結果

問題 No.1111 コード進行
ユーザー commycommy
提出日時 2022-02-21 02:03:47
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 79 ms / 2,000 ms
コード長 3,908 bytes
コンパイル時間 923 ms
コンパイル使用メモリ 83,112 KB
最終ジャッジ日時 2025-01-28 01:14:52
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 48
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <algorithm>
#include <iostream>
#include <numeric>
#include <string>
#include <tuple>
#include <utility>
#include <vector>

#define rep(i, a, b) for (int i = int(a); i < int(b); i++)
using namespace std;
using ll = long long int;
using P = pair<ll, ll>;

// clang-format off
#ifdef _DEBUG_
#define dump(...) do{ cerr << __LINE__ << ":\t" << #__VA_ARGS__ << " = "; debug_print(__VA_ARGS__); } while(false)
template<typename T, typename... Ts> void debug_print(const T &t, const Ts &...ts) { cerr << t; ((cerr << ", " << ts), ...); cerr << endl; }
#else
#define dump(...) do{ } while(false)
#endif
template<typename T> vector<T> make_v(size_t a, T b) { return vector<T>(a, b); }
template<typename... Ts> auto make_v(size_t a, Ts... ts) { return vector<decltype(make_v(ts...))>(a, make_v(ts...)); }
template<typename T> bool chmin(T &a, const T& b) { if (a > b) {a = b; return true; } return false; }
template<typename T> bool chmax(T &a, const T& b) { if (a < b) {a = b; return true; } return false; }
template<typename T, typename... Ts> void print(const T& t, const Ts&... ts) { cout << t; ((cout << ' ' << ts), ...); cout << '\n'; }
template<typename... Ts> void input(Ts&... ts) { (cin >> ... >> ts); }
template<typename T> istream &operator,(istream &in, T &t) { return in >> t; }
// clang-format on

template<ll MOD = 1000000007>
class ModInt {
    ll n;
    ModInt constexpr inverse() const {
        return ModInt::pow(*this, MOD - 2);
    }

public:
    ModInt() : n(0) {}
    ModInt(ll _n) : n(((_n % MOD) + MOD) % MOD) {}
    ModInt operator+=(const ModInt &m) {
        n += m.n;
        if (n >= MOD) n -= MOD;
        return *this;
    }
    ModInt operator-=(const ModInt &m) {
        n -= m.n;
        if (n < 0) n += MOD;
        return *this;
    }
    ModInt operator*=(const ModInt &m) {
        n *= m.n;
        if (n >= MOD) n %= MOD;
        return *this;
    }
    ModInt operator/=(const ModInt &m) {
        (*this) *= m.inverse();
        return *this;
    }
    friend ModInt operator+(ModInt t, const ModInt &m) {
        return t += m;
    }
    friend ModInt operator-(ModInt t, const ModInt &m) {
        return t -= m;
    }
    friend ModInt operator*(ModInt t, const ModInt &m) {
        return t *= m;
    }
    friend ModInt operator/(ModInt t, const ModInt &m) {
        return t /= m;
    }
    ModInt operator=(const ll l) {
        n = l % MOD;
        if (n < 0) n += MOD;
        return *this;
    }
    friend ostream &operator<<(ostream &out, const ModInt &m) {
        out << m.n;
        return out;
    }
    friend istream &operator>>(istream &in, ModInt &m) {
        ll l;
        in >> l;
        m = l;
        return in;
    }
    static constexpr ModInt pow(const ModInt x, ll p) {
        ModInt<MOD> ans = 1;
        for (ModInt<MOD> m = x; p > 0; p /= 2, m *= m) {
            if (p % 2) ans *= m;
        }
        return ans;
    }
    static constexpr ll mod() {
        return MOD;
    }
};
using mint = ModInt<>;
mint operator"" _m(unsigned long long m) {
    return mint(m);
}

int main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    int n, m, k;
    cin, n, m, k;
    vector<int> P(m), Q(m), C(m);
    rep(i, 0, m) {
        cin, P[i], Q[i], C[i];
        P[i]--;
        Q[i]--;
    }

    const int codes = 300;
    auto dp = make_v(2, codes, k + 1, 0_m);
    rep(i, 0, codes) {
        dp[0][i][0] = 1;
    }
    rep(_, 0, n - 1) {
        int cur = _ % 2, nxt = (_ + 1) % 2;
        rep(i, 0, codes) {
            rep(j, 0, k + 1) {
                dp[nxt][i][j] = 0;
            }
        }
        rep(i, 0, m) {
            rep(j, 0, k + 1) {
                if (j + C[i] <= k) {
                    dp[nxt][Q[i]][j + C[i]] += dp[cur][P[i]][j];
                }
            }
        }
    }
    mint ans = 0;
    rep(i, 0, codes) {
        ans += dp[(n - 1) % 2][i][k];
    }
    print(ans);

    return 0;
}
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