結果

問題 No.1768 The frog in the well knows the great ocean.
ユーザー 👑 hitonanodehitonanode
提出日時 2021-11-26 22:56:28
言語 C++23(draft)
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 186 ms / 3,000 ms
コード長 7,321 bytes
コンパイル時間 1,996 ms
コンパイル使用メモリ 187,488 KB
実行使用メモリ 21,132 KB
最終ジャッジ日時 2023-09-12 05:50:23
合計ジャッジ時間 6,286 ms
ジャッジサーバーID
(参考情報)
judge15 / judge14
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,380 KB
testcase_01 AC 6 ms
4,380 KB
testcase_02 AC 6 ms
4,384 KB
testcase_03 AC 6 ms
4,380 KB
testcase_04 AC 6 ms
4,384 KB
testcase_05 AC 6 ms
4,380 KB
testcase_06 AC 138 ms
7,596 KB
testcase_07 AC 147 ms
10,224 KB
testcase_08 AC 133 ms
8,788 KB
testcase_09 AC 135 ms
7,400 KB
testcase_10 AC 140 ms
10,264 KB
testcase_11 AC 161 ms
10,776 KB
testcase_12 AC 143 ms
10,900 KB
testcase_13 AC 132 ms
10,680 KB
testcase_14 AC 139 ms
10,716 KB
testcase_15 AC 152 ms
10,636 KB
testcase_16 AC 186 ms
17,560 KB
testcase_17 AC 180 ms
17,552 KB
testcase_18 AC 178 ms
17,496 KB
testcase_19 AC 154 ms
17,560 KB
testcase_20 AC 181 ms
17,496 KB
testcase_21 AC 2 ms
4,376 KB
testcase_22 AC 2 ms
4,380 KB
testcase_23 AC 2 ms
4,380 KB
testcase_24 AC 49 ms
4,384 KB
testcase_25 AC 185 ms
21,132 KB
testcase_26 AC 132 ms
20,868 KB
testcase_27 AC 1 ms
4,380 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <deque>
#include <forward_list>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iostream>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <type_traits>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template <typename T, typename V>
void ndarray(vector<T>& vec, const V& val, int len) { vec.assign(len, val); }
template <typename T, typename V, typename... Args> void ndarray(vector<T>& vec, const V& val, int len, Args... args) { vec.resize(len), for_each(begin(vec), end(vec), [&](T& v) { ndarray(v, val, args...); }); }
template <typename T> bool chmax(T &m, const T q) { return m < q ? (m = q, true) : false; }
template <typename T> bool chmin(T &m, const T q) { return m > q ? (m = q, true) : false; }
int floor_lg(long long x) { return x <= 0 ? -1 : 63 - __builtin_clzll(x); }
template <typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template <typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template <typename T> vector<T> sort_unique(vector<T> vec) { sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end()); return vec; }
template <typename T> int arglb(const std::vector<T> &v, const T &x) { return std::distance(v.begin(), std::lower_bound(v.begin(), v.end(), x)); }
template <typename T> int argub(const std::vector<T> &v, const T &x) { return std::distance(v.begin(), std::upper_bound(v.begin(), v.end(), x)); }
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T, size_t sz> ostream &operator<<(ostream &os, const array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }
#if __cplusplus >= 201703L
template <typename... T> istream &operator>>(istream &is, tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }
template <typename... T> ostream &operator<<(ostream &os, const tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }
#endif
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T, typename TH> ostream &operator<<(ostream &os, const unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
template <typename TK, typename TV, typename TH> ostream &operator<<(ostream &os, const unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
#ifdef HITONANODE_LOCAL
const string COLOR_RESET = "\033[0m", BRIGHT_GREEN = "\033[1;32m", BRIGHT_RED = "\033[1;31m", BRIGHT_CYAN = "\033[1;36m", NORMAL_CROSSED = "\033[0;9;37m", RED_BACKGROUND = "\033[1;41m", NORMAL_FAINT = "\033[0;2m";
#define dbg(x) cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << endl
#define dbgif(cond, x) ((cond) ? cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << endl : cerr)
#else
#define dbg(x) (x)
#define dbgif(cond, x) 0
#endif

#include <atcoder/lazysegtree>
int op(int l, int r) { return max(l, r); }
int e() { return -1; }
int mapping(pint x, int v) {
    if (x.first) return x.second;
    return v;
}
pint composition(pint fnew, pint gold) {
    if (fnew.first) return fnew;
    return gold;
}
pint id() { return {false, 0}; }

// 0-indexed BIT (binary indexed tree / Fenwick tree) (i : [0, len))
template <class T> struct BIT {
    int n;
    std::vector<T> data;
    BIT(int len = 0) : n(len), data(len) {}
    void reset() { std::fill(data.begin(), data.end(), T(0)); }
    void add(int pos, T v) { // a[pos] += v
        pos++;
        while (pos > 0 and pos <= n) data[pos - 1] += v, pos += pos & -pos;
    }
    T sum(int k) const { // a[0] + ... + a[k - 1]
        T res = 0;
        while (k > 0) res += data[k - 1], k -= k & -k;
        return res;
    }

    T sum(int l, int r) const { return sum(r) - sum(l); } // a[l] + ... + a[r - 1]

    template <class OStream> friend OStream &operator<<(OStream &os, const BIT &bit) {
        T prv = 0;
        os << '[';
        for (int i = 1; i <= bit.n; i++) {
            T now = bit.sum(i);
            os << now - prv << ',', prv = now;
        }
        return os << ']';
    }
};

bool solve() {
    int N;
    cin >> N;
    vector<int> A(N), B(N);
    cin >> A >> B;
    atcoder::lazy_segtree<int, op, e, pint, mapping, composition, id> tree(A);
    map<int, vector<int>> mp;
    REP(i, N) mp[B[i]].push_back(i);

    BIT<int> bit(N);
    for (auto [b, is] : mp) {
        for (auto i : is) {
            if (A[i] > B[i]) return false;
            int r = tree.max_right(i, [&](int x) { return x < B[i]; });
            int l = tree.min_left(i, [&](int x) { return x < B[i]; });
            bool found = false;
            if (r < N and A[r] == B[i] and bit.sum(i, r) == 0) found = true;
            if (l and A[l - 1] == B[i] and bit.sum(l - 1, i) == 0) found = true;
            if (!found) return false;
        }
        for (auto i : is) bit.add(i, 1);
    }
    return true;
}

int main() {
    int T;
    cin >> T;
    while (T--) cout << (solve() ? "Yes" : "No") << '\n';
}
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