結果
| 問題 |
No.1812 Uribo Road
|
| コンテスト | |
| ユーザー |
SSRS
|
| 提出日時 | 2022-01-14 21:46:03 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 441 ms / 5,000 ms |
| コード長 | 2,108 bytes |
| コンパイル時間 | 2,064 ms |
| コンパイル使用メモリ | 189,700 KB |
| 実行使用メモリ | 16,916 KB |
| 最終ジャッジ日時 | 2024-11-20 09:13:09 |
| 合計ジャッジ時間 | 8,031 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 30 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
int main(){
int N, M, K;
cin >> N >> M >> K;
vector<int> R(K);
for (int i = 0; i < K; i++){
cin >> R[i];
R[i]--;
}
vector<int> A(M), B(M), C(M);
for (int i = 0; i < M; i++){
cin >> A[i] >> B[i] >> C[i];
A[i]--;
B[i]--;
}
vector<vector<pair<int, int>>> E(N);
for (int i = 0; i < M; i++){
E[A[i]].push_back(make_pair(C[i], B[i]));
E[B[i]].push_back(make_pair(C[i], A[i]));
}
vector<int> id;
id.push_back(0);
id.push_back(N - 1);
for (int i = 0; i < K; i++){
id.push_back(A[R[i]]);
id.push_back(B[R[i]]);
}
int V = id.size();
vector<vector<int>> d(V, vector<int>(V));
for (int i = 0; i < V; i++){
vector<int> d2(N, -1);
priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;
pq.push(make_pair(0, id[i]));
while (!pq.empty()){
int c = pq.top().first;
int v = pq.top().second;
pq.pop();
if (d2[v] == -1){
d2[v] = c;
for (auto P : E[v]){
int w = P.second;
if (d2[w] == -1){
pq.push(make_pair(c + P.first, w));
}
}
}
}
for (int j = 0; j < V; j++){
d[i][j] = d2[id[j]];
}
}
vector<vector<int>> T(V, vector<int>(V, -1));
for (int i = 0; i < K; i++){
d[i * 2 + 2][i * 2 + 3] = C[R[i]];
d[i * 2 + 3][i * 2 + 2] = C[R[i]];
T[i * 2 + 2][i * 2 + 3] = i;
T[i * 2 + 3][i * 2 + 2] = i;
}
vector<vector<int>> d2(1 << K, vector<int>(V, -1));
priority_queue<tuple<int, int, int>, vector<tuple<int, int, int>>, greater<tuple<int, int, int>>> pq;
pq.push(make_tuple(0, 0, 0));
while (!pq.empty()){
int c = get<0>(pq.top());
int s = get<1>(pq.top());
int v = get<2>(pq.top());
pq.pop();
if (d2[s][v] == -1){
d2[s][v] = c;
for (int i = 0; i < V; i++){
int s2 = s;
if (T[v][i] != -1){
s2 |= 1 << T[v][i];
}
if (d2[s2][i] == -1){
pq.push(make_tuple(c + d[v][i], s2, i));
}
}
}
}
cout << d2[(1 << K) - 1][1] << endl;
}
SSRS