結果
問題 | No.1768 The frog in the well knows the great ocean. |
ユーザー | TKTYI |
提出日時 | 2021-11-26 23:59:14 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,061 bytes |
コンパイル時間 | 3,764 ms |
コンパイル使用メモリ | 249,928 KB |
実行使用メモリ | 48,836 KB |
最終ジャッジ日時 | 2024-06-29 19:09:49 |
合計ジャッジ時間 | 8,450 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 8 ms
18,960 KB |
testcase_01 | WA | - |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | AC | 211 ms
34,604 KB |
testcase_12 | WA | - |
testcase_13 | AC | 192 ms
34,568 KB |
testcase_14 | AC | 183 ms
34,652 KB |
testcase_15 | AC | 186 ms
34,600 KB |
testcase_16 | AC | 231 ms
48,836 KB |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | AC | 202 ms
48,588 KB |
testcase_20 | AC | 205 ms
48,792 KB |
testcase_21 | AC | 8 ms
18,944 KB |
testcase_22 | AC | 8 ms
18,844 KB |
testcase_23 | WA | - |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | AC | 137 ms
41,580 KB |
testcase_27 | WA | - |
コンパイルメッセージ
main.cpp: In function 'int main()': main.cpp:44:23: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions] 44 | if(r==u)for(auto[key,val]:M[v])M[u][key]+=val; | ^ main.cpp:45:20: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions] 45 | else for(auto[key,val]:M[u])M[v][key]+=val; | ^ main.cpp:52:25: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions] 52 | if(r==u)for(auto[key,val]:M[v])M[u][key]+=val; | ^ main.cpp:53:22: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions] 53 | else for(auto[key,val]:M[u])M[v][key]+=val; | ^ main.cpp:57:25: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions] 57 | if(r==u)for(auto[key,val]:M[v])M[u][key]+=val; | ^ main.cpp:58:22: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions] 58 | else for(auto[key,val]:M[u])M[v][key]+=val; | ^
ソースコード
#include <bits/stdc++.h> #include <atcoder/all> using namespace std; using namespace atcoder; typedef long long int ll; typedef long double ld; #define FOR(i,l,r) for(int i=l;i<r;i++) #define REP(i,n) FOR(i,0,n) #define RFOR(i,l,r) for(ll i=r-1;i>=l;i--) #define RREP(i,n) RFOR(i,0,n) #define ALL(x) x.begin(),x.end() #define P pair<ll,ll> #define F first #define S second #define BS(A,x) binary_search(ALL(A),x) #define LB(A,x) (ll)(lower_bound(ALL(A),x)-A.begin()) #define UB(A,x) (ll)(upper_bound(ALL(A),x)-A.begin()) #define COU(A,x) (UB(A,x)-LB(A,x)) template<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>; //using mint=modint1000000007; using mint=modint998244353; void chmax(ll&a,ll b){a=max(a,b);} void chmin(ll&a,ll b){a=min(a,b);} signed main(){ int T,N;cin>>T; vector<int>A(2e5),B(2e5); set<int>S; vector<map<int,int>>M(2e5); vector<vector<int>>X(2e5+1); while(T--){ scanf("%d",&N); REP(i,N)scanf("%d",&A[i]); REP(i,N)scanf("%d",&B[i]); S.clear();REP(i,N)S.insert(A[i]); bool ans=1; REP(i,N){ ans=ans&&S.count(B[i])&&A[i]<=B[i]; M[i].clear();M[i][A[i]]++;X[i+1].clear(); if(i==0||B[i-1]!=B[i])X[B[i]].emplace_back(i); } dsu D(N); REP(i,N-1)if(B[i]==B[i+1]){ int u=D.leader(i),v=D.leader(i+1),r=D.merge(u,v); if(r==u)for(auto[key,val]:M[v])M[u][key]+=val; else for(auto[key,val]:M[u])M[v][key]+=val; } RREP(v,N+1)for(auto i:X[v]){ int l=i,r=N-1; while(l!=r){int m=(l+r+1)/2;if(D.same(i,m))l=m;else r=m-1;} if(i&&B[i-1]>B[i]){ int u=D.leader(i-1),v=D.leader(i),r=D.merge(u,v); if(r==u)for(auto[key,val]:M[v])M[u][key]+=val; else for(auto[key,val]:M[u])M[v][key]+=val; } if(l<N-1&&B[l+1]>B[l]){ int u=D.leader(l+1),v=D.leader(l),r=D.merge(u,v); if(r==u)for(auto[key,val]:M[v])M[u][key]+=val; else for(auto[key,val]:M[u])M[v][key]+=val; } ans=ans&&M[D.leader(i)][v]; } if(ans)printf("Yes\n"); else printf("No\n"); } return 0; }