結果
| 問題 |
No.1707 Simple Range Reverse Problem
|
| コンテスト | |
| ユーザー |
snuke
|
| 提出日時 | 2021-10-27 04:56:03 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 2 ms / 2,000 ms |
| コード長 | 2,939 bytes |
| コンパイル時間 | 1,847 ms |
| コンパイル使用メモリ | 198,924 KB |
| 実行使用メモリ | 7,844 KB |
| 最終ジャッジ日時 | 2025-07-13 03:52:36 |
| 合計ジャッジ時間 | 2,525 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 19 |
コンパイルメッセージ
main.cpp: In function ‘int getInt()’:
main.cpp:24:25: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
24 | int getInt(){int x;scanf("%d",&x);return x;}
| ~~~~~^~~~~~~~~
main.cpp: In function ‘int main()’:
main.cpp:72:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
72 | scanf("%d",&ts);
| ~~~~~^~~~~~~~~~
main.cpp: In member function ‘void Solver::solve()’:
main.cpp:48:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
48 | scanf("%d",&n);
| ~~~~~^~~~~~~~~
ソースコード
#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rrep(i,n) for(int i = 1; i <= (n); ++i)
#define drep(i,n) for(int i = (n)-1; i >= 0; --i)
#define srep(i,s,t) for (int i = s; i < (t); ++i)
#define rng(a) a.begin(),a.end()
#define rrng(a) a.rbegin(),a.rend()
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define snuke srand((unsigned)clock()+(unsigned)time(NULL));
#define newline puts("")
using namespace std;
template<typename T> using vc = vector<T>;
template<typename T> using vv = vc<vc<T>>;
template<typename T> using PQ = priority_queue<T,vc<T>,greater<T>>;
using uint = unsigned; using ull = unsigned long long;
using vi = vc<int>; using vvi = vv<int>;
using ll = long long; using vl = vc<ll>; using vvl = vv<ll>;
using P = pair<int,int>; using vp = vc<P>;
int getInt(){int x;scanf("%d",&x);return x;}
vi pm(int n, int s=0) { vi a(n); iota(rng(a),s); return a;}
template<typename T>istream& operator>>(istream&i,vc<T>&v){rep(j,sz(v))i>>v[j];return i;}
template<typename T>string join(const T&v,const string& d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();}
template<typename T>ostream& operator<<(ostream&o,const vc<T>&v){if(sz(v))o<<join(v," ");return o;}
template<typename T1,typename T2>istream& operator>>(istream&i,pair<T1,T2>&v){return i>>v.fi>>v.se;}
template<typename T1,typename T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.fi<<","<<v.se;}
template<typename T1,typename T2>bool mins(T1& x,const T2&y){if(x>y){x=y;return true;}else return false;}
template<typename T1,typename T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;}
template<typename Tx, typename Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;}
template<typename T>ll suma(const vc<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
template<typename T>ll suma(const vv<T>&a){ll res(0);for(auto&&x:a)res+=suma(x);return res;}
template<typename T>void uni(T& a){sort(rng(a));a.erase(unique(rng(a)),a.end());}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#define dame { puts("No"); return;}
#define ok { puts("Yes"); return;}
#define yn {puts("Yes");}else{puts("No");}
const int MX = 200005;
struct Solver {
void solve() {
int n;
scanf("%d",&n);
int n2 = n*2;
vi a(n2);
cin>>a;
int x = -1;
vvi is(n);
rep(i,n2) is[a[i]-1].pb(i);
rep(i,n) if (sz(is[i]) != 2) dame;
vi xs;
rep(i,n) if (is[i][1] - is[i][0] == n) xs.pb(i);
vi t(n2);
rep(i,n2) t[i] = i%n+1;
if (a == t) ok;
for (int x : xs) {
reverse(a.begin()+is[x][0]+1, a.begin()+is[x][1]);
if (a == t) ok;
reverse(a.begin()+is[x][0]+1, a.begin()+is[x][1]);
}
dame;
}
};
int main() {
int ts = 1;
scanf("%d",&ts);
rrep(ti,ts) {
Solver solver;
solver.solve();
}
return 0;
}
snuke