結果

問題 No.1848 Long Prefixes
ユーザー leaf_1415leaf_1415
提出日時 2022-02-18 23:51:34
言語 C++11
(gcc 11.4.0)
結果
AC  
実行時間 39 ms / 2,000 ms
コード長 9,016 bytes
コンパイル時間 1,574 ms
コンパイル使用メモリ 110,620 KB
実行使用メモリ 14,356 KB
最終ジャッジ日時 2024-06-29 09:56:55
合計ジャッジ時間 3,258 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 39 ms
14,300 KB
testcase_01 AC 24 ms
14,356 KB
testcase_02 AC 34 ms
14,300 KB
testcase_03 AC 35 ms
14,248 KB
testcase_04 AC 25 ms
14,252 KB
testcase_05 AC 37 ms
13,692 KB
testcase_06 AC 35 ms
13,340 KB
testcase_07 AC 24 ms
13,860 KB
testcase_08 AC 35 ms
13,468 KB
testcase_09 AC 36 ms
13,760 KB
testcase_10 AC 26 ms
14,088 KB
testcase_11 AC 36 ms
14,040 KB
testcase_12 AC 33 ms
13,388 KB
testcase_13 AC 24 ms
13,688 KB
testcase_14 AC 34 ms
13,944 KB
testcase_15 AC 2 ms
5,376 KB
testcase_16 AC 2 ms
5,376 KB
testcase_17 AC 2 ms
5,376 KB
testcase_18 AC 2 ms
5,376 KB
testcase_19 AC 2 ms
5,376 KB
testcase_20 AC 2 ms
5,376 KB
testcase_21 AC 1 ms
5,376 KB
testcase_22 AC 2 ms
5,376 KB
testcase_23 AC 2 ms
5,376 KB
testcase_24 AC 2 ms
5,376 KB
testcase_25 AC 2 ms
5,376 KB
testcase_26 AC 2 ms
5,376 KB
testcase_27 AC 2 ms
5,376 KB
testcase_28 AC 2 ms
5,376 KB
testcase_29 AC 2 ms
5,376 KB
testcase_30 AC 2 ms
5,376 KB
testcase_31 AC 1 ms
5,376 KB
testcase_32 AC 2 ms
5,376 KB
testcase_33 AC 17 ms
7,876 KB
testcase_34 AC 22 ms
11,364 KB
testcase_35 AC 9 ms
5,376 KB
testcase_36 AC 15 ms
7,556 KB
testcase_37 AC 18 ms
9,916 KB
testcase_38 AC 20 ms
9,128 KB
testcase_39 AC 16 ms
7,660 KB
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstdlib>
#include <cassert>
#include <vector>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <bitset>
#include <string>
#include <algorithm>
#include <utility>
#include <complex>
#include <array>
#include <unordered_set>
#include <unordered_map>
#define rep(x, s, t) for(ll x = (s); (x) <= (t); (x)++)
#define per(x, s, t) for(ll x = (s); (x) >= (t); (x)--)
#define reps(x, s) for(ll x = 0; (x) < (ll)(s).size(); (x)++)
#define chmin(x, y) (x) = min((x), (y))
#define chmax(x, y) (x) = max((x), (y))
#define sz(x) ((ll)(x).size())
#define all(x) (x).begin(),(x).end()
#define outl(...) dump_func(__VA_ARGS__)
#define outf(x) cout << fixed << setprecision(16) << (x) << endl
#define pb push_back
#define fi first
#define se second
#define inf 2e18
#define eps 1e-9
const double PI = 3.1415926535897932384626433;
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> P;
struct edge{
ll to, cost;
edge(){}
edge(ll a, ll b){ to = a, cost = b;}
};
const int dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1};
const int mod = 1000000007;
//const int mod = 998244353;
struct mint{
int x;
mint(ll y = 0){if(y < 0 || y >= mod) y = (y%mod+mod)%mod; x = y;}
mint(const mint &ope) {x = ope.x;}
mint operator-(){return mint(-x);}
mint operator+(const mint &ope){return mint(x) += ope;}
mint operator-(const mint &ope){return mint(x) -= ope;}
mint operator*(const mint &ope){return mint(x) *= ope;}
mint operator/(const mint &ope){return mint(x) /= ope;}
mint& operator+=(const mint &ope){x += ope.x; if(x >= mod) x -= mod; return *this;}
mint& operator-=(const mint &ope){x += mod - ope.x; if(x >= mod) x -= mod; return *this;}
mint& operator*=(const mint &ope){ll tmp = x; tmp *= ope.x, tmp %= mod; x = tmp; return *this;}
mint& operator/=(const mint &ope){
ll n = mod-2; mint mul = ope;
while(n){if(n & 1) *this *= mul; mul *= mul; n >>= 1;}
return *this;
}
mint inverse(){return mint(1) / *this;}
bool operator ==(const mint &ope){return x == ope.x;}
bool operator !=(const mint &ope){return x != ope.x;}
bool operator <(const mint &ope)const{return x < ope.x;}
};
mint modpow(mint a, ll n){
if(n == 0) return mint(1);
if(n % 2) return a * modpow(a, n-1);
else return modpow(a*a, n/2);
}
istream& operator >>(istream &is, mint &ope){ll t; is >> t, ope.x = t; return is;}
ostream& operator <<(ostream &os, mint &ope){return os << ope.x;}
ostream& operator <<(ostream &os, const mint &ope){return os << ope.x;}
ll modpow(ll a, ll n, ll mod){
if(n == 0) return 1;
if(n % 2) return ((a%mod) * (modpow(a, n-1, mod)%mod)) % mod;
else return modpow((a*a)%mod, n/2, mod) % mod;
}
vector<mint> fact, fact_inv;
void make_fact(int n){
fact.resize(n+1), fact_inv.resize(n+1);
fact[0] = mint(1); rep(i, 1, n) fact[i] = fact[i-1] * mint(i);
fact_inv[n] = fact[n].inverse(); per(i, n-1, 0) fact_inv[i] = fact_inv[i+1] * mint(i+1);
}
mint comb(int n, int k){ if(n < 0 || k < 0 || n < k) return mint(0); return fact[n] * fact_inv[k] * fact_inv[n-k];}
mint perm(int n, int k){ return comb(n, k) * fact[k]; }
vector<int> prime, pvec, qrime;
void make_prime(int n){
prime.resize(n+1);
rep(i, 2, n){
if(prime[i] == 0) pvec.push_back(i), prime[i] = i;
for(auto p : pvec){ if(i*p > n || p > prime[i]) break; prime[i*p] = p;}
}
}
void make_qrime(int n){
qrime.resize(n+1);
rep(i, 2, n){int ni = i / prime[i]; if(prime[i] == prime[ni]) qrime[i] = qrime[ni] * prime[i]; else qrime[i] = prime[i];}
}
bool exceed(ll x, ll y, ll m){return y > 0 && x >= m / y + 1;}
void mark(){ cout << "*" << endl; }
void yes(){ cout << "YES" << endl; }
void no(){ cout << "NO" << endl; }
ll floor(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return a/b; else return -((-a+b-1)/b); }
ll ceil(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return (a+b-1)/b; else return -((-a)/b); }
ll modulo(ll a, ll b){ b = abs(b); return a - floor(a, b) * b;}
ll sgn(ll x){ if(x > 0) return 1; if(x < 0) return -1; return 0;}
ll gcd(ll a, ll b){if(b == 0) return a; return gcd(b, a%b);}
ll lcm(ll a, ll b){return a/gcd(a, b)*b;}
ll arith(ll x){return x*(x+1)/2;}
ll arith(ll l, ll r){return arith(r) - arith(l-1);}
ll digitnum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret++; return ret;}
ll digitsum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret += x % b; return ret;}
string lltos(ll x){string ret; for(;x;x/=10) ret += x % 10 + '0'; reverse(all(ret)); return ret;}
ll stoll(string &s){ll ret = 0; for(auto c : s) ret *= 10, ret += c - '0'; return ret;}
template<typename T> void uniq(T &vec){sort(all(vec)); vec.erase(unique(all(vec)), vec.end());}
int popcount(ull x){
x -= ((x>>1)&0x5555555555555555ULL), x = (x & 0x3333333333333333ULL) + ((x>>2) & 0x3333333333333333ULL);
return (((x + (x>>4)) & 0x0F0F0F0F0F0F0F0FULL) * 0x0101010101010101ULL) >> 56;
}
template<class S, class T> pair<S, T>& operator+=(pair<S, T> &s, const pair<S, T> &t){s.first += t.first, s.second += t.second; return s;}
template<class S, class T> pair<S, T>& operator-=(pair<S, T> &s, const pair<S, T> &t){s.first -= t.first, s.second -= t.second; return s;}
template<class S, class T> pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t){return pair<S,T>(s.first+t.first, s.second+t.second);}
template<class S, class T> pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t){return pair<S,T>(s.first-t.first, s.second-t.second);}
template<class T> T dot(const pair<T, T> &s, const pair<T, T> &t){return s.first*t.first + s.second*t.second;}
template<class T> T cross(const pair<T, T> &s, const pair<T, T> &t){return s.first*t.second - s.second*t.first;}
template<typename T, typename U> ostream& operator << (ostream& os, pair<T, U>& ope){ os << "(" << ope.first << ", " << ope.second << ")"; return os
    ;}
template<typename T, typename U> ostream& operator << (ostream& os, const pair<T, U>& ope){ os << "(" << ope.first << ", " << ope.second << ")";
    return os;}
template<typename T> ostream& operator << (ostream& os, vector<T>& vec){reps(i, vec) os << vec[i] << " "; return os;}
template<typename T> ostream& operator << (ostream& os, const vector<T>& vec){reps(i, vec) os << vec[i] << " "; return os;}
template<typename T> ostream& operator << (ostream& os, list<T>& ls){for(auto x : ls) os << x << " "; return os;}
template<typename T> ostream& operator << (ostream& os, const list<T>& ls){for(auto x : ls) os << x << " "; return os;}
template<typename T> ostream& operator << (ostream& os, deque<T>& deq){reps(i, deq) os << deq[i] << " "; return os;}
template<typename T, typename U> ostream& operator << (ostream& os, map<T, U>& ope){ for(auto p : ope) os << "(" << p.first << ", " << p.second << "
    ),";return os;}
template<typename T> ostream& operator << (ostream& os, set<T>& ope){for(auto x : ope) os << x << " "; return os;}
template<typename T> ostream& operator << (ostream& os, multiset<T>& ope){for(auto x : ope) os << x << " "; return os;}
template<typename T> void outa(T a[], ll s, ll t){rep(i, s, t){ cout << a[i]; if(i < t) cout << " ";} cout << endl;}
template<typename T, size_t N> ostream& operator << (ostream& os, array<T, N>& arr){reps(i, arr) os << arr[i] << " "; return os;}
template<typename T, size_t N> ostream& operator << (ostream& os, const array<T, N>& arr){reps(i, arr) os << arr[i] << " "; return os;}
void dump_func(){cout << endl;}
template <class Head, class... Tail>
void dump_func(Head &&head, Tail &&... tail){cout << head; if(sizeof...(Tail) > 0) cout << " "; dump_func(std::move(tail)...);}
void z_algorithm(vector<P> &s, vector<ll> &z)
{
z.resize(s.size());
z[0] = s.size();
int x = 0, y = 0;
for(int i = 1; i < s.size(); i++){
if(i > y){
z[i] = 0;
for(int j = 0; j < s.size(); j++){
if(i+j >= s.size() || s[i+j] != s[j]) break;
z[i]++;
}
x = i, y = i + z[i] - 1;
}
else if(i + z[i-x] <= y) z[i] = z[i-x];
else{
z[i] = y-i+1;
for(int j = y-i+1; j < s.size(); j++){
if(i+j >= s.size() || s[i+j] != s[j]) break;
z[i]++;
}
x = i, y = i + z[i] - 1;
}
}
}
ll n;
ll a[200005], sum[200005];
string s;
vector<ll> z;
int main(void)
{
ios::sync_with_stdio(0);
cin.tie(0);
cin >> n;
rep(i, 0, n-1) cin >> a[i];
cin >> s;
sum[0] = a[0];
rep(i, 1, n-1) sum[i] = sum[i-1] + a[i];
vector<P> vec;
rep(i, 0, n-1) vec.pb(P(s[i]-'a', a[i]));
if(sz(vec) == 1){
outl(mint(arith(a[0])));
return 0;
}
vector<P> vec2 = vec;
vec2.erase(vec2.begin());
z_algorithm(vec2, z);
mint ans = 0;
rep(i, 0, n-1){
if(vec[i].fi != vec[0].fi) continue;
if(vec[i].se < vec[0].se){
ans += mint(arith(vec[i].se));
continue;
}
ans += mint(arith(vec[0].se));
ans += mint(vec[0].se) * mint(vec[i].se - vec[0].se);
if(i <= n-2){
ll l = z[i];
ans += sum[l] - sum[0];
if(l+1 <= n-1 && i+1+l <= n-1 && vec[l+1].fi == vec[i+1+l].fi) ans += min(vec[l+1].se, vec[i+1+l].se);
}
}
outl(ans);
return 0;
}
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