結果
問題 |
No.1717 Levi-Civita Triangle
|
ユーザー |
|
提出日時 | 2021-10-22 22:59:42 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,353 bytes |
コンパイル時間 | 543 ms |
コンパイル使用メモリ | 82,300 KB |
実行使用メモリ | 108,772 KB |
最終ジャッジ日時 | 2024-09-23 06:52:08 |
合計ジャッジ時間 | 4,532 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 WA * 1 |
other | AC * 27 WA * 15 |
ソースコード
N = int(input()) As = list(map(int, input().split())) cnt = 0 while len(As) >= 3 and cnt <= 0: cnt += 1 Bs = [None]*(len(As)-2) for i in range(1, len(As)-1): if (As[i - 1] == 0 and As[i] == 1 and As[i + 1] == 2): Bs[i - 1] = 1 elif (As[i - 1] == 1 and As[i] == 2 and As[i + 1] == 0): Bs[i - 1] = 1 elif (As[i - 1] == 2 and As[i] == 0 and As[i + 1] == 1): Bs[i - 1] = 1 elif (As[i - 1] == 2 and As[i] == 1 and As[i + 1] == 0): Bs[i - 1] = 2 elif (As[i - 1] == 1 and As[i] == 0 and As[i + 1] == 2): Bs[i - 1] = 2 elif (As[i - 1] == 0 and As[i] == 2 and As[i + 1] == 1): Bs[i - 1] = 2 else: Bs[i - 1] = 0 As = Bs # print(As) if (len(As) == 1): print(As[0]) exit() if all(i == 0 for i in As[1::2]): if all(i == 1 for i in As[::4]) and all(i == 2 for i in As[2::4]) and len(As) % 4 == 3: print(1) elif all(i == 2 for i in As[::4]) and all(i == 1 for i in As[2::4]) and len(As) % 4 == 1: print(2) elif all(i == 1 for i in As[::4]) and all(i == 2 for i in As[2::4]) and len(As) % 4 == 1: print(2) elif all(i == 2 for i in As[::4]) and all(i == 1 for i in As[2::4]) and len(As) % 4 == 3: print(1) else: print(0) else: print(0)