結果

問題 No.1705 Mode of long array
ユーザー hayaten
提出日時 2021-10-09 13:47:54
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 96 ms / 3,000 ms
コード長 3,674 bytes
コンパイル時間 6,470 ms
コンパイル使用メモリ 304,604 KB
最終ジャッジ日時 2025-01-24 23:52:46
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 51
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ソースコード

diff #
プレゼンテーションモードにする

#pragma region Macros
// #pragma GCC target("avx2")
#pragma GCC optimize("O3")
#include <bits/stdc++.h>
#include <atcoder/all>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <typename T>
using ordered_set =
tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
struct __INIT{__INIT(){cin.tie(0);ios::sync_with_stdio(false);cout<<fixed<<setprecision(15);}} __init;
#define REP(i,n) for(ll i=0;i<ll(n);i++)
#define REPD(i,n) for(ll i=n-1;i>=0;i--)
#define FOR(i,a,b) for(ll i=a;i<=ll(b);i++)
#define FORD(i,a,b) for(ll i=a;i>=ll(b);i--)
#define overload4(_1,_2,_3,_4,name,...) name
#define overload3(_1,_2,_3,name,...) name
#define rep1(n) for(ll i=0;i<n;++i)
#define rep2(i,n) for(ll i=0;i<n;++i)
#define rep3(i,a,b) for(ll i=a;i<b;++i)
#define rep4(i,a,b,c) for(ll i=a;i<b;i+=c)
#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)
#define rrep1(n) for(ll i=n;i--;)
#define rrep2(i,n) for(ll i=n;i--;)
#define rrep3(i,a,b) for(ll i=b;i-->(a);)
#define rrep4(i,a,b,c) for(ll i=(a)+((b)-(a)-1)/(c)*(c);i>=(a);i-=c)
#define rrep(...) overload4(__VA_ARGS__,rrep4,rrep3,rrep2,rrep1)(__VA_ARGS__)
#define ALL(v) v.begin(), v.end()
#define endl "\n"
#define fi first
#define se second
#define popcount(bit) __builtin_popcount(bit)
#define popcountll(bit) __builtin_popcountll(bit)
#define pb push_back
#define eb emplace_back
#define sz(x) ((ll)(x).size())
using namespace atcoder;
using P = pair<int, int>;
using PL = pair<long long, long long>;
using Graph = vector<vector<int>>;
typedef long long ll;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
inline void Yes(bool b = true) { cout << (b ? "Yes" : "No") << '\n'; }
inline void YES(bool b = true) { cout << (b ? "YES" : "NO") << '\n'; }
inline void OKNG(bool b = true) { cout << (b ? "OK" : "NG") << '\n'; }
const int dx[4] = {1, 0, -1, 0};
const int dy[4] = {0, 1, 0, -1};
const int fx[8] = {0, 1, 1, 1, 0, -1, -1, -1};
const int fy[8] = {1, 1, 0, -1, -1, -1, 0, 1};
template <typename T>
const auto INF = numeric_limits<T>::max()/2;
template <typename T>
vector<T> compress(vector<T> &X) {
// vals
vector<T> vals = X;
sort(vals.begin(), vals.end());
// (unique), (erase)
vals.erase(unique(vals.begin(), vals.end()), vals.end());
//
for (int i = 0; i < (int)X.size(); i++) {
X[i] = lower_bound(vals.begin(), vals.end(), X[i]) - vals.begin();
}
return vals;
}
ll op(ll a, ll b){
return max(a, b);
}
ll e(){
return -1;
}
ll target = -1;
bool f(ll v){
return v < target;
}
int main() {
ll n, m;
cin >> n >> m;
vector<ll> A(m);
vector<ll> tmp(m);
rep(i, m){
cin >> A[i];
tmp[i] = i + 1;
}
int q;
cin >> q;
vector<tuple<ll, ll, ll>> query;
rep(i, q){
ll t, x, y;
cin >> t >> x >> y;
tmp.pb(x);
query.pb(make_tuple(t, x, y));
}
vector<ll> res = compress(tmp);
vector<ll> rest(res.size());
rep(i, m){
rest[tmp[i]] = A[i];
}
segtree<ll, op, e> seg(rest);
int g = res.size();
rep(i, q){
auto [a, b, c] = query[i];
if(a == 1){
ll d = tmp[m + i];
ll h = seg.get(d);
h += c;
seg.set(d, h);
}else if(a == 2){
ll d = tmp[m+ i];
ll h = seg.get(d);
h -= c;
seg.set(d, h);
}else{
target = seg.all_prod();
cout << res[seg.min_left<f>(g) - 1] << endl;
}
}
}
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