結果

問題 No.1715 Dinner 2
ユーザー tarattata1
提出日時 2021-10-22 22:55:17
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 9 ms / 2,000 ms
コード長 4,007 bytes
コンパイル時間 3,579 ms
コンパイル使用メモリ 174,696 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-09-23 06:44:31
合計ジャッジ時間 4,555 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 1
other AC * 38
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <string>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <iterator>
#include <cassert>
#include <numeric>
#include <functional>
#include <ctime>
#include <bitset>
#pragma warning(disable:4996)
#define ATCODER
#ifdef ATCODER
#include <atcoder/all>
#endif
typedef long long ll;
typedef unsigned long long ull;
#define LINF 9223300000000000000
#define LINF2 1223300000000000000
#define LINF3 1000000000000
#define INF 2140000000
//const long long MOD = 1000000007;
const long long MOD = 998244353;
using namespace std;
#ifdef ATCODER
using namespace atcoder;
#endif
void solve()
{
int n, d;
scanf("%d%d", &n, &d);
vector<int> p(n), q(n), a(n);
vector<pair<int, int>> z; // p[i],i
for (int i = 0; i < n; i++) {
scanf("%d%d", &p[i], &q[i]);
a[i] = -p[i] + q[i];
z.push_back(make_pair(p[i], i));
}
sort(z.begin(), z.end());
vector<vector<int>> vv(n, vector<int>(3,-1));
set<pair<int, int>> ss;
for (int i = 0; i < n; i++) {
int id = z[i].second;
ss.insert(make_pair(a[id], id));
auto it0 = ss.rbegin();
vv[i][0]= it0->second;
it0++;
if (it0 == ss.rend()) {
continue;
}
vv[i][1] = it0->second;
it0++;
if (it0 == ss.rend()) {
continue;
}
vv[i][2] = it0->second;
}
int l = -1, r = 1000000000;
while (r - l > 1) {
int m = (l + r) / 2;
int bad = 0;
map<int, int> mp0;
for (int i = 0; i < d; i++) {
if (i == 0) {
int val = 0;
int diff = m;
int k = lower_bound(z.begin(), z.end(), make_pair(diff + 1, -INF))-z.begin();
k--;
if (k < 0) {
bad = 1;
break;
}
for (int aa = 0; aa < 3; aa++) {
if (vv[k][aa] >= 0) {
int idne = vv[k][aa];
int valne = val + a[idne];
mp0[idne] = valne;
}
}
if (mp0.empty()) {
bad = 1;
break;
}
}
else {
map<int, int> mp;
auto it0 = mp0.begin();
for (; it0 != mp0.end(); ++it0) {
int val = it0->second;
int diff = m + val;
int k = lower_bound(z.begin(), z.end(), make_pair(diff + 1, -INF)) - z.begin();
k--;
if (k < 0) {
continue;
}
for (int aa = 0; aa < 3; aa++) {
if (vv[k][aa] >= 0) {
int id = it0->first;
int idne = vv[k][aa];
if (idne == id) continue;
int valne = val + a[idne];
auto it1 = mp.find(idne);
if (it1 == mp.end()) {
mp[idne] = valne;
}
else {
mp[idne] = max(mp[idne], valne);
}
}
}
}
if (mp.empty()) {
bad = 1;
break;
}
mp0.swap(mp);
}
}
if (bad) {
l = m;
}
else {
r = m;
}
}
printf("%d\n", -r);
return;
}
int main()
{
#if 1
solve();
#else
int T, t;
scanf("%d", &T);
for (t = 0; t < T; t++) {
//printf("Case #%d: ", t + 1);
solve();
}
#endif
return 0;
}
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