結果
問題 | No.1153 ねこちゃんゲーム |
ユーザー |
![]() |
提出日時 | 2021-10-13 18:19:22 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 996 ms / 2,500 ms |
コード長 | 2,405 bytes |
コンパイル時間 | 153 ms |
コンパイル使用メモリ | 82,236 KB |
実行使用メモリ | 186,016 KB |
最終ジャッジ日時 | 2024-09-17 16:20:45 |
合計ジャッジ時間 | 36,728 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 40 |
ソースコード
import sys# sys.setrecursionlimit(200005)int1 = lambda x: int(x)-1p2D = lambda x: print(*x, sep="\n")def II(): return int(sys.stdin.readline())def LI(): return list(map(int, sys.stdin.readline().split()))def LI1(): return list(map(int1, sys.stdin.readline().split()))def LLI(rows_number): return [LI() for _ in range(rows_number)]def LLI1(rows_number): return [LI1() for _ in range(rows_number)]def SI(): return sys.stdin.readline().rstrip()# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]inf = 10**16# md = 998244353md = 10**9+7from collections import Countern, m = LI()aa = LI1()to = [[] for _ in range(n)]for _ in range(n-1):u, v = LI1()to[u].append(v)to[v].append(u)# ***************ここから本体*****************# 設定root = 0e = lambda: set() # 単位元def op(a, b):if isinstance(b, set): return a | ba.add(b)return adef trans_up(u):for a in range(n):if a not in dp[u]:dp[u] = areturndef trans_down(u):for a in range(n):if a not in rdp[u]:rdp[u] = areturn# dfs順を作るuu = []stack = [root]par = [-1]*nwhile stack:u = stack.pop()uu.append(u)vv = []# ↓変数注意for v in to[u]:if v == par[u]: continuevv.append(v)par[v] = ustack.append(v)to[u] = vv# print("to",to)# print("par",par)dp = [e() for _ in range(n)]rdp = [0 for _ in range(n)]# 下から更新for u in uu[::-1]:p = par[u]if p != -1:trans_up(u)dp[p] = op(dp[p], dp[u])# print("dp",dp)# 上から更新gg = [-1]*nfor u in uu:cnt = Counter(dp[v] for v in to[u])if u != root: cnt[rdp[u]] += 1for g in range(n):if cnt[g] == 0:gg[u] = gbreakfor v in to[u]:if cnt[dp[v]] == 1 and dp[v] < gg[u]:rdp[v] = dp[v]else:rdp[v] = gg[u]# print(gg)g = 0for a in aa: g ^= gg[a]# print(g)if g == 0:print(-1, -1)exit()ln = g.bit_length()-1for i, a in enumerate(aa):if gg[a] >> ln & 1 == 0: continuefor v in to[a]:if g ^ gg[a] ^ dp[v] == 0:print(i+1, v+1)exit()if a != root and g ^ gg[a] ^ rdp[a] == 0:print(i+1, par[a]+1)exit()