結果

問題 No.1817 Reversed Edges
ユーザー ktr216
提出日時 2022-01-21 22:08:22
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 391 ms / 2,000 ms
コード長 2,028 bytes
コンパイル時間 1,582 ms
コンパイル使用メモリ 175,256 KB
実行使用メモリ 258,176 KB
最終ジャッジ日時 2024-11-26 00:30:32
合計ジャッジ時間 11,127 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 23
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using VI = vector<int>;
using P = pair<int, int>;
#define REP(i, n) for (int i = 0; i < (int)(n); i++)
#define FOR(i, a, b) for (ll i = a; i < (ll)(b); i++)
#define ALL(a) (a).begin(),(a).end()
constexpr int INF = 1001001001;
constexpr ll LINF = 1001001001001001001ll;
constexpr int DX[] = {1, 0, -1, 0};
constexpr int DY[] = {0, 1, 0, -1};
template< typename T1, typename T2>
inline bool chmax(T1 &a, T2 b) {return a < b && (a = b, true); }
template< typename T1, typename T2>
inline bool chmin(T1 &a, T2 b) {return a > b && (a = b, true); }
const ll MOD = 1000000007;
int N, MAX_N = 2000001, idx = 0, MAX_LOG_V = 20;
vector<vector<int>> edge(MAX_N), parent(MAX_LOG_V, vector<int>(MAX_N, -1));
vector<int> tp(MAX_N), l(MAX_N), r(MAX_N), par(MAX_N, -1), depth(MAX_N, 0);
vector<bool> done(MAX_N, false);
void tps(int u) {
done[u] = true;
l[u] = idx;
tp[idx] = u;
idx++;
REP(i, edge[u].size()) {
int v = edge[u][i];
if (done[v]) continue;
par[v] = u;
depth[v] = depth[u] + 1;
tps(v);
}
r[u] = idx;
}
int main() {
int N;
cin >> N;
vector<int> A(N - 1), B(N - 1);
REP(i, N - 1) cin >> A[i] >> B[i];
REP(i, N - 1) {
edge[A[i] - 1].push_back(B[i] - 1);
edge[B[i] - 1].push_back(A[i] - 1);
}
tps(0);
vector<int> C(N, 0), D(N, 0);
for (int i = N - 1; i > 0; i--) {
int u = tp[i], v = par[u];
C[v] += C[u];
if (u < v) C[v]++;
}
FOR(i, 1, N) {
int u = tp[i], v = par[u];
D[u] = D[v];
if (u > v) D[u]++;
else D[u]--;
}
/*
REP(i, N) cout << tp[i] << " "; cout << "\n";
REP(i, N) cout << par[i] << " "; cout << "\n";
REP(i, N) cout << l[i] << " "; cout << "\n";
REP(i, N) cout << r[i] << " "; cout << "\n";
REP(i, N) cout << C[i] << " "; cout << endl;
REP(i, N) cout << D[i] << " "; cout << endl;
*/
REP(i, N) cout << C[0] + D[i] << endl;
}
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