結果
問題 |
No.1640 簡単な色塗り
|
ユーザー |
👑 |
提出日時 | 2021-11-23 22:56:22 |
言語 | Lua (LuaJit 2.1.1734355927) |
結果 |
AC
|
実行時間 | 309 ms / 2,000 ms |
コード長 | 2,189 bytes |
コンパイル時間 | 142 ms |
コンパイル使用メモリ | 5,120 KB |
実行使用メモリ | 55,168 KB |
最終ジャッジ日時 | 2024-06-25 20:43:25 |
合計ジャッジ時間 | 18,461 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 53 |
ソースコード
local n = io.read("*n") local parent = {} for i = 1, n do parent[i] = i end local function uf_findroot(idx) local idx_update = idx while parent[idx] ~= idx do idx = parent[idx] end while parent[idx_update] ~= idx do parent[idx_update], idx_update = idx, parent[idx_update] end return idx end local as, bs = {}, {} for i = 1, n do local a, b = io.read("*n", "*n") as[i], bs[i] = a, b local ra, rb = uf_findroot(a), uf_findroot(b) parent[b], parent[rb] = ra, ra end local group = {} local g_e = {} local edge = {} local edgecnt = {} for i = 1, n do group[i] = {} g_e[i] = {} edge[i] = {} edgecnt[i] = 0 end for i = 1, n do local r = uf_findroot(i) table.insert(group[r], i) end for i = 1, n do local a, b = as[i], bs[i] local r = uf_findroot(a) table.insert(g_e[r], i) edge[a][i], edge[b][i] = true, true edgecnt[a] = edgecnt[a] + 1 if a ~= b then edgecnt[b] = edgecnt[b] + 1 end end for i = 1, n do if #group[i] ~= #g_e[i] then print("No") os.exit() end end print("Yes") local ans = {} for i = 1, n do ans[i] = 0 end local function solve(gi) local tasks = {} local done = 0 for i = 1, #group[gi] do local src = group[gi][i] if edgecnt[src] == 1 then table.insert(tasks, src) end end while done < #tasks do done = done + 1 local src = tasks[done] local ei = next(edge[src]) ans[ei] = src local dst = as[ei] == src and bs[ei] or as[ei] edge[dst][ei] = nil edgecnt[dst] = edgecnt[dst] - 1 if edgecnt[dst] == 1 then table.insert(tasks, dst) end end if done == #group[gi] then return end local ring_spos = false for i = 1, #group[gi] do local src = group[gi][i] if edgecnt[src] == 2 then ring_spos = src table.insert(tasks, src) break end end while done < #tasks do done = done + 1 local src = tasks[done] local ei = next(edge[src]) ans[ei] = src local dst = as[ei] == src and bs[ei] or as[ei] edge[dst][ei] = nil edgecnt[dst] = edgecnt[dst] - 1 if edgecnt[dst] == 1 then table.insert(tasks, dst) end end end for i = 1, n do solve(i) end print(table.concat(ans, "\n"))