結果
| 問題 |
No.1715 Dinner 2
|
| コンテスト | |
| ユーザー |
stoq
|
| 提出日時 | 2021-10-22 22:32:29 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 5,952 bytes |
| コンパイル時間 | 2,403 ms |
| コンパイル使用メモリ | 211,936 KB |
| 最終ジャッジ日時 | 2025-01-25 03:58:18 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 37 WA * 1 |
コンパイルメッセージ
main.cpp: In function ‘void solve()’:
main.cpp:193:61: warning: ‘pmin_i2’ may be used uninitialized [-Wmaybe-uninitialized]
193 | if (pmin == pmin2 and (p[pmin_i] <= q[pmin_i] or p[pmin_i2] <= q[pmin_i2]))
| ^
main.cpp:187:7: note: ‘pmin_i2’ was declared here
187 | int pmin_i2;
| ^~~~~~~
ソースコード
#define MOD_TYPE 2
#include <bits/stdc++.h>
using namespace std;
//#include <atcoder/all>
#include <atcoder/modint>
//#include <atcoder/segtree>
using namespace atcoder;
#if 0
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <boost/multiprecision/cpp_int.hpp>
using Int = boost::multiprecision::cpp_int;
using lld = boost::multiprecision::cpp_dec_float_100;
#endif
#if 0
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tag_and_trait.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
using namespace __gnu_pbds;
using namespace __gnu_cxx;
template <typename T>
using extset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#endif
#if 1
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#endif
#pragma region Macros
using ll = long long int;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
template <typename Q_type>
using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>;
#if MOD_TYPE == 1
constexpr ll MOD = ll(1e9 + 7);
#else
#if MOD_TYPE == 2
constexpr ll MOD = 998244353;
#else
constexpr ll MOD = 1000003;
#endif
#endif
using mint = static_modint<MOD>;
constexpr int INF = (int)1e9 + 10;
constexpr ll LINF = (ll)4e18;
constexpr double PI = acos(-1.0);
constexpr double EPS = 1e-11;
constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0};
constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0};
#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define REPI(i, m, n) for (int i = m; i < (int)(n); ++i)
#define repi(i, n) REPI(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << "\n"
#define Yes(n) cout << ((n) ? "Yes" : "No") << "\n"
#define possible(n) cout << ((n) ? "possible" : "impossible") << "\n"
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n"
#define Yay(n) cout << ((n) ? "Yay!" : ":(") << "\n"
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << "\n";
#define UNIQUE(v) v.erase(unique(all(v)), v.end())
struct io_init {
io_init() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
cout << setprecision(30) << setiosflags(ios::fixed);
};
} io_init;
template <typename T>
inline bool chmin(T& a, T b) {
if (a > b) {
a = b;
return true;
}
return false;
}
template <typename T>
inline bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
return false;
}
inline ll CEIL(ll a, ll b) { return (a + b - 1) / b; }
template <typename A, size_t N, typename T>
inline void Fill(A (&array)[N], const T& val) {
fill((T*)array, (T*)(array + N), val);
}
template <typename T>
vector<T> compress(vector<T>& v) {
vector<T> val = v;
sort(all(val)), val.erase(unique(all(val)), val.end());
for (auto&& vi : v) vi = lower_bound(all(val), vi) - val.begin();
return val;
}
template <typename T, typename U>
constexpr istream& operator>>(istream& is, pair<T, U>& p) noexcept {
is >> p.first >> p.second;
return is;
}
template <typename T, typename U>
constexpr ostream& operator<<(ostream& os, pair<T, U> p) noexcept {
os << p.first << " " << p.second;
return os;
}
ostream& operator<<(ostream& os, mint m) {
os << m.val();
return os;
}
ostream& operator<<(ostream& os, modint m) {
os << m.val();
return os;
}
random_device seed_gen;
mt19937_64 engine(seed_gen());
struct BiCoef {
vector<mint> fact_, inv_, finv_;
BiCoef(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) {
fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1);
for (int i = 2; i < n; i++) {
fact_[i] = fact_[i - 1] * i;
inv_[i] = -inv_[MOD % i] * (MOD / i);
finv_[i] = finv_[i - 1] * inv_[i];
}
}
mint c(ll n, ll k) const noexcept {
if (n < k || n < 0 || k < 0) return 0;
return fact_[n] * finv_[k] * finv_[n - k];
}
mint P(ll n, ll k) const noexcept { return c(n, k) * fact_[k]; }
mint H(ll n, ll k) const noexcept { return c(n + k - 1, k); }
mint Ch1(ll n, ll k) const noexcept {
if (n < 0 || k < 0) return 0;
mint res = 0;
for (int i = 0; i < n; i++)
res += c(n, i) * mint(n - i).pow(k) * (i & 1 ? -1 : 1);
return res;
}
mint fact(ll n) const noexcept {
if (n < 0) return 0;
return fact_[n];
}
mint inv(ll n) const noexcept {
if (n < 0) return 0;
return inv_[n];
}
mint finv(ll n) const noexcept {
if (n < 0) return 0;
return finv_[n];
}
};
BiCoef bc(500010);
#pragma endregion
void solve() {
int n, d;
cin >> n >> d;
vector<ll> p(n), q(n);
rep(i, n) cin >> p[i] >> q[i];
ll Max = -LINF;
auto itr = min_element(all(p));
ll pmin = *itr;
int pmin_i = itr - p.begin();
ll pmin2 = LINF;
int pmin_i2;
rep(i, n) {
if (i == pmin_i) continue;
if (chmin(pmin2, p[i])) pmin_i2 = i;
}
bool pass = false;
if (pmin == pmin2 and (p[pmin_i] <= q[pmin_i] or p[pmin_i2] <= q[pmin_i2]))
pass = true;
rep(i, n) rep(j, n) {
if (i == j) continue;
ll Min = 0;
if (d % 2 == 0) {
chmin(Min, -p[i]);
if (d > 2) chmin(Min, -p[i] + q[i] - p[j]);
ll s = -p[i] + q[i] - p[j] + q[j];
if (not pass) chmin(Min, s * (d / 2 - 1) - p[i]);
if (pmin_i != i)
chmin(Min, s * (d / 2 - 1) - p[i] + q[i] - pmin);
else
chmin(Min, s * (d / 2 - 1) - p[i] + q[i] - pmin2);
} else {
chmin(Min, -p[i]);
chmin(Min, -p[i] + q[i] - p[j]);
ll s = -p[i] + q[i] - p[j] + q[j];
chmin(Min, s * ((d - 1) / 2 - 1) - p[i]);
chmin(Min, s * ((d - 1) / 2 - 1) - p[i] + q[i] - p[j]);
if (pmin_i != j)
chmin(Min, s * ((d - 1) / 2 - 1) - p[i] + q[i] - p[j] + q[j] - pmin);
else
chmin(Min, s * ((d - 1) / 2 - 1) - p[i] + q[i] - p[j] + q[j] - pmin2);
}
chmax(Max, Min);
}
cout << Max << "\n";
}
int main() { solve(); }
stoq