#710687 (C++17) No.1710 Minimum OR is X

• 問題: No.1710 Minimum OR is X
• ユーザー: snuke
• 提出日時: 2021-10-27 05:24:48
• 言語: C++17 (gcc 12.3.0 + boost 1.83.0)
• 結果: AC
• 実行時間: 100 ms / 2,000 ms
• コード長: 5,271 bytes
• コンパイル時間: 2,188 ms
• コンパイル使用メモリ: 210,888 KB
• 実行使用メモリ: 5,248 KB
• 最終ジャッジ日時: 2024-10-06 21:16:08
• 合計ジャッジ時間: 3,621 ms
• ジャッジサーバーID （参考情報）: judge4 / judge3

入力	結果	実行時間; 実行使用メモリ
testcase_00	AC	2 ms; 5,248 KB
testcase_01	AC	2 ms; 5,248 KB
testcase_02	AC	6 ms; 5,248 KB
testcase_03	AC	2 ms; 5,248 KB
testcase_04	AC	2 ms; 5,248 KB
testcase_05	AC	1 ms; 5,248 KB
testcase_06	AC	1 ms; 5,248 KB
testcase_07	AC	2 ms; 5,248 KB
testcase_08	AC	8 ms; 5,248 KB
testcase_09	AC	11 ms; 5,248 KB
testcase_10	AC	12 ms; 5,248 KB
testcase_11	AC	6 ms; 5,248 KB
testcase_12	AC	25 ms; 5,248 KB
testcase_13	AC	14 ms; 5,248 KB
testcase_14	AC	19 ms; 5,248 KB
testcase_15	AC	4 ms; 5,248 KB
testcase_16	AC	22 ms; 5,248 KB
testcase_17	AC	3 ms; 5,248 KB
testcase_18	AC	62 ms; 5,248 KB
testcase_19	AC	28 ms; 5,248 KB
testcase_20	AC	3 ms; 5,248 KB
testcase_21	AC	81 ms; 5,248 KB
testcase_22	AC	100 ms; 5,248 KB
testcase_23	AC	2 ms; 5,248 KB
testcase_24	AC	2 ms; 5,248 KB
testcase_25	AC	2 ms; 5,248 KB
testcase_26	AC	2 ms; 5,248 KB
testcase_27	AC	2 ms; 5,248 KB
testcase_28	AC	7 ms; 5,248 KB
testcase_29	AC	2 ms; 5,248 KB
testcase_30	AC	2 ms; 5,248 KB
testcase_31	AC	2 ms; 5,248 KB
testcase_32	AC	7 ms; 5,248 KB

ソースコード

#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rrep(i,n) for(int i = 1; i <= (n); ++i)
#define drep(i,n) for(int i = (n)-1; i >= 0; --i)
#define srep(i,s,t) for (int i = s; i < (t); ++i)
#define rng(a) a.begin(),a.end()
#define rrng(a) a.rbegin(),a.rend()
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define snuke srand((unsigned)clock()+(unsigned)time(NULL));
#define newline puts("")
using namespace std;
template<typename T> using vc = vector<T>;
template<typename T> using vv = vc<vc<T>>;
template<typename T> using PQ = priority_queue<T,vc<T>,greater<T>>;
using uint = unsigned; using ull = unsigned long long;
using vi = vc<int>; using vvi = vv<int>;
using ll = long long; using vl = vc<ll>; using vvl = vv<ll>;
using P = pair<int,int>; using vp = vc<P>;
int getInt(){int x;scanf("%d",&x);return x;}
vi pm(int n, int s=0) { vi a(n); iota(rng(a),s); return a;}
template<typename T>istream& operator>>(istream&i,vc<T>&v){rep(j,sz(v))i>>v[j];return i;}
template<typename T>string join(const T&v,const string& d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();}
template<typename T>ostream& operator<<(ostream&o,const vc<T>&v){if(sz(v))o<<join(v," ");return o;}
template<typename T1,typename T2>istream& operator>>(istream&i,pair<T1,T2>&v){return i>>v.fi>>v.se;}
template<typename T1,typename T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.fi<<","<<v.se;}
template<typename T1,typename T2>bool mins(T1& x,const T2&y){if(x>y){x=y;return true;}else return false;}
template<typename T1,typename T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;}
template<typename Tx, typename Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;}
template<typename T>ll suma(const vc<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
template<typename T>ll suma(const vv<T>&a){ll res(0);for(auto&&x:a)res+=suma(x);return res;}
template<typename T>void uni(T& a){sort(rng(a));a.erase(unique(rng(a)),a.end());}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#define dame { puts("-1"); return;}
#define yes { puts("Yes"); return;}
#define no { puts("No"); return;}
#define yn {puts("Yes");}else{puts("No");}
const int MX = 200005;

// Mod int
const uint mod = 998244353;
struct mint {
  uint x;
  mint(): x(0) {}
  mint(ll x):x((x%mod+mod)%mod) {}
  mint operator-() const { return mint(0) - *this;}
  mint operator~() const { return mint(1) / *this;}
  mint& operator+=(const mint& a) { if((x+=a.x)>=mod) x-=mod; return *this;}
  mint& operator-=(const mint& a) { if((x+=mod-a.x)>=mod) x-=mod; return *this;}
  mint& operator*=(const mint& a) { x=(ull)x*a.x%mod; return *this;}
  mint& operator/=(const mint& a) { x=(ull)x*a.pow(mod-2).x%mod; return *this;}
  mint operator+(const mint& a) const { return mint(*this) += a;}
  mint operator-(const mint& a) const { return mint(*this) -= a;}
  mint operator*(const mint& a) const { return mint(*this) *= a;}
  mint operator/(const mint& a) const { return mint(*this) /= a;}
  mint pow(ll t) const {
    if(!t) return 1;
    mint res = pow(t/2);
    res *= res;
    return (t&1)?res*x:res;
  }
  bool operator<(const mint& a) const { return x < a.x;}
  bool operator==(const mint& a) const { return x == a.x;}
  bool operator!=(const mint& a) const { return x != a.x;}
};
mint ex(mint x, ll t) { return x.pow(t);}
istream& operator>>(istream&i,mint&a) {i>>a.x;return i;}
//*
ostream& operator<<(ostream&o,const mint&a) {o<<a.x;return o;}
/*/
ostream& operator<<(ostream&o, const mint&x) {
  int a = x.x, b = 1;
  rep(s,2)rrep(i,1000) {
    int y = ((s?-x:x)*i).x;
    if (abs(a)+b > y+i) a = s?-y:y, b = i;
  }
  o<<a; if (b != 1) o<<'/'<<b; return o;
}//*/
using vm = vector<mint>;
using vvm = vector<vm>;
struct modinv {
  int n; vm d;
  modinv(): n(2), d({0,1}) {}
  mint operator()(int i) { while (n <= i) d.pb(-d[mod%n]*(mod/n)), ++n; return d[i];}
  mint operator[](int i) const { return d[i];}
} invs;
struct modfact {
  int n; vm d;
  modfact(): n(2), d({1,1}) {}
  mint operator()(int i) { while (n <= i) d.pb(d.back()*n), ++n; return d[i];}
  mint operator[](int i) const { return d[i];}
} facs;
struct modfactinv {
  int n; vm d;
  modfactinv(): n(2), d({1,1}) {}
  mint operator()(int i) { while (n <= i) d.pb(d.back()*invs(n)), ++n; return d[i];}
  mint operator[](int i) const { return d[i];}
} ifacs;
mint comb(int a, int b) {
  if (a < b || b < 0) return 0;
  return facs(a)*ifacs(b)*ifacs(a-b);
}
//

struct Solver {
  void solve() {
    int n,m,k;
    scanf("%d%d%d",&n,&m,&k);
    string s;
    cin>>s;
    vm d(n+1);
    rep(i,n+1)srep(j,i-k+1,i+1) d[i] += comb(i,j);
    vm dp(n+1);
    dp[n] = 1;
    rep(i,m) {
      vm p(n+1); swap(dp,p);
      if (s[i] == '1') {
        rep(j,n+1) dp[j] += p[j]*d[j];
      } else {
        mint two = 1;
        srep(j,i+1,m) two *= 2;
        for (int j = n; j >= k; --j) {
          srep(nj,k,j+1) dp[nj] += p[j]*comb(j,nj)*two.pow(j-nj);
        }
      }
    }
    mint ans;
    rep(i,n+1) ans += dp[i];
    cout<<ans<<endl;
  }
};

int main() {
  int ts = 1;
  // scanf("%d",&ts);
  rrep(ti,ts) {
    Solver solver;
    solver.solve();
  }
  return 0;
}