結果
| 問題 |
No.1813 Magical Stones
|
| コンテスト | |
| ユーザー |
👑 SPD_9X2
|
| 提出日時 | 2022-01-14 22:28:09 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 271 ms / 2,000 ms |
| コード長 | 3,217 bytes |
| コンパイル時間 | 296 ms |
| コンパイル使用メモリ | 81,992 KB |
| 実行使用メモリ | 137,264 KB |
| 最終ジャッジ日時 | 2024-11-20 12:02:01 |
| 合計ジャッジ時間 | 7,433 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 40 |
ソースコード
"""
グラフを強連結にすればよい
とりあえず SCCする
DAGになる
S1,G1
S2,G2
...
S3,G3
さて, StartとGoalがあるやつは
上手くやればくっ付けられる
"""
import sys
from sys import stdin
import sys
class scc_graph:
def __init__(self, N):
self.N = N
self.edges = []
def csr(self):
self.start = [0]*(self.N+1)
self.elist = [0]*len(self.edges)
for e in self.edges:
self.start[e[0]+1] += 1
for i in range(1, self.N+1):
self.start[i] += self.start[i-1]
counter = self.start[:]
for e in self.edges:
self.elist[counter[e[0]]] = e[1]
counter[e[0]] += 1
def add_edge(self, v, w):
self.edges.append((v, w))
def scc_ids(self):
self.csr()
N = self.N
now_ord = group_num = 0
visited = []
low = [0]*N
order = [-1]*N
ids = [0]*N
parent = [-1]*N
stack = []
for i in range(N):
if order[i] == -1:
stack.append(i)
stack.append(i)
while stack:
v = stack.pop()
if order[v] == -1:
low[v] = order[v] = now_ord
now_ord += 1
visited.append(v)
for i in range(self.start[v], self.start[v+1]):
to = self.elist[i]
if order[to] == -1:
stack.append(to)
stack.append(to)
parent[to] = v
else:
low[v] = min(low[v], order[to])
else:
if low[v] == order[v]:
while True:
u = visited.pop()
order[u] = N
ids[u] = group_num
if u == v:
break
group_num += 1
if parent[v] != -1:
low[parent[v]] = min(low[parent[v]], low[v])
for i, x in enumerate(ids):
ids[i] = group_num-1-x
return group_num, ids
def scc(self):
group_num, ids = self.scc_ids()
groups = [[] for _ in range(group_num)]
for i, x in enumerate(ids):
groups[x].append(i)
return groups
N,M = map(int,stdin.readline().split())
AB = []
g = scc_graph(N)
for i in range(M):
A,B = map(int,stdin.readline().split())
A -= 1;B -= 1
AB.append( (A,B) )
g.add_edge(A,B)
scc = g.scc()
dic = {}
for i in range(len(scc)):
for v in scc[i]:
dic[v] = i
inlis = [0] * len(scc)
olis = [0] * len(scc)
if len(scc) == 1:
print (0)
sys.exit()
for A,B in AB:
if dic[A] == dic[B]:
continue
olis[ dic[A] ] += 1
inlis[dic[B]] += 1
inone = 0
onone = 0
for i in inlis:
if i == 0:
inone += 1
for i in olis:
if i == 0:
onone += 1
ans = max(inone,onone)
print (ans)
SPD_9X2