結果

問題 No.1199 お菓子配り-2
ユーザー cozy_sauna
提出日時 2021-10-10 20:55:19
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
AC  
実行時間 399 ms / 1,000 ms
コード長 1,924 bytes
コンパイル時間 324 ms
コンパイル使用メモリ 12,800 KB
実行使用メモリ 51,840 KB
最終ジャッジ日時 2024-09-14 16:40:50
合計ジャッジ時間 19,361 ms
ジャッジサーバーID
(参考情報)
judge4 / judge6
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 45
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

from sys import setrecursionlimit, stdin
from collections import defaultdict, deque
from itertools import permutations, combinations, product
from functools import lru_cache
from random import sample, choice, randint, random
from heapq import heappush, heappop
from math import factorial, gcd, exp
from copy import copy, deepcopy
from time import time
setrecursionlimit(500000)
readline = stdin.readline
# @lru_cache(maxsize=None)
INF = 10 ** 18
MOD = 1000000007
MOD2 = 998244353
DYDX = [(-1, 0), (1, 0), (0, -1), (0, 1)]
def I(): return int(readline())
def S(): return readline()[:-1]
def LI(): return list(map(int, readline().split()))
def SPI(): return map(int, readline().split())
def SPII(): return map(lambda x: int(x)-1, readline().split())
def FIE(x): return [readline()[:-1] for _ in [0] * x]
def NODE(x): return [[] for _ in [0] * x]
def ranges(*args): return [(i, j) for i in range(args[0]) for j in range(args[-1])]
def nynx(y, x, ly = INF, lx = INF): return [(y+dy, x+dx) for dy, dx in DYDX if 0 <= y+dy < ly and 0 <= x+dx < lx]
def imax(A, idx=-1, m=-(1<<18)):
for i, a in enumerate(A): m, idx = [[m, idx], [a, i]][m < a]
return idx
def imin(A, idx=-1, m=1<<18):
for i, a in enumerate(A): m, idx = [[m, idx], [a, i]][m > a]
return idx
def cmin(dp, i, x):
if x < dp[i]: dp[i] = x
def cmax(dp, i, x):
if x > dp[i]: dp[i] = x
def gen(x, *args):
ret = [x] * args[-1]
for e in args[:-1][::-1]: ret = [deepcopy(ret) for _ in [0] * e]
return ret
def puts(E):
for e in E: print(e)
def pprint(E):
print()
puts(E)
####################################################################
N, M = SPI()
A = [LI() for _ in range(N)]
dp = gen(-INF, N+1, 2)
dp[0][0] = 0
for i, a in enumerate(A):
s = sum(A[i])
# not take
dp[i+1][0] = dp[i][0]
dp[i+1][1] = dp[i][1]
# take
cmax(dp[i+1], 1, dp[i][0]+s)
cmax(dp[i+1], 0, dp[i][1]-s)
print(max(dp[N]))
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