結果

問題 No.1810 RGB Biscuits
ユーザー miscalc
提出日時 2022-01-14 22:50:27
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 19 ms / 2,000 ms
コード長 2,027 bytes
コンパイル時間 2,204 ms
コンパイル使用メモリ 205,692 KB
最終ジャッジ日時 2025-01-27 12:02:33
ジャッジサーバーID
(参考情報)
judge3 / judge3
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ファイルパターン 結果
sample AC * 2
other AC * 20
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ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#include <atcoder/modint>
using namespace atcoder;
//using mint = modint998244353;
using mint = modint1000000007;
using ll = long long;
using ld = long double;
using pll = pair<ll, ll>;
using tlll = tuple<ll, ll, ll>;
constexpr ll INF = 1LL << 60;
template<class T> bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;}
template<class T> bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;}
ll safemod(ll A, ll M) {return (A % M + M) % M;}
ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;}
ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);}
#define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false)
using mmat = vector<vector<mint>>;
mmat mmatrixprod(mmat &A1, mmat &A2)
{
ll n1 = A1.size(), n2 = A2.size();
ll m1 = A1.front().size(), m2 = A2.front().size();
assert(n2 == m1);
mmat ret(n1, vector<mint>(m2, 0));
for (ll i = 0; i < n1; i++)
{
for (ll j = 0; j < m2; j++)
{
for (ll k = 0; k < n2; k++)
{
ret[i][j] += A1[i][k] * A2[k][j];
}
}
}
return ret;
}
mmat mmatrixpow(mmat &A1, ll k)
{
ll n = A1.size();
mmat A10(n, vector<mint>(n, 0));
for (ll i = 0; i < n; i++)
{
for (ll j = 0; j < n; j++)
{
A10[i][j] = A1[i][j];
}
}
mmat ret(n, vector<mint>(n, 0));
for (ll i = 0; i < n; i++)
{
ret[i][i] = 1;
}
while (k > 0)
{
if ((k & 1) != 0)
ret = mmatrixprod(ret, A10);
A10 = mmatrixprod(A10, A10);
k >>= 1;
}
return ret;
}
int main()
{
ll A, B;
cin >> A >> B;
mmat C = {{A, B}, {1, 0}};
ll N;
cin >> N;
for (ll t = 0; t < N; t++)
{
ll T;
cin >> T;
mmat pw = mmatrixpow(C, T / 2);
mmat ret0 = {{1}, {1}};
mmat ret = mmatrixprod(pw, ret0);
mint r = ret.at(0).at(0), g = ret.at(1).at(0);
mint ans = r + g + (T % 2 == 0 ? 0 : A * r + B * g);
cout << ans.val() << '\n';
}
}
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