結果

問題 No.1838 Modulo Straight
ユーザー rianoriano
提出日時 2022-02-11 22:31:18
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 800 ms / 2,000 ms
コード長 6,333 bytes
コンパイル時間 2,058 ms
コンパイル使用メモリ 190,320 KB
実行使用メモリ 60,100 KB
最終ジャッジ日時 2024-06-27 20:00:33
合計ジャッジ時間 21,549 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 38
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define rep(i,n) for(int i=0;i<n;i++)
#define rrep(i,n) for(int i=n-1;i>=0;i--)
#define rrep2(i,n,k) for(int i=n-1;i>=n-k;i--)
#define vll(n,i) vector<long long>(n,i)
#define v2ll(n,m,i) vector<vector<long long>>(n,vll(m,i))
#define v3ll(n,m,k,i) vector<vector<vector<long long>>>(n,v2ll(m,k,i))
#define v4ll(n,m,k,l,i) vector<vector<vector<vector<long long>>>>(n,v3ll(m,k,l,i))
#define all(v) v.begin(),v.end()
#define chmin(k,m) k = min(k,m)
#define chmax(k,m) k = max(k,m)
#define Pr pair<ll,ll>
#define Tp tuple<ll,ll,ll>
#define riano_ std::ios::sync_with_stdio(false);std::cin.tie(nullptr)

//Graph
struct graph {
    long long N;
	vector<vector<tuple<long long,long long,int>>> G;
    vector<long long> par_v;
    vector<long long> par_e;
    int edge_count = 0;
    
	graph(long long n) {
        N = n;
		G = vector<vector<tuple<long long,long long,int>>>(N);
        par_v = vector<long long>(N,-1);
        par_e = vector<long long>(N,-1);
	}

    void unite(long long a,long long b,long long cost = 1,bool directed = false){
        G[a].emplace_back(b,cost,edge_count);
        if(!directed) G[b].emplace_back(a,cost,edge_count);
        edge_count++;
    }
};

const ll mod = 998244353;
template<uint64_t mod>
struct modint{
    uint64_t val;
    constexpr modint(const int64_t val_=0) noexcept:val((val_%int64_t(mod)+int64_t(mod))%int64_t(mod)){}
    constexpr modint operator-() const noexcept{
        return modint(*this)=mod-val;
    }
    constexpr modint operator+(const modint rhs) const noexcept{
        return modint(*this)+=rhs;
    }
    constexpr modint operator-(const modint rhs) const noexcept{
        return modint(*this)-=rhs;
    }
    constexpr modint operator*(const modint rhs) const noexcept{
        return modint(*this)*=rhs;
    }
    constexpr modint operator/(const modint rhs) const noexcept{
        return modint(*this)/=rhs;
    }
    constexpr modint &operator+=(const modint rhs) noexcept{
        val+=rhs.val;
        val-=((val>=mod)?mod:0);
        return (*this);
    }
    constexpr modint &operator-=(const modint rhs) noexcept{
        val+=((val<rhs.val)?mod:0);
        val-=rhs.val;
        return (*this);
    }
    constexpr modint &operator*=(const modint rhs) noexcept{
        val=val*rhs.val%mod;
        return (*this);
    }
    constexpr modint &operator/=(modint rhs) noexcept{
        uint64_t ex=mod-2;
        modint now=1;
        while(ex){
            now*=((ex&1)?rhs:1);
            rhs*=rhs,ex>>=1;
        }
        return (*this)*=now;
    }
    modint & operator++(){
        val++;
        if (val == mod) val = 0;
        return *this;
    }
    modint operator++(int){
        modint<mod> res = *this;
        ++*this;
        return res;
    }
    constexpr bool operator==(const modint rhs) noexcept{
        return val==rhs.val;
    }
    constexpr bool operator!=(const modint rhs) noexcept{
        return val!=rhs.val;
    }
    friend constexpr ostream &operator<<(ostream& os,const modint x) noexcept{
        return os<<(x.val);
    }
    friend constexpr istream &operator>>(istream& is,modint& x) noexcept{
        uint64_t t;
        is>>t,x=t;
        return is;
    }
};
typedef modint<mod> mint;
mint pw(long long a,long long b,long long m = mod){
    if(a%m==0) return mint(0);
    if(b==0) return mint(1);
    else if(b%2==0){
        long long x = pw(a,b/2,m).val;
        return mint(x*x);
    }
    else{
        long long x = pw(a,b-1,m).val;
        return mint(a*x);
    }
}
mint modinv(long long a, long long m = mod) {
    long long b = m, u = 1, v = 0;
    while (b) {
        long long t = a / b;
        a -= t * b; swap(a, b);
        u -= t * v; swap(u, v);
    }
    u %= m;
    return mint(u);
}
#define vm(n,i) vector<mint>(n,i)
#define v2m(n,m,i) vector<vector<mint>>(n,vm(m,i))
#define v3m(n,m,k,i) vector<vector<vector<mint>>>(n,v2m(m,k,i))
#define v4m(n,m,k,l,i) vector<vector<vector<vector<mint>>>>(n,v3m(m,k,l,i))
void out(vector<ll> &v){
    for(ll x:v) cout << x << " ";
    cout << "\n"; return;
}


//inversion
//転倒数 : distinct かつ座圧されている前提
class segtree {
public:
    ll n;
    vector<ll> A;
    segtree(ll k){
        n = 1;
        while(n<k){ n *= 2; }
        A=vector<ll>(2*n,0);
    }
 
    //a[i]にxを加算する
    void add(ll i,ll x){
        int index = n-1+i;
        A[index] += x;
        while(index>1){
            index /= 2;
            A[index] = A[2*index]+A[2*index+1];
        }
    }
 
    //a[i]をにする
    void replace(ll i,ll x){
        int index = n-1+i;
        A[index] = x;
        while(index>1){
            index /= 2;
            A[index] = A[2*index]+A[2*index+1];
        }
    }
 
    //a[i]+a[i+1]+…+a[j]を求める
    ll sum(ll i,ll j){
        return rangesum(i,j,1,1,n);
    }
 
    // a,b求める区間 k区間番号 c,d区間の始終点(k=1,c=1,d=nで入力する)
    ll rangesum(ll a,ll b,ll k,ll c,ll d){
        //単位元の設定
        ll el = 0;
        if(d<a||b<c){
            return el;
        }
        else if(a<=c&&d<=b){
            return A[k];
        }
        else{
            //2区間に分割して演算を行う
            ll p = rangesum(a,b,k*2,c,(c+d)/2)+rangesum(a,b,k*2+1,(c+d)/2+1,d);
            return p;
        }
    }
 
};

ll invr(vector<ll> &v){
    ll K = v.size();
    segtree seq(K+1);
    ll res = 0;
    rep(i,K){
        ll n = v[i];
        res += seq.sum(n,K);
        seq.add(n,1);
    }
    return res;
}

int main(){
    riano_; ll ans = 2e18;
    ll N,M,K,H,W; cin >> M >> K; N = M*K;
    ll a[N];
    rep(i,N) cin >> a[i];
    vector<vector<ll>> p(M);
    rep(i,N){
        p[a[i]].push_back(i+1);
    }
    vector<ll> b(N);
    rep(i,M){
        rep(j,K) b[j*M+i] = p[i][j];
    }
    ans = invr(b);
    map<ll,ll> lab;
    rep(i,K){
        vector<ll> c;
        rep(j,M){
            c.push_back(b[i*M+j]);
        }
        sort(all(c));
        rep(j,M){
            lab[c[j]] = j+1;
        }
    }
    ll tmp = ans;
    //cout << ans << endl;
    rep(i,M){
        rep(j,K){
            ll aa = lab[b[j*M+i]];
            //cout << j*M+i << " " << aa << endl;
            tmp += (M+1)-2*aa;
        }
        chmin(ans,tmp);
        //cout << ans << endl;
    }
    cout << ans << endl;
}
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