結果
問題 | No.1824 門\松\列 |
ユーザー | riano |
提出日時 | 2022-01-28 21:28:02 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 5 ms / 2,000 ms |
コード長 | 4,362 bytes |
コンパイル時間 | 1,364 ms |
コンパイル使用メモリ | 174,068 KB |
実行使用メモリ | 11,300 KB |
最終ジャッジ日時 | 2024-06-09 14:17:20 |
合計ジャッジ時間 | 1,759 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 5 ms
11,156 KB |
testcase_01 | AC | 4 ms
11,300 KB |
testcase_02 | AC | 5 ms
11,260 KB |
testcase_03 | AC | 5 ms
11,164 KB |
testcase_04 | AC | 4 ms
11,160 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define ll long long #define rep(i,n) for(int i=0;i<n;i++) #define rrep(i,n) for(int i=n-1;i>=0;i--) #define rrep2(i,n,k) for(int i=n-1;i>=n-k;i--) #define vll(n,i) vector<long long>(n,i) #define v2ll(n,m,i) vector<vector<long long>>(n,vll(m,i)) #define v3ll(n,m,k,i) vector<vector<vector<long long>>>(n,v2ll(m,k,i)) #define v4ll(n,m,k,l,i) vector<vector<vector<vector<long long>>>>(n,v3ll(m,k,l,i)) #define all(v) v.begin(),v.end() #define chmin(k,m) k = min(k,m) #define chmax(k,m) k = max(k,m) #define Pr pair<ll,ll> #define Tp tuple<ll,ll,ll> #define riano_ std::ios::sync_with_stdio(false);std::cin.tie(nullptr) //Graph struct graph { long long N; vector<vector<tuple<long long,long long,int>>> G; vector<long long> par_v; vector<long long> par_e; int edge_count = 0; graph(long long n) { N = n; G = vector<vector<tuple<long long,long long,int>>>(N); par_v = vector<long long>(N,-1); par_e = vector<long long>(N,-1); } void unite(long long a,long long b,long long cost = 1,bool directed = false){ G[a].emplace_back(b,cost,edge_count); if(!directed) G[b].emplace_back(a,cost,edge_count); edge_count++; } }; const ll mod = 998244353; template<uint64_t mod> struct modint{ uint64_t val; constexpr modint(const int64_t val_=0) noexcept:val((val_%int64_t(mod)+int64_t(mod))%int64_t(mod)){} constexpr modint operator-() const noexcept{ return modint(*this)=mod-val; } constexpr modint operator+(const modint rhs) const noexcept{ return modint(*this)+=rhs; } constexpr modint operator-(const modint rhs) const noexcept{ return modint(*this)-=rhs; } constexpr modint operator*(const modint rhs) const noexcept{ return modint(*this)*=rhs; } constexpr modint operator/(const modint rhs) const noexcept{ return modint(*this)/=rhs; } constexpr modint &operator+=(const modint rhs) noexcept{ val+=rhs.val; val-=((val>=mod)?mod:0); return (*this); } constexpr modint &operator-=(const modint rhs) noexcept{ val+=((val<rhs.val)?mod:0); val-=rhs.val; return (*this); } constexpr modint &operator*=(const modint rhs) noexcept{ val=val*rhs.val%mod; return (*this); } constexpr modint &operator/=(modint rhs) noexcept{ uint64_t ex=mod-2; modint now=1; while(ex){ now*=((ex&1)?rhs:1); rhs*=rhs,ex>>=1; } return (*this)*=now; } modint & operator++(){ val++; if (val == mod) val = 0; return *this; } modint operator++(int){ modint<mod> res = *this; ++*this; return res; } constexpr bool operator==(const modint rhs) noexcept{ return val==rhs.val; } constexpr bool operator!=(const modint rhs) noexcept{ return val!=rhs.val; } friend constexpr ostream &operator<<(ostream& os,const modint x) noexcept{ return os<<(x.val); } friend constexpr istream &operator>>(istream& is,modint& x) noexcept{ uint64_t t; is>>t,x=t; return is; } }; typedef modint<mod> mint; mint pw(long long a,long long b,long long m = mod){ if(a%m==0) return mint(0); if(b==0) return mint(1); else if(b%2==0){ long long x = pw(a,b/2,m).val; return mint(x*x); } else{ long long x = pw(a,b-1,m).val; return mint(a*x); } } mint modinv(long long a, long long m = mod) { long long b = m, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } u %= m; return mint(u); } #define vm(n,i) vector<mint>(n,i) #define v2m(n,m,i) vector<vector<mint>>(n,vm(m,i)) #define v3m(n,m,k,i) vector<vector<vector<mint>>>(n,v2m(m,k,i)) #define v4m(n,m,k,l,i) vector<vector<vector<vector<mint>>>>(n,v3m(m,k,l,i)) void out(vector<ll> &v){ for(ll x:v) cout << x << " "; cout << "\n"; return; } int main() { riano_; ll ans = 0; ll N,M,K,T; cin >> T; ll ptn[(ll)1e6+1]; ptn[3] = 2; for(int i=4;i<=1e6;i++){ ptn[i] = ptn[i-1] + (ll)(i-1)*(ll)(i-2); } rep(ii,T){ ll N; cin >> N; cout << ptn[N]*2LL << "\n"; } }