結果
問題 | No.1969 XOR Equation |
ユーザー | chineristAC |
提出日時 | 2022-02-09 01:21:50 |
言語 | PyPy3 (7.3.15) |
結果 |
RE
|
実行時間 | - |
コード長 | 2,782 bytes |
コンパイル時間 | 289 ms |
コンパイル使用メモリ | 82,376 KB |
実行使用メモリ | 67,688 KB |
最終ジャッジ日時 | 2024-09-21 02:23:20 |
合計ジャッジ時間 | 3,718 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | RE | - |
testcase_01 | RE | - |
testcase_02 | RE | - |
testcase_03 | RE | - |
testcase_04 | RE | - |
testcase_05 | RE | - |
testcase_06 | RE | - |
testcase_07 | RE | - |
testcase_08 | RE | - |
testcase_09 | RE | - |
testcase_10 | RE | - |
testcase_11 | RE | - |
testcase_12 | RE | - |
testcase_13 | RE | - |
testcase_14 | RE | - |
testcase_15 | RE | - |
testcase_16 | RE | - |
testcase_17 | RE | - |
testcase_18 | RE | - |
testcase_19 | RE | - |
testcase_20 | RE | - |
testcase_21 | RE | - |
testcase_22 | RE | - |
testcase_23 | RE | - |
testcase_24 | RE | - |
testcase_25 | RE | - |
testcase_26 | RE | - |
testcase_27 | RE | - |
testcase_28 | RE | - |
testcase_29 | RE | - |
testcase_30 | RE | - |
testcase_31 | RE | - |
testcase_32 | RE | - |
testcase_33 | RE | - |
testcase_34 | RE | - |
testcase_35 | RE | - |
testcase_36 | RE | - |
ソースコード
def solve_mini(N,A,Y,M=60): dp = [[1<<(M+1) for j in range(N+1)] for i in range(M+1)] for j in range(Y>>M,N+1,2): dp[M][j] = 0 low_sort = [[i for i in range(N)] for _ in range(M)] for t in range(M): low_sort[t].sort(key=lambda i:A[i]%(1<<(t+1)),reverse=True) """ pre = [i for i in range(N)] for t in range(M): zero,one = [],[] for i in pre: if A[i]>>t & 1: one.append(i) else: zero.append(i) pre = one + zero low_sort[t] = [i for i in pre] """ for i in range(M)[::-1]: zero,one,two = 0,0,0 for j in range(N): if A[j]>>i & 1: one += 1 else: zero += 1 if one&1==(Y>>i & 1): dp[i][0] = min(dp[i][0], 2*dp[i+1][two]) if (zero+two)&1==(Y>>i & 1): dp[i][0] = min(dp[i][0], 2*dp[i+1][one+two]+1) if i==0: break for j in range(1,N+1): next_up = low_sort[i-1][j-1] if A[next_up]>>i & 1: one -= 1 two += 1 else: zero -= 1 one += 1 if j!=N: next_next_up = low_sort[i-1][j] if A[next_up]%(1<<(t+1)) == A[next_next_up]%(1<<(t+1)): continue if one&1==(Y>>i & 1): dp[i][j] = min(dp[i][j], 2*dp[i+1][two]) if (zero+two)&1==(Y>>i & 1): dp[i][j] = min(dp[i][j], 2*dp[i+1][one+two]+1) if dp[0][0]==1<<(M+1): return -1 return dp[0][0] def brute(N,A,Y): ans = 2**61 def dfs(d,tmp,up): nonlocal ans if d==60: if len(up)&1==0: return tmp else: return 1<<61 res = ans if tmp > res: return ans zero,one,two = 0,set(),set() for i in range(N): if A[i]>>d & 1: if i in up: two.add(i) else: one.add(i) else: if i in up: one.add(i) else: zero += 1 if len(one)&1==(Y>>d)&1: res = min(res,dfs(d+1,tmp,two)) if (zero+len(two))&1==(Y>>d)&1: n_up = set([i for i in one]+[j for j in two]) res = min(res,dfs(d+1,tmp+(1<<d),n_up)) ans = min(ans,res) return res res = dfs(0,0,set()) if res < 2**61: return res return -1 N,Y = map(int,input().split()) A = list(map(int,input().split())) print(brute(N,A,Y))