結果
問題 | No.1832 NAND Reversible |
ユーザー | snuke |
提出日時 | 2022-02-13 02:42:55 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 5,263 bytes |
コンパイル時間 | 2,173 ms |
コンパイル使用メモリ | 208,392 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-06-29 05:22:53 |
合計ジャッジ時間 | 3,127 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | WA | - |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 12 ms
6,944 KB |
testcase_04 | WA | - |
testcase_05 | AC | 2 ms
6,944 KB |
testcase_06 | AC | 10 ms
6,940 KB |
testcase_07 | AC | 11 ms
6,944 KB |
testcase_08 | AC | 11 ms
6,940 KB |
testcase_09 | WA | - |
testcase_10 | AC | 11 ms
6,940 KB |
testcase_11 | AC | 2 ms
6,944 KB |
testcase_12 | WA | - |
testcase_13 | AC | 2 ms
6,940 KB |
testcase_14 | AC | 2 ms
6,944 KB |
testcase_15 | AC | 5 ms
6,940 KB |
testcase_16 | AC | 8 ms
6,944 KB |
testcase_17 | AC | 11 ms
6,940 KB |
testcase_18 | AC | 11 ms
6,940 KB |
testcase_19 | AC | 10 ms
6,944 KB |
testcase_20 | AC | 10 ms
6,940 KB |
testcase_21 | AC | 11 ms
6,944 KB |
testcase_22 | AC | 11 ms
6,940 KB |
testcase_23 | WA | - |
testcase_24 | AC | 2 ms
6,944 KB |
testcase_25 | AC | 8 ms
6,944 KB |
ソースコード
#include <bits/stdc++.h> #define rep(i,n) for(int i = 0; i < (n); ++i) #define rep1(i,n) for(int i = 1; i <= (n); ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) #define srep(i,s,t) for (int i = s; i < (t); ++i) #define rng(a) a.begin(),a.end() #define rrng(a) a.rbegin(),a.rend() #define fi first #define se second #define pb push_back #define eb emplace_back #define pob pop_back #define sz(x) (int)(x).size() #define pcnt __builtin_popcountll #define snuke srand((unsigned)clock()+(unsigned)time(NULL)); #define newline puts("") using namespace std; template<typename T> using vc = vector<T>; template<typename T> using vv = vc<vc<T>>; template<typename T> using PQ = priority_queue<T,vc<T>,greater<T>>; using uint = unsigned; using ull = unsigned long long; using vi = vc<int>; using vvi = vv<int>; using vvvi = vv<vi>; using ll = long long; using vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using P = pair<int,int>; using vp = vc<P>; using vvp = vv<P>; int getInt(){int x;scanf("%d",&x);return x;} vi pm(int n, int s=0) { vi a(n); iota(rng(a),s); return a;} template<typename T>istream& operator>>(istream&i,vc<T>&v){rep(j,sz(v))i>>v[j];return i;} template<typename T>string join(const T&v,const string& d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();} template<typename T>ostream& operator<<(ostream&o,const vc<T>&v){if(sz(v))o<<join(v," ");return o;} template<typename T1,typename T2>istream& operator>>(istream&i,pair<T1,T2>&v){return i>>v.fi>>v.se;} template<typename T1,typename T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.fi<<","<<v.se;} template<typename T1,typename T2>bool mins(T1& x,const T2&y){if(x>y){x=y;return true;}else return false;} template<typename T1,typename T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;} template<typename Tx, typename Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;} template<typename T>ll suma(const vc<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;} template<typename T>ll suma(const vv<T>&a){ll res(0);for(auto&&x:a)res+=suma(x);return res;} template<typename T>void uni(T& a){sort(rng(a));a.erase(unique(rng(a)),a.end());} template<typename T>void prepend(vc<T>&a,const T&x){a.insert(a.begin(),x);} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #define dame { puts("-1"); return;} #define yes { puts("Yes"); return;} #define no { puts("No"); return;} #define ret(x) { cout<<(x)<<endl; return;} #define yn {puts("Yes");}else{puts("No");} const int MX = 200005; // Mod int const uint mod = 998244353; struct mint { uint x; mint(): x(0) {} mint(ll x):x((x%mod+mod)%mod) {} mint operator-() const { return mint(0) - *this;} mint operator~() const { return mint(1) / *this;} mint& operator+=(const mint& a) { if((x+=a.x)>=mod) x-=mod; return *this;} mint& operator-=(const mint& a) { if((x+=mod-a.x)>=mod) x-=mod; return *this;} mint& operator*=(const mint& a) { x=(ull)x*a.x%mod; return *this;} mint& operator/=(const mint& a) { x=(ull)x*a.pow(mod-2).x%mod; return *this;} mint operator+(const mint& a) const { return mint(*this) += a;} mint operator-(const mint& a) const { return mint(*this) -= a;} mint operator*(const mint& a) const { return mint(*this) *= a;} mint operator/(const mint& a) const { return mint(*this) /= a;} mint pow(ll t) const { mint res = 1; for (mint p=x;t;p*=p,t>>=1) if (t&1) res *= p; return res; } mint ppow(ll t) const { int p=mod-1; return pow((t%p+p)%p);} bool operator<(const mint& a) const { return x < a.x;} bool operator==(const mint& a) const { return x == a.x;} bool operator!=(const mint& a) const { return x != a.x;} }; mint ex(mint x, ll t) { return x.pow(t);} istream& operator>>(istream&i,mint&a) {i>>a.x;return i;} //* ostream& operator<<(ostream&o,const mint&a) {o<<a.x;return o;} /*/ ostream& operator<<(ostream&o, const mint&x) { int a = x.x, b = 1; rep(s,2)rep1(i,1000) { int y = ((s?-x:x)*i).x; if (abs(a)+b > y+i) a = s?-y:y, b = i; } o<<a; if (b != 1) o<<'/'<<b; return o; }//*/ using vm = vector<mint>; using vvm = vector<vm>; struct modinv { int n; vm d; modinv(): n(2), d({0,1}) {} mint operator()(int i) { while (n <= i) d.pb(-d[mod%n]*(mod/n)), ++n; return d[i];} mint operator[](int i) const { return d[i];} } invs; struct modfact { int n; vm d; modfact(): n(2), d({1,1}) {} mint operator()(int i) { while (n <= i) d.pb(d.back()*n), ++n; return d[i];} mint operator[](int i) const { return d[i];} } facs; struct modfactinv { int n; vm d; modfactinv(): n(2), d({1,1}) {} mint operator()(int i) { while (n <= i) d.pb(d.back()*invs(n)), ++n; return d[i];} mint operator[](int i) const { return d[i];} } ifacs; mint comb(int a, int b) { if (a < b || b < 0) return 0; return facs(a)*ifacs(b)*ifacs(a-b); } // struct Solver { void solve() { int n,k; scanf("%d%d",&n,&k); mint ans; if ((n&1) && k == 1) { ans += n; } if (k >= 2) { rep(i,n-1) { int r = n-i-2; if (r%2) continue; ans += comb(i,k-2)*(r+1); } } if (k == 0) ans += 1; cout<<ans<<endl; } }; int main() { int ts = 1; // scanf("%d",&ts); rep1(ti,ts) { Solver solver; solver.solve(); } return 0; }