結果

問題 No.1802 Range Score Query for Bracket Sequence
ユーザー noya2
提出日時 2022-01-07 22:55:34
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
RE  
(最新)
AC  
(最初)
実行時間 -
コード長 12,279 bytes
コンパイル時間 4,388 ms
コンパイル使用メモリ 274,852 KB
最終ジャッジ日時 2025-01-27 09:43:14
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 1
other AC * 23 RE * 1
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
/*
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <boost/multiprecision/cpp_int.hpp>
namespace mp = boost::multiprecision;
using bint = mp::cpp_int;
*/
#include <atcoder/all>
#include <iostream>
#include <queue>
#include <stack>
#include <vector>
#include <string>
#include <set>
#include <map>
#include <random>
#include <bitset>
#define rep(i,n) for (int i = 0; i < int(n); ++i)
#define repp(i,n,m) for (int i = m; i < int(n); ++i)
#define repb(i,n) for (int i = int(n)-1; i >= 0; --i)
#define fi first
#define se second
#define endl "\n"
using namespace std;
using namespace atcoder;
using ll = long long;
using ld = long double;
using P = pair<int, int>;
using PL = pair<long long, long long>;
using Pxy = pair<long double, long double>;
using pil = pair<int,ll>;
using pli = pair<ll,int>;
const int INF = 1001001007;
const long long mod1 = 1000000007LL;
const long long mod2 = 998244353LL;
const ll inf = 2e18;
const ld pi = 3.14159265358979323;
const ld eps = 1e-7;
const char _ = ' ';
template<class T>istream &operator>>(istream &is,vector<T> &v){for(auto &e:v)is>>e;return is;}
template<class T>ostream &operator<<(ostream &os,const vector<T> &v){if(v.size()!=0){rep(i,v.size())os<<v[i]<<(i+1==v.size()?"":" ");}return os;}
template<class T>istream &operator>>(istream &is,vector<vector<T>> &v){for(auto &e:v)is>>e;return is;}
template<class T>ostream &operator<<(ostream &os,const vector<vector<T>> &v){if(v.size()!=0){for(auto &e:v)os<<e;}return os;}
template<typename T>bool range(T a,T b,T x){return (a<=x&&x<b);}
template<typename T>bool rrange(T a,T b,T c,T d,T x,T y){return (range(a,c,x)&&range(b,d,y));}
template<typename T>void rev(vector<T> &v){reverse(v.begin(),v.end());}
void revs(string &s) {reverse(s.begin(),s.end());}
template<typename T>void sor(vector<T> &v, int f=0){sort(v.begin(),v.end());if(f!=0) rev(v);}
template<typename T>bool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;}
template<typename T>bool chmax(T &a,const T &b){if(a<b){a=b;return true;}return false;}
template<typename T>void eru(vector<T> &v){sor(v);v.erase(unique(v.begin(),v.end()),v.end());}
template<typename T>T cel(T a,T b){if(a%b==0)return a/b;return a/b +1;}
void o(){cout<<"!?"<<endl;}
template<typename T>void o(T a){cout<<a<<endl;}
template<typename T,typename U>void o2(T a,U b){cout<<a<<_<<b<<endl;}
template<typename T,typename U>void o2(pair<T,U> a){o2(a.first,a.second);}
template<typename T,typename U,typename V>void o3(T a,U b,V c){cout<<a<<_<<b<<_<<c<<endl;}
template<typename T>void mout(T a){cout<<a.val()<<endl;}
void yes(){cout << "Yes" << endl;}
void no (){cout << "No" << endl;}
void yn (bool t){if(t)yes();else no();}
template<typename T>void dame(bool t, T s){if(!t){cout << s << endl;exit(0);}}
void fast_io(){cin.tie(0); ios::sync_with_stdio(0); cout<<fixed<<setprecision(20);}
vector<int> dx = {0,1,0,-1};
vector<int> dy = {1,0,-1,0};
const string ALP = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const string alp = "abcdefghijklmnopqrstuvwxyz";
const string num = "0123456789";
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
ll mpow(ll x,ll n,ll m){if(n==0)return 1LL;x%=m;ll a=mpow(x,n/2,m);a=a*a%m;return (n&1)?a*x%m:a;}
ll tentou(vector<ll> ar){
int n = ar.size();
set<ll> st;
rep(i,n) st.insert(ar[i]);
map<ll,int> mp;
int ind = 0;
for (ll x : st){
mp[x] = ind;
ind++;
}
fenwick_tree<ll> fw(ind);
ll ans = 0;
rep(i,n){
int a = mp[ar[i]];
ans += i - fw.sum(0,a+1);
fw.add(a,1);
}
return ans;
}
struct edge{
int from, to, idx;
long long cost;
edge(int _from = -1, int _to = -1, long long _cost = 1LL, int _idx = -1) : from(_from), to(_to), cost(_cost), idx(_idx) {}
};
struct vertex{
vector<edge> adj;
};
struct Graph{
int n, m;
vector<vertex> ar;
void add_edge(int from, int to, long long cost = 1LL){
assert(0 <= from && from < n);
assert(0 <= to && to < n);
ar[from].adj.emplace_back(edge(from,to,cost));
}
void add_dual_edge(int from, int to, long long cost = 1LL){
assert(0 <= from && from < n);
assert(0 <= to && to < n);
ar[from].adj.emplace_back(edge(from,to,cost));
ar[to].adj.emplace_back(edge(to,from,cost));
}
Graph(int _n) : n(_n) , ar(n) {}
vector<long long> dijkstra(int s){
using pli = pair<long long, int>;
priority_queue<pli, vector<pli>, greater<pli>> pque;
vector<long long> dist(n,inf);
dist[s] = 0LL;
pque.push(pli(0,s));
while (!pque.empty()){
pli p = pque.top(); pque.pop();
if (dist[p.second] < p.first) continue;
for (edge x : ar[p.second].adj){
if (dist[x.to] > p.first + x.cost){
dist[x.to] = p.first + x.cost;
pque.push(pli(dist[x.to],x.to));
}
}
}
return dist;
}
vector<long long> bfs01(int s){
deque<int> que;
vector<long long> dist(n,inf);
dist[s] = 0LL;
que.push_front(s);
while (!que.empty()){
int p = que.front(); que.pop_front();
for (edge x : ar[p].adj){
if (dist[x.to] > dist[p] + x.cost){
if (x.cost == 0LL) que.push_front(x.to);
else que.push_back(x.to);
}
}
}
return dist;
}
vector<int> dfs(int s){
vector<int> ans;
vector<int> vis(n,0);
_dfs(s,ans,vis);
return ans;
}
private:
void _dfs(int s, vector<int> &ans, vector<int> &vis){
vis[s]++;
for (edge x : ar[s].adj){
if (vis[x.to] == 0){
_dfs(x.to,ans,vis);
}
}
ans.emplace_back(s);
}
};
struct Tree{
Tree(int _n, int _root = 0) : n(_n), root(_root) {
assert(0 <= root && root < n);
initialize();
}
void add_edge(int from, int to, long long cost = 1LL, int _idx = -1){
assert(0 <= from && from < n);
assert(0 <= to && to < n);
if (_idx == -1) _idx = m, m++;
assert(0 <= _idx && _idx < n-1);
assert(edge_idx_cnt[_idx] == 0);
edge_idx_cnt[_idx]++;
vs[from].adj.emplace_back(edge(from,to,cost,_idx));
es[_idx] = edge(from,to,cost,_idx);
}
void add_dual_edge(int from, int to, long long cost = 1LL, int _idx = -1){
assert(0 <= from && from < n);
assert(0 <= to && to < n);
if (_idx == -1) _idx = m, m++;
assert(0 <= _idx && _idx < n-1);
assert(edge_idx_cnt[_idx] == 0);
edge_idx_cnt[_idx]++;
vs[from].adj.emplace_back(edge(from,to,cost,_idx));
vs[to].adj.emplace_back(edge(to,from,cost,_idx));
es[_idx] = edge(from,to,cost,_idx);
}
int size(){return n;}
int parent(int v){
assert(0 <= v && v < n);
if (is_done_par_rdist_init == false) par_rdist_init();
return par[v];
}
int depth(int v){
assert(0 <= v && v < n);
if (dep[v] != -1) return dep[v];
if (v == root) return dep[v] = 0;
return dep[v] = depth(parent(v)) + 1;
}
int subtree_size(int v){
assert(0 <= v && v < n);
if (sub[v] != 0) return sub[v];
sub[v] = 1;
for (edge x : vs[v].adj){
if (x.to != parent(v)) sub[v] += subtree_size(x.to);
}
return sub[v];
}
int lca(int u, int v){
assert(0 <= u && u < n);
assert(0 <= v && v < n);
if (is_done_lca_init == false) lca_init();
if (depth(u) > depth(v)) swap(u,v);
for (int i = 0; i < 30; i++) if ((depth(v) - depth(u)) >> i & 1) v = par2[i][v];
if (u == v) return u;
for (int k = 29; k >= 0; k--){
if (par2[k][u] != par2[k][v]) {
u = par2[k][u];
v = par2[k][v];
}
}
return par2[0][u];
}
long long dist(int u, int v){
assert(0 <= u && u < n);
assert(0 <= v && v < n);
if (is_done_par_rdist_init == false) par_rdist_init();
return rdist[u] + rdist[v] - rdist[lca(u,v)] * 2LL;
}
vector<int> path(int f, int t){
assert(0 <= f && f < n);
assert(0 <= t && t < n);
int v = lca(f,t);
vector<int> fp = {f};
vector<int> tp = {t};
int fn = f, tn = t;
while (fn != v){
fn = parent(fn);
fp.emplace_back(fn);
}
while (tn != v){
tn = parent(tn);
tp.emplace_back(tn);
}
for (int i = int(tp.size()) - 2; i >= 0; i--){
fp.emplace_back(tp[i]);
}
return fp;
}
vector<long long> alldists(int v){
assert(0 <= v && v < n);
if (v == 0) return rdist;
vector<long long> dists(n,1e18);
vector<int> vis(n,0);
dists[v] = 0LL;
queue<int> que;
que.push(v);
while (!que.empty()){
int p = que.front(); que.pop();
vis[p]++;
for (edge x : vs[p].adj){
if (vis[x.to] == 0){
dists[x.to] = dists[p] + x.cost;
que.push(x.to);
}
}
}
return dists;
}
vector<int> dfs(int v){
assert(0 <= v && v < n);
vector<int> ans;
vector<int> vis(n,0);
_dfs(v,vis,ans);
return ans;
}
edge to_parent(int v){
assert(0 <= v && v < n && v != root);
if (is_done_par_rdist_init == false) par_rdist_init();
return es[epar[v]];
}
private:
int n;
int m;
int root;
int idx_vhfs;
bool is_done_lca_init;
bool is_done_par_rdist_init;
vector<vertex> vs;
vector<edge> es;
vector<int> edge_idx_cnt;
vector<int> par;
vector<int> epar;
vector<int> dep;
vector<int> sub;
vector<int> top;
vector<long long> rdist;
vector<vector<int>> par2;
void initialize(){
m = 0;
is_done_lca_init = false;
is_done_par_rdist_init = false;
vs.resize(n);
es.resize(n-1);
edge_idx_cnt.resize(n-1,0);
dep.resize(n,-1);
sub.resize(n,0);
}
void lca_init(){
par2.resize(30,vector<int>(n,-1));
for (int i = 0; i < n; i++) par2[0][i] = parent(i);
for (int i = 0; i < 29 ; i++) {
for (int j = 0; j < n; j++) {
if (par2[i][j] < 0) par2[i+1][j] = -1;
else par2[i+1][j] = par2[i][par2[i][j]];
}
}
is_done_lca_init = true;
}
void par_rdist_init(){
par.resize(n,-2);
epar.resize(n);
rdist.resize(n,-1);
par[root] = -1;
rdist[root] = 0;
queue<int> que;
que.push(root);
while (!que.empty()){
int p = que.front(); que.pop();
for (edge x : vs[p].adj){
if (par[x.to] == -2){
par[x.to] = p;
epar[x.to] = x.idx;
rdist[x.to] = rdist[p] + x.cost;
que.push(x.to);
}
}
}
is_done_par_rdist_init = true;
}
void _dfs(int v, vector<int> &vis, vector<int> &ans){
vis[v]++;
for (edge x : vs[v].adj){
if (vis[x.to] == 0) _dfs(x.to,vis,ans);
}
ans.emplace_back(v);
}
};
int op(int a, int b){return a + b;}
int e(){return 0;}
int main(){
int n, q; cin >> n >> q;
string s; cin >> s;
vector<int> a(n);
rep(i,n) a[i] = (s[i] == '(' ? 1 : -1);
vector<int> b(n-1);
rep(i,n-1) b[i] = (a[i] == 1 && a[i+1] == -1 ? 1 : 0);
segtree<int,op,e> seg(b);
vector<int> ans;
rep(c,q){
int t; cin >> t;
if (t == 1){
int p; cin >> p;
p--;
a[p] *= -1;
int q = max(p-1,0);
seg.set(q,(a[q] == 1 && a[q+1] == -1 ? 1 : 0));
q = min(q+1,n-2);
seg.set(q,(a[q] == 1 && a[q+1] == -1 ? 1 : 0));
}
else {
int l, r; cin >> l >> r;
l--, r--;
ans.emplace_back(seg.prod(l,r));
}
}
for (int x : ans) o(x);
}
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