結果

問題 No.1739 Princess vs. Dragoness (& AoE)
ユーザー 👑 obakyan
提出日時 2021-11-13 20:39:39
言語 Lua
(LuaJit 2.1.1734355927)
結果
TLE  
(最新)
AC  
(最初)
実行時間 -
コード長 2,056 bytes
コンパイル時間 437 ms
コンパイル使用メモリ 5,504 KB
実行使用メモリ 17,312 KB
最終ジャッジ日時 2024-11-27 22:02:30
合計ジャッジ時間 63,522 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 32 TLE * 8
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

local mfl, mce = math.floor, math.ceil
local mmi, mma = math.min, math.max
local bls, brs = bit.lshift, bit.rshift
local Heapq = {}
Heapq.create = function(self, lt)
  self.lt = lt
  self.cnt = 0
  self.t = {}
end
Heapq.push = function(self, v)
  local hqlt = self.lt
  local hqt = self.t
  local c = self.cnt + 1
  self.cnt = c
  hqt[c] = v
  while 1 < c do
    local p = brs(c, 1)
    if hqlt(hqt[c], hqt[p]) then
      hqt[c], hqt[p] = hqt[p], hqt[c]
      c = p
    else
      break
    end
  end
end
Heapq.pop = function(self)
  local hqlt = self.lt
  local hqt = self.t
  local ret = hqt[1]
  local c = self.cnt
  hqt[1] = hqt[c]
  c = c - 1
  self.cnt = c
  local p = 1
  while true do
    local d1, d2 = p * 2, p * 2 + 1
    if c < d1 then break
    elseif c < d2 then
      if hqlt(hqt[d1], hqt[p]) then
        hqt[d1], hqt[p] = hqt[p], hqt[d1]
      end
      break
    else
      if hqlt(hqt[d1], hqt[d2]) then
        if hqlt(hqt[d1], hqt[p]) then
          hqt[d1], hqt[p] = hqt[p], hqt[d1]
          p = d1
        else break
        end
      else
        if hqlt(hqt[d2], hqt[p]) then
          hqt[d2], hqt[p] = hqt[p], hqt[d2]
          p = d2
        else break
        end
      end
    end
  end
  return ret
end
Heapq.new = function(lt)
  local obj = {}
  setmetatable(obj, {__index = Heapq})
  obj:create(lt)
  return obj
end
local n = io.read("*n")
local a, b = io.read("*n", "*n")
local x, y = io.read("*n", "*n")
local hs = {}
for i = 1, n do
  table.insert(hs, io.read("*n"))
end
local function solve(z)
  local hq = Heapq.new(function(c, d) return c > d end)
  for i = 1, n do
    local h = hs[i]
    hq:push(h)
  end
  for i = 1, a do
    local v = hq:pop()
    if v <= z then
      hq:push(v) break
    end
    v = mma(z, v - x)
    hq:push(v)
  end
  local tot = 0
  for i = 1, n do
    tot = tot + mma(0, hq:pop() - z)
  end
  return tot <= b * y
end
local min, max = -1, 1000000007
while 1 < max - min do
  local mid = mfl((min + max) / 2)
  if solve(mid) then
    max = mid
  else
    min = mid
  end
end
print(max)
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0