結果

問題 No.1707 Simple Range Reverse Problem
ユーザー snukesnuke
提出日時 2021-10-27 04:56:03
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 2,939 bytes
コンパイル時間 2,346 ms
コンパイル使用メモリ 198,796 KB
最終ジャッジ日時 2025-01-25 07:35:39
ジャッジサーバーID
（参考情報） 		judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 18
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int getInt()’:
main.cpp:24:25: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   24 | int getInt(){int x;scanf("%d",&x);return x;}
      |                    ~~~~~^~~~~~~~~
main.cpp: In function ‘int main()’:
main.cpp:72:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   72 |   scanf("%d",&ts);
      |   ~~~~~^~~~~~~~~~
main.cpp: In member function ‘void Solver::solve()’:
main.cpp:48:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   48 |     scanf("%d",&n);
      |     ~~~~~^~~~~~~~~

ソースコード

diff # 

#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rrep(i,n) for(int i = 1; i <= (n); ++i)
#define drep(i,n) for(int i = (n)-1; i >= 0; --i)
#define srep(i,s,t) for (int i = s; i < (t); ++i)
#define rng(a) a.begin(),a.end()
#define rrng(a) a.rbegin(),a.rend()
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define snuke srand((unsigned)clock()+(unsigned)time(NULL));
#define newline puts("")
using namespace std;
template<typename T> using vc = vector<T>;
template<typename T> using vv = vc<vc<T>>;
template<typename T> using PQ = priority_queue<T,vc<T>,greater<T>>;
using uint = unsigned; using ull = unsigned long long;
using vi = vc<int>; using vvi = vv<int>;
using ll = long long; using vl = vc<ll>; using vvl = vv<ll>;
using P = pair<int,int>; using vp = vc<P>;
int getInt(){int x;scanf("%d",&x);return x;}
vi pm(int n, int s=0) { vi a(n); iota(rng(a),s); return a;}
template<typename T>istream& operator>>(istream&i,vc<T>&v){rep(j,sz(v))i>>v[j];return i;}
template<typename T>string join(const T&v,const string& d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();}
template<typename T>ostream& operator<<(ostream&o,const vc<T>&v){if(sz(v))o<<join(v," ");return o;}
template<typename T1,typename T2>istream& operator>>(istream&i,pair<T1,T2>&v){return i>>v.fi>>v.se;}
template<typename T1,typename T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.fi<<","<<v.se;}
template<typename T1,typename T2>bool mins(T1& x,const T2&y){if(x>y){x=y;return true;}else return false;}
template<typename T1,typename T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;}
template<typename Tx, typename Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;}
template<typename T>ll suma(const vc<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
template<typename T>ll suma(const vv<T>&a){ll res(0);for(auto&&x:a)res+=suma(x);return res;}
template<typename T>void uni(T& a){sort(rng(a));a.erase(unique(rng(a)),a.end());}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#define dame { puts("No"); return;}
#define ok { puts("Yes"); return;}
#define yn {puts("Yes");}else{puts("No");}
const int MX = 200005;

struct Solver {
  void solve() {
    int n;
    scanf("%d",&n);
    int n2 = n*2;
    vi a(n2);
    cin>>a;
    int x = -1;
    vvi is(n);
    rep(i,n2) is[a[i]-1].pb(i);
    rep(i,n) if (sz(is[i]) != 2) dame;
    vi xs;
    rep(i,n) if (is[i][1] - is[i][0] == n) xs.pb(i);
    vi t(n2);
    rep(i,n2) t[i] = i%n+1;
    if (a == t) ok;
    for (int x : xs) {
      reverse(a.begin()+is[x][0]+1, a.begin()+is[x][1]);
      if (a == t) ok;
      reverse(a.begin()+is[x][0]+1, a.begin()+is[x][1]);
    }
    dame;
  }
};

int main() {
  int ts = 1;
  scanf("%d",&ts);
  rrep(ti,ts) {
    Solver solver;
    solver.solve();
  }
  return 0;
}
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