結果

問題 No.1741 Arrays and XOR Procedure
ユーザー miscalc
提出日時 2021-11-12 22:33:39
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,253 bytes
コンパイル時間 2,253 ms
コンパイル使用メモリ 203,944 KB
最終ジャッジ日時 2025-01-25 17:10:46
ジャッジサーバーID
(参考情報)
judge2 / judge4
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ファイルパターン 結果
sample AC * 3
other AC * 31 WA * 10
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ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#include <atcoder/modint>
using namespace std;
using namespace atcoder;
using mint = modint998244353;
//using mint = modint1000000007;
using ll = long long;
using ld = long double;
using pll = pair<ll, ll>;
using tlll = tuple<ll, ll, ll>;
constexpr ll INF = 1LL << 60;
template<class T> bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;}
template<class T> bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;}
ll safemod(ll A, ll M) {return (A % M + M) % M;}
ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;}
ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);}
#define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false)
class mintcombination
{
public:
vector<mint> fac, finv, inv;
mintcombination(ll M)
{
fac.resize(M + 1);
finv.resize(M + 1);
inv.resize(M + 1);
fac.at(0) = 1, finv.at(0) = 1;
fac.at(1) = 1, finv.at(1) = 1, inv.at(1) = 1;
for (ll i = 2; i <= M; i++)
{
fac.at(i) = fac.at(i - 1) * i;
inv.at(i) = mint::mod() - inv.at(mint::mod() % i) * (mint::mod() / i);
finv.at(i) = finv.at(i - 1) * inv.at(i);
}
}
mint P(ll N, ll K)
{
if (N < K) return 0;
if (N < 0 || K < 0) return 0;
return fac.at(N) * finv.at(N - K);
}
mint C(ll N, ll K)
{
if (N < K) return 0;
if (N < 0 || K < 0) return 0;
return fac.at(N) * finv.at(K) * finv.at(N - K);
}
mint H(ll N, ll K)
{
return C(N + K - 1, K);
}
};
int main()
{
ll N;
cin >> N;
vector<ll> B(N);
for (ll i = 0; i < N; i++)
{
cin >> B.at(i);
}
vector<ll> C;
if (N % 2 == 1)
C = {B.front(), B.back()};
else
{
C.resize(N);
for (ll i = 0; i < N; i++)
{
C.at(i) = B.at(i);
}
}
ll X = 0;
for (auto c : C)
{
if (c != -1)
X ^= c;
}
ll M = count(B.begin(), B.end(), -1);
ll K = count(C.begin(), C.end(), -1);
mintcombination com(N);
if (K == 0)
{
cout << (X == 1 ? 1 : 0) << endl;
}
else
{
mint ans = 0;
for (ll i = X; i <= K; i += 2)
{
ans += com.C(K, i);
}
ans *= mint(2).pow(M - K);
cout << ans.val() << endl;
}
}
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