結果

問題 No.1153 ねこちゃんゲーム
ユーザー mkawa2
提出日時 2021-10-13 18:19:22
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 996 ms / 2,500 ms
コード長 2,405 bytes
コンパイル時間 153 ms
コンパイル使用メモリ 82,236 KB
実行使用メモリ 186,016 KB
最終ジャッジ日時 2024-09-17 16:20:45
合計ジャッジ時間 36,728 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 40
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
# sys.setrecursionlimit(200005)
int1 = lambda x: int(x)-1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = 10**16
# md = 998244353
md = 10**9+7
from collections import Counter
n, m = LI()
aa = LI1()
to = [[] for _ in range(n)]
for _ in range(n-1):
u, v = LI1()
to[u].append(v)
to[v].append(u)
# ********************************
#
root = 0
e = lambda: set() #
def op(a, b):
if isinstance(b, set): return a | b
a.add(b)
return a
def trans_up(u):
for a in range(n):
if a not in dp[u]:
dp[u] = a
return
def trans_down(u):
for a in range(n):
if a not in rdp[u]:
rdp[u] = a
return
# dfs
uu = []
stack = [root]
par = [-1]*n
while stack:
u = stack.pop()
uu.append(u)
vv = []
# ↓
for v in to[u]:
if v == par[u]: continue
vv.append(v)
par[v] = u
stack.append(v)
to[u] = vv
# print("to",to)
# print("par",par)
dp = [e() for _ in range(n)]
rdp = [0 for _ in range(n)]
#
for u in uu[::-1]:
p = par[u]
if p != -1:
trans_up(u)
dp[p] = op(dp[p], dp[u])
# print("dp",dp)
#
gg = [-1]*n
for u in uu:
cnt = Counter(dp[v] for v in to[u])
if u != root: cnt[rdp[u]] += 1
for g in range(n):
if cnt[g] == 0:
gg[u] = g
break
for v in to[u]:
if cnt[dp[v]] == 1 and dp[v] < gg[u]:
rdp[v] = dp[v]
else:
rdp[v] = gg[u]
# print(gg)
g = 0
for a in aa: g ^= gg[a]
# print(g)
if g == 0:
print(-1, -1)
exit()
ln = g.bit_length()-1
for i, a in enumerate(aa):
if gg[a] >> ln & 1 == 0: continue
for v in to[a]:
if g ^ gg[a] ^ dp[v] == 0:
print(i+1, v+1)
exit()
if a != root and g ^ gg[a] ^ rdp[a] == 0:
print(i+1, par[a]+1)
exit()
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