結果

問題 No.1713 trick or treat!
ユーザー Kanten4205
提出日時 2022-02-21 11:40:05
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 4 ms / 2,000 ms
コード長 6,405 bytes
コンパイル時間 1,646 ms
コンパイル使用メモリ 174,048 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-29 15:56:18
合計ジャッジ時間 2,170 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 5
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
const long long MOD1 = 1000000007;
const long long MOD2 = 998244353;
typedef long long ll;
typedef pair<ll, ll> P;
const long long INF = 1e17;
template <typename T>
void input_arr(vector<T>& A, ll N) {
for (ll i = 0; i < N; i++) {
cin >> A[i];
}
}
template <typename T, typename Q>
void input_arr(vector<pair<T, Q>>& A, ll N) {
for (ll i = 0; i < N; i++) {
cin >> A[i].first >> A[i].second;
}
}
template <typename T>
void input_arr(vector<vector<T>>& A, ll H, ll W) {
for (ll i = 0; i < H; i++) {
for (ll j = 0; j < W; j++) {
cin >> A[i][j];
}
}
}
vector<bool>seen(200010, false);
vector<P>kukan(200010, {INF, -INF});
vector<ll>B;
ll num = -1;
void dfs(vector<vector<ll>>&G, ll v) {
seen[v] = true;
kukan[v].first = (ll)B.size() - 1;
for (auto nv : G[v]) {
if (!seen[nv]) {
if (num != nv) {
B.push_back(nv); num = nv;
}
dfs(G, nv);
}
}
kukan[v].second = B.size();
}
struct SuccinctIndexableDictionary {
size_t length;
size_t blocks;
vector< unsigned > bit, sum;
SuccinctIndexableDictionary() = default;
SuccinctIndexableDictionary(size_t length) : length(length), blocks((length + 31) >> 5) {
bit.assign(blocks, 0U);
sum.assign(blocks, 0U);
}
void set(int k) {
bit[k >> 5] |= 1U << (k & 31);
}
void build() {
sum[0] = 0U;
for(int i = 1; i < blocks; i++) {
sum[i] = sum[i - 1] + __builtin_popcount(bit[i - 1]);
}
}
bool operator[](int k) {
return (bool((bit[k >> 5] >> (k & 31)) & 1));
}
int rank(int k) {
return (sum[k >> 5] + __builtin_popcount(bit[k >> 5] & ((1U << (k & 31)) - 1)));
}
int rank(bool val, int k) {
return (val ? rank(k) : k - rank(k));
}
};
template< typename T, int MAXLOG >
struct WaveletMatrix {
size_t length;
SuccinctIndexableDictionary matrix[MAXLOG];
int mid[MAXLOG];
WaveletMatrix() = default;
WaveletMatrix(vector< T > v) : length(v.size()) {
vector< T > l(length), r(length);
for(int level = MAXLOG - 1; level >= 0; level--) {
matrix[level] = SuccinctIndexableDictionary(length + 1);
int left = 0, right = 0;
for(int i = 0; i < length; i++) {
if(((v[i] >> level) & 1)) {
matrix[level].set(i);
r[right++] = v[i];
} else {
l[left++] = v[i];
}
}
mid[level] = left;
matrix[level].build();
v.swap(l);
for(int i = 0; i < right; i++) {
v[left + i] = r[i];
}
}
}
pair< int, int > succ(bool f, int l, int r, int level) {
return {matrix[level].rank(f, l) + mid[level] * f, matrix[level].rank(f, r) + mid[level] * f};
}
// v[k]
T access(int k) {
T ret = 0;
for(int level = MAXLOG - 1; level >= 0; level--) {
bool f = matrix[level][k];
if(f) ret |= T(1) << level;
k = matrix[level].rank(f, k) + mid[level] * f;
}
return ret;
}
T operator[](const int &k) {
return access(k);
}
// count i s.t. (0 <= i < r) && v[i] == x
int rank(const T &x, int r) {
int l = 0;
for(int level = MAXLOG - 1; level >= 0; level--) {
tie(l, r) = succ((x >> level) & 1, l, r, level);
}
return r - l;
}
// k-th(0-indexed) smallest number in v[l,r)
T kth_smallest(int l, int r, int k) {
assert(0 <= k && k < r - l);
T ret = 0;
for(int level = MAXLOG - 1; level >= 0; level--) {
int cnt = matrix[level].rank(false, r) - matrix[level].rank(false, l);
bool f = cnt <= k;
if(f) {
ret |= T(1) << level;
k -= cnt;
}
tie(l, r) = succ(f, l, r, level);
}
return ret;
}
// k-th(0-indexed) largest number in v[l,r)
T kth_largest(int l, int r, int k) {
return kth_smallest(l, r, r - l - k - 1);
}
// count i s.t. (l <= i < r) && (v[i] < upper)
int range_freq(int l, int r, T upper) {
int ret = 0;
for(int level = MAXLOG - 1; level >= 0; level--) {
bool f = ((upper >> level) & 1);
if(f) ret += matrix[level].rank(false, r) - matrix[level].rank(false, l);
tie(l, r) = succ(f, l, r, level);
}
return ret;
}
// count i s.t. (l <= i < r) && (lower <= v[i] < upper)
int range_freq(int l, int r, T lower, T upper) {
return range_freq(l, r, upper) - range_freq(l, r, lower);
}
// max v[i] s.t. (l <= i < r) && (v[i] < upper)
T prev_value(int l, int r, T upper) {
int cnt = range_freq(l, r, upper);
return cnt == 0 ? T(-1) : kth_smallest(l, r, cnt - 1);
}
// min v[i] s.t. (l <= i < r) && (lower <= v[i])
T next_value(int l, int r, T lower) {
int cnt = range_freq(l, r, lower);
return cnt == r - l ? T(-1) : kth_smallest(l, r, cnt);
}
};
template< typename T, int MAXLOG >
struct CompressedWaveletMatrix {
WaveletMatrix< int, MAXLOG > mat;
vector< T > ys;
CompressedWaveletMatrix(const vector< T > &v) : ys(v) {
sort(begin(ys), end(ys));
ys.erase(unique(begin(ys), end(ys)), end(ys));
vector< int > t(v.size());
for(int i = 0; i < v.size(); i++) t[i] = get(v[i]);
mat = WaveletMatrix< int, MAXLOG >(t);
}
inline int get(const T& x) {
return lower_bound(begin(ys), end(ys), x) - begin(ys);
}
T access(int k) {
return ys[mat.access(k)];
}
T operator[](const int &k) {
return access(k);
}
int rank(const T &x, int r) {
auto pos = get(x);
if(pos == ys.size() || ys[pos] != x) return 0;
return mat.rank(pos, r);
}
T kth_smallest(int l, int r, int k) {
return ys[mat.kth_smallest(l, r, k)];
}
T kth_largest(int l, int r, int k) {
return ys[mat.kth_largest(l, r, k)];
}
int range_freq(int l, int r, T upper) {
return mat.range_freq(l, r, get(upper));
}
int range_freq(int l, int r, T lower, T upper) {
return mat.range_freq(l, r, get(lower), get(upper));
}
T prev_value(int l, int r, T upper) {
auto ret = mat.prev_value(l, r, get(upper));
return ret == -1 ? T(-1) : ys[ret];
}
T next_value(int l, int r, T lower) {
auto ret = mat.next_value(l, r, get(lower));
return ret == -1 ? T(-1) : ys[ret];
}
};
void solve() {
ll a, b; cin >> a >> b;
ll num = (a | b);
ll ans = 1;
for (ll i = 2; i <= num; i++) {
ans *= i;
}
cout << ans << endl;
}
int main() {
ll T=1;//cin>>T;
while(T--)solve();
}
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