結果

問題 No.1640 簡単な色塗り
ユーザー 👑 rin204
提出日時 2022-01-26 16:19:10
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 584 ms / 2,000 ms
コード長 2,078 bytes
コンパイル時間 298 ms
コンパイル使用メモリ 81,772 KB
実行使用メモリ 101,532 KB
最終ジャッジ日時 2024-12-23 07:21:29
合計ジャッジ時間 29,153 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 53
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class UnionFind():
    def __init__(self, n):
        self.n = n
        self.parents = [-1] * n
        self.hasloop = [False] * n
        self.group = n
    def find(self, x):
        if self.parents[x] < 0:
            return x
        else:
            self.parents[x] = self.find(self.parents[x])
            return self.parents[x]
    def union(self, x, y):
        x = self.find(x)
        y = self.find(y)
        if x == y:
            self.hasloop[x] = True
            return
        self.group -= 1
        if self.parents[x] > self.parents[y]:
            x, y = y, x
        self.hasloop[x] |= self.hasloop[y]
        self.parents[x] += self.parents[y]
        self.parents[y] = x
    def size(self, x):
        return -self.parents[self.find(x)]
    def same(self, x, y):
        return self.find(x) == self.find(y)
    def members(self, x):
        root = self.find(x)
        return [i for i in range(self.n) if self.find(i) == root]
    def roots(self):
        return [i for i, x in enumerate(self.parents) if x < 0]
    def group_count(self):
        return self.group
    def all_group_members(self):
        dic = {r:[] for r in self.roots()}
        for i in range(self.n):
            dic[self.find(i)].append(i)
        return dic
    def __str__(self):
        return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())
        
n = int(input())
ab = []
UF = UnionFind(n)
edges = [[] for _ in range(n)]
ans = [-1] * n
used = [False] * n
stack = []
for i in range(n):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    if UF.same(a, b):
        ans[i] = a + 1
        stack.append(a)
        used[i] = True
    else:
        edges[a].append((b, i))
        edges[b].append((a, i))
    
    UF.union(a, b)
    
for r in UF.roots():
    if not UF.hasloop[r]:
        print("No")
        exit()
print("Yes")
while stack:
    pos = stack.pop()
    for npos, i in edges[pos]:
        if used[i]:
            continue
        used[i] = True
        ans[i] = npos + 1
        stack.append(npos)
print(*ans, sep="\n")
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