結果

問題 No.618 labo-index
ユーザー koba-e964
提出日時 2021-11-05 11:23:48
言語 Rust
(1.83.0 + proconio)
結果
AC  
実行時間 232 ms / 6,000 ms
コード長 5,558 bytes
コンパイル時間 15,041 ms
コンパイル使用メモリ 379,508 KB
実行使用メモリ 11,264 KB
最終ジャッジ日時 2024-10-15 20:03:24
合計ジャッジ時間 19,493 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 4
other AC * 35
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

use std::cmp::*;
use std::io::{Write, BufWriter};
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
($($r:tt)*) => {
let stdin = std::io::stdin();
let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
let mut next = move || -> String{
bytes.by_ref().map(|r|r.unwrap() as char)
.skip_while(|c|c.is_whitespace())
.take_while(|c|!c.is_whitespace())
.collect()
};
input_inner!{next, $($r)*}
};
}
macro_rules! input_inner {
($next:expr) => {};
($next:expr,) => {};
($next:expr, $var:ident : $t:tt $($r:tt)*) => {
let $var = read_value!($next, $t);
input_inner!{$next $($r)*}
};
}
macro_rules! read_value {
($next:expr, ( $($t:tt),* )) => { ($(read_value!($next, $t)),*) };
($next:expr, [ $t:tt ; $len:expr ]) => {
(0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
};
($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));
}
/**
* Segment Tree. This data structure is useful for fast folding on intervals of an array
* whose elements are elements of monoid I. Note that constructing this tree requires the identity
* element of I and the operation of I.
* Verified by: yukicoder No. 259 (http://yukicoder.me/submissions/100581)
* AGC015-E (http://agc015.contest.atcoder.jp/submissions/1461001)
* yukicoder No. 833 (https://yukicoder.me/submissions/703521)
*/
struct SegTree<I, BiOp> {
n: usize,
dat: Vec<I>,
op: BiOp,
e: I,
}
impl<I, BiOp> SegTree<I, BiOp>
where BiOp: Fn(I, I) -> I,
I: Copy {
pub fn new(n_: usize, op: BiOp, e: I) -> Self {
let mut n = 1;
while n < n_ { n *= 2; } // n is a power of 2
SegTree {n: n, dat: vec![e; 2 * n - 1], op: op, e: e}
}
/* ary[k] <- v */
pub fn update(&mut self, idx: usize, v: I) {
let mut k = idx + self.n - 1;
self.dat[k] = v;
while k > 0 {
k = (k - 1) / 2;
self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]);
}
}
/* [a, b) (note: half-inclusive)
* http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ */
#[allow(unused)]
pub fn query(&self, mut a: usize, mut b: usize) -> I {
let mut left = self.e;
let mut right = self.e;
a += self.n - 1;
b += self.n - 1;
while a < b {
if (a & 1) == 0 {
left = (self.op)(left, self.dat[a]);
}
if (b & 1) == 0 {
right = (self.op)(self.dat[b - 1], right);
}
a = a / 2;
b = (b - 1) / 2;
}
(self.op)(left, right)
}
}
// Depends on: datastr/SegTree.rs
impl<I, BiOp> SegTree<I, BiOp>
where BiOp: Fn(I, I) -> I,
I: Copy {
// Port from https://github.com/atcoder/ac-library/blob/master/atcoder/segtree.hpp
#[allow(unused)]
fn max_right<F: Fn(I) -> bool>(
&self, mut l: usize, f: &F,
) -> usize {
assert!(f(self.e));
if l == self.n {
return self.n;
}
l += self.n - 1;
let mut sm = self.e;
loop {
while l % 2 == 1 {
l = (l - 1) / 2;
}
if !f((self.op)(sm, self.dat[l])) {
while l < self.n - 1 {
l = 2 * l + 1;
let val = (self.op)(sm, self.dat[l]);
if f(val) {
sm = val;
l += 1;
}
}
return l + 1 - self.n;
}
sm = (self.op)(sm, self.dat[l]);
l += 1;
if (l + 1).is_power_of_two() { break; }
}
self.n
}
}
fn main() {
let out = std::io::stdout();
let mut out = BufWriter::new(out.lock());
macro_rules! puts {($($format:tt)*) => (let _ = write!(out,$($format)*););}
input! {
q: usize,
tx: [(i32, i64); q],
}
let mut coo = vec![];
let mut bias = 0;
for &(t, x) in &tx {
if t == 1 {
coo.push(x - bias);
}
if t == 3 {
bias += x;
}
}
coo.sort_unstable(); coo.dedup();
let m = coo.len();
const INF: i64 = 1 << 50;
let mut st = SegTree::new(m, |(a, s, x), (b, t, y)| if x < y {
(a + b + s, t, y)
} else {
(a + b + t, s, x)
}, (0, 0, -INF));
for i in 0..m {
st.update(i, (0, 0, coo[i]));
}
bias = 0;
let mut dat = vec![];
for &(t, x) in &tx {
if t == 1 {
let idx = coo.binary_search(&(x - bias)).unwrap();
dat.push(idx);
let (a, s, b) = st.query(idx, idx + 1);
st.update(idx, (a, s + 1, b));
} else if t == 2 {
let idx = dat[x as usize - 1];
let (a, s, b) = st.query(idx, idx + 1);
st.update(idx, (a, s - 1, b));
} else {
bias += x;
}
let whole = {
let (a, b, _) = st.query(0, m);
a + b
};
let idx = st.max_right(0, &|(a, _, x)| whole - a >= x + bias);
let (a, _, b) = st.query(0, idx);
let mut ans = min(whole - a, b + bias);
if idx + 1 <= m {
let (a, _, b) = st.query(0, idx + 1);
ans = max(ans, min(whole - a, b + bias));
}
puts!("{}\n", max(0, ans));
eprintln!();
}
}
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