結果
| 問題 | No.1768 The frog in the well knows the great ocean. |
| コンテスト | |
| ユーザー |
fuppy_kyopro
|
| 提出日時 | 2021-11-26 22:53:23 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.89.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 5,146 bytes |
| 記録 | |
| コンパイル時間 | 2,494 ms |
| コンパイル使用メモリ | 218,292 KB |
| 最終ジャッジ日時 | 2025-01-26 01:39:59 |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 25 WA * 2 |
ソースコード
/*
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
//*/
#include <bits/stdc++.h>
// #include <atcoder/all>
// #include <atcoder/maxflow>
using namespace std;
// using namespace atcoder;
#define DEBUG(x) cerr << #x << ": " << x << endl;
#define DEBUG_VEC(v) \
cerr << #v << ":"; \
for (int iiiiiiii = 0; iiiiiiii < v.size(); iiiiiiii++) \
cerr << " " << v[iiiiiiii]; \
cerr << endl;
#define DEBUG_MAT(v) \
cerr << #v << endl; \
for (int iv = 0; iv < v.size(); iv++) { \
for (int jv = 0; jv < v[iv].size(); jv++) { \
cerr << v[iv][jv] << " "; \
} \
cerr << endl; \
}
typedef long long ll;
// #define int ll
#define vi vector<int>
#define vl vector<ll>
#define vii vector<vector<int>>
#define vll vector<vector<ll>>
#define vs vector<string>
#define pii pair<int, int>
#define pis pair<int, string>
#define psi pair<string, int>
#define pll pair<ll, ll>
template <class S, class T>
pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t) {
return pair<S, T>(s.first + t.first, s.second + t.second);
}
template <class S, class T>
pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first - t.first, s.second - t.second); }
template <class S, class T>
ostream &operator<<(ostream &os, pair<S, T> p) {
os << "(" << p.first << ", " << p.second << ")";
return os;
}
#define X first
#define Y second
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define rep1(i, n) for (int i = 1; i <= (int)(n); i++)
#define rrep(i, n) for (int i = (int)(n)-1; i >= 0; i--)
#define rrep1(i, n) for (int i = (int)(n); i > 0; i--)
#define REP(i, a, b) for (int i = a; i < b; i++)
#define in(x, a, b) (a <= x && x < b)
#define all(c) c.begin(), c.end()
void YES(bool t = true) {
cout << (t ? "YES" : "NO") << endl;
}
void Yes(bool t = true) { cout << (t ? "Yes" : "No") << endl; }
void yes(bool t = true) { cout << (t ? "yes" : "no") << endl; }
void NO(bool t = true) { cout << (t ? "NO" : "YES") << endl; }
void No(bool t = true) { cout << (t ? "No" : "Yes") << endl; }
void no(bool t = true) { cout << (t ? "no" : "yes") << endl; }
template <class T>
bool chmax(T &a, const T &b) {
if (a < b) {
a = b;
return 1;
}
return 0;
}
template <class T>
bool chmin(T &a, const T &b) {
if (a > b) {
a = b;
return 1;
}
return 0;
}
#define UNIQUE(v) v.erase(std::unique(v.begin(), v.end()), v.end());
const ll inf = 1000000001;
const ll INF = (ll)1e18 + 1;
const long double pi = 3.1415926535897932384626433832795028841971L;
int popcount(ll t) { return __builtin_popcountll(t); }
// int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};
// int dx2[8] = { 1,1,0,-1,-1,-1,0,1 }, dy2[8] = { 0,1,1,1,0,-1,-1,-1 };
vi dx = {0, 1, 0, -1}, dy = {-1, 0, 1, 0};
// vi dx2 = { 1,1,0,-1,-1,-1,0,1 }, dy2 = { 0,1,1,1,0,-1,-1,-1 };
struct Setup_io {
Setup_io() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
cout << fixed << setprecision(25);
}
} setup_io;
// const ll MOD = 1000000007;
const ll MOD = 998244353;
// #define mp make_pair
//#define endl '\n'
void solve() {
int n;
cin >> n;
vi a(n);
rep(i, n) cin >> a[i];
vi b(n);
rep(i, n) cin >> b[i];
rep(i, n) {
if (a[i] > b[i]) {
No();
return;
}
}
int l = 0;
using P = pair<int, pii>;
map<int, vector<pii>> mp;
while (l < n) {
int r = l;
while (r < n && b[r] == b[l]) {
r++;
}
mp[b[l]].emplace_back(l, r);
l = r;
}
map<int, vi> idxs;
rep(i, n) {
idxs[a[i]].push_back(i);
}
set<int> used;
for (auto itr = mp.begin(); itr != mp.end(); itr++) {
int x = itr->first;
for (auto [l, r] : itr->second) {
auto itrr = used.lower_bound(r);
int r2;
if (itrr == used.end())
r2 = n;
else
r2 = *itrr;
itrr = used.lower_bound(l);
int l2;
if (itrr == used.begin())
l2 = -1;
else {
itrr--;
l2 = *itrr;
}
bool flag = false;
auto itrrr = lower_bound(all(idxs[x]), l2 + 1);
if (itrrr != idxs[x].end() && *itrrr < r2) {
flag = true;
}
// for (int i = l2 + 1; i < r2; i++) {
// if (a[i] == x) {
// flag = true;
// }
// }
if (!flag) {
No();
return;
}
}
for (auto [l, r] : itr->second) {
REP(i, l, r)
used.insert(i);
}
}
Yes();
}
signed main() {
int t;
cin >> t;
while (t--) {
solve();
}
}
fuppy_kyopro