結果
問題 |
No.1805 Approaching Many Typhoon
|
ユーザー |
|
提出日時 | 2022-01-12 20:17:53 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
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実行時間 | 68 ms / 2,000 ms |
コード長 | 2,052 bytes |
コンパイル時間 | 156 ms |
コンパイル使用メモリ | 82,232 KB |
実行使用メモリ | 72,136 KB |
最終ジャッジ日時 | 2024-11-15 14:59:42 |
合計ジャッジ時間 | 2,844 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 35 |
ソースコード
n, m = map(int,input().split()) s, g = map(int,input().split()) s -= 1; g -= 1 class dsu(): n=1 parent_or_size=[-1 for i in range(n)] def __init__(self,N): self.n=N self.parent_or_size=[-1 for i in range(N)] def merge(self,a,b): assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n) assert 0<=b<self.n, "0<=b<n,b={0},n={1}".format(b,self.n) x=self.leader(a) y=self.leader(b) if x==y: return x if (-self.parent_or_size[x]<-self.parent_or_size[y]): x,y=y,x self.parent_or_size[x]+=self.parent_or_size[y] self.parent_or_size[y]=x return x def same(self,a,b): assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n) assert 0<=b<self.n, "0<=b<n,b={0},n={1}".format(b,self.n) return self.leader(a)==self.leader(b) def leader(self,a): assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n) if (self.parent_or_size[a]<0): return a self.parent_or_size[a]=self.leader(self.parent_or_size[a]) return self.parent_or_size[a] def size(self,a): assert 0<=a<self.n, "0<=a<n,a={0},n={1}".format(a,self.n) return -self.parent_or_size[self.leader(a)] def groups(self): leader_buf=[0 for i in range(self.n)] group_size=[0 for i in range(self.n)] for i in range(self.n): leader_buf[i]=self.leader(i) group_size[leader_buf[i]]+=1 result=[[] for i in range(self.n)] for i in range(self.n): result[leader_buf[i]].append(i) result2=[] for i in range(self.n): if len(result[i])>0: result2.append(result[i]) return result2 graph = [[] for _ in range(n)] uv = [list(map(int,input().split())) for _ in range(m)] u = int(input()) I = set(map(int,input().split())) U = dsu(n) for u, v in uv: if u in I or v in I: continue else: U.merge(u - 1, v - 1) print('Yes' if U.same(s, g) else 'No')