *= a;}
mint pow(ll n) const {
mint x = *this, r = 1;
while (n) {
if (n & 1) r *= x;
x *= x;
n >>= 1;
}
return r;
}
// for prime MOD
mint inv() const { return pow(MOD-2);}
mint& operator/=(const mint& a) { return *this *= a.inv();}
mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
typedef vector<mint> Vmint;
typedef vector<vector<mint>> VVmint;
typedef vector<vector<vector<mint>>> VVVmint;
struct combination {
vector<mint> fact, ifact;
combination(int n):fact(n+1),ifact(n+1) {
assert(n < MOD);
fact[0] = 1;
for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
ifact[n] = fact[n].inv();
for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
}
mint operator()(int n, int k) {
if (k < 0 || k > n) return 0;
return fact[n]*ifact[k]*ifact[n-k];
}
};
int solve(){
ll n;
cin>>n;
string s;
cin>>s;
string t = "yukicoder";
ll m = t.length();
mint ans = 0;
auto f = [&](string t)->mint{
VVmint dp(n+1, Vmint(m+1));
dp[0][0] = 1;
rep(i,n){
rep(j,m+1){
dp[i+1][j] += dp[i][j];
ll x = s[i];
if(x == t[j] && j < m){
dp[i+1][j+1] += dp[i][j];
}
}
}
return dp[n][m];
};
ans += f(t);
rep(i,m){
string T = t;
T[i] = '?';
ans += f(T);
}
out(ans);
return 0;
}
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
cout<<std::setprecision(10);
// ll T;
// cin>>T;
// while(T--)
solve();
}
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