結果

問題 No.1863 Xor Sum 2...?
ユーザー Carpenters-Cat
提出日時 2022-03-04 22:21:13
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 107 ms / 2,000 ms
コード長 7,567 bytes
コンパイル時間 1,782 ms
コンパイル使用メモリ 131,748 KB
最終ジャッジ日時 2025-01-28 05:30:53
ジャッジサーバーID
（参考情報） 		judge3 / judge1
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ファイルパターン 結果
sample AC * 3
other AC * 28
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ソースコード

diff #
プレゼンテーションモードにする

#include <algorithm>
#include <bitset>
#include <cassert>
#include <cmath>
#include <deque>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <utility>
#include <vector>
using namespace std;
using ll = long long;
using Vi = vector<int>;
using VVi = vector<Vi>;
using Vl = vector<ll>;
using VVl = vector<Vl>;
using P = pair<int, int>;
using Vp = vector<P>;
using VVp = vector<Vp>;
using Pl = pair<ll, int>;
using Vpl = vector<Pl>;
using VVpl = vector<Vpl>;
using tup = tuple<ll, ll, int>;
using Vt = vector<tuple<int, int, int>>;
using Pll = pair<ll, ll>;
using Vc = vector<char>;
using VVc = vector<Vc>;
template <class U>
using PQmax = priority_queue<U>;
template <class U>
using PQmin = priority_queue<U, vector<U>, greater<U>>;
void tprsort(int u, const VVi& gr, Vi& tpr, Vi& par);
void tprsort(const VVi& gr, Vi& tpr);
ll mpow(ll x, ll n, ll m = 1e9 + 7);
ll comb(int n, int r, const Vl& kai, const Vl& fkai, ll m = 1e9 + 7);
ll gcd(ll a, ll b);
int LCA(const VVi& par, const Vi& depth, int a, int b);
Vi sccResolve(const VVi& gr);
void dijkstra(const VVi& gr, const VVl& cost, Vl& dist, int s);
class unionfind
{
private:
    Vi par;
    Vi siz;
    Vi val;
public:
    unionfind(int N);
    unionfind();
    int root(int v);
    void merge(int a, int b);
    bool same(int a, int b);
    int value(int a);
};
int main()
{
    int N;
    cin >> N;
    Vl A(N), B(N + 1);
    Vl sum(N + 1);
    Vl xoa(N + 1);
    Vl cnt(N + 1);
    sum[0] = xoa[0] = cnt[0] = 0;
    for (int i = 0; i < N; i++) {
        cin >> A[i];
        /*if (i) {
            B[i] = B[i] ^ B[i - 1];
        }
        sum[i + 1] = sum[i] + A[i];
        xoa[i + 1] = xoa[i] ^ A[i];
        cnt[i + 1] = cnt[i] + B[i];*/
    }
    B[0] = 0;
    for (int i = 0; i < N; i++) {
        cin >> B[i + 1];
        B[i + 1] ^= B[i];
        cnt[i + 1] = cnt[i] + B[i + 1];
    }
    /*for (int i = 0; i < N; i++) {
        cout << B[i] << ' ';
    }
    cout << endl;
    for (int i = 0; i <= N; i++) {
        cout << cnt[i] << ' ';
    }
    cout << endl;*/
    ll ans = 0;
    int r = 0;
    ll s = 0;
    ll x = 0;
    for (int l = 0; l < N; l++) {
        if (l == r) {
            r++;
            s += A[r - 1];
            x = x ^ A[r - 1];
        }
        while (r <= N) {
            r++;
            if (r > N) {
                r--;
                break;
            }
            s += A[r - 1];
            x = x ^ A[r - 1];
            if (s > x) {
                r--;
                s -= A[r];
                x ^= A[r];
                break;
            }
        }
        if (!B[l]) {
            ans += (r - l) - (cnt[r] - cnt[l]);
        } else {
            ans += (cnt[r] - cnt[l]);
        }
        s -= A[l];
        x ^= A[l];
        // cout << l << ' ' << r << ' ' << ans << endl;
    }
    cout << ans << endl;
}
// Library
void tprsort(const VVi& gr, Vi& tpr)
{
    queue<int> que;
    int N = gr.size();
    Vi siz(N, 0);
    for (int i = 0; i < N; i++) {
        for (int j : gr[i]) {
            siz[j]++;
        }
    }
    for (int i = 0; i < N; i++) {
        if (siz[i] == 0) {
            que.push(i);
        }
    }
    while (!que.empty()) {
        int u = que.front();
        que.pop();
        tpr.push_back(u);
        for (int v : gr[u]) {
            siz[v]--;
            if (siz[v] == 0) {
                que.push(v);
            }
        }
    }
    reverse(tpr.begin(), tpr.end());
}
void tprsort(int u, const VVi& gr, Vi& tpr, Vi& par)
{
    // idx[u] = tpr.size();
    /*for (int v : gr[u]) {
        if (par[v] == u || par[v] == -1) {
            par[v] = u;
            tprsort(v, gr, tpr, par);
        }
    }
    tpr.push_back(u);*/
    stack<int> st;
    st.push(u);
    bool vis[2000020];
    for (int i = 0; i <= gr.size(); i++) {
        vis[i] = false;
    }
    while (!st.empty()) {
        int v = st.top();
        if (!vis[v]) {
            vis[v] = true;
            for (int p : gr[v]) {
                if (par[p] == -1) {
                    par[p] = v;
                    st.push(p);
                }
            }
        } else {
            tpr.push_back(v);
            st.pop();
        }
    }
}
Vi sccResolve(const VVi& gr)
{
    int N = gr.size();
    Vi tpr;
    Vi par(N, -1);
    for (int i = 0; i < N; i++) {
        if (par[i] == -1) {
            tprsort(i, gr, tpr, par);
        }
    }
    Vi ret(N, -1);
    int now = 0;
    for (int i = N - 1; i >= 0; i--) {
        int u = tpr[i];
        if (ret[u] != -1) {
            continue;
        }
        ret[u] = now;
        stack<int> st;
        st.push(u);
        while (!st.empty()) {
            int v = st.top();
            st.pop();
            for (int p : gr[v]) {
                if (ret[p] == -1) {
                    st.push(p);
                    ret[p] = now;
                }
            }
        }
        now++;
    }
    return ret;
}
ll gcd(ll a, ll b)
{
    while (b) {
        a %= b;
        swap(a, b);
    }
    return a;
}
ll mpow(ll x, ll n, ll m)
{
    ll ret = 1;
    while (n) {
        if (n % 2) {
            ret *= x;
            ret %= m;
        }
        x = (x * x) % m;
        n /= 2;
    }
    return ret;
}
ll comb(int n, int r, const Vl& kai, const Vl& fkai, ll m)
{
    if (n < 0 || r < 0 || n < r) {
        return 0;
    }
    ll ret = kai[n];
    ret *= fkai[r];
    ret %= m;
    ret *= fkai[n - r];
    ret %= m;
    return ret;
}
int LCA(const VVi& par, const Vi& depth, int a, int b)
{
    if (depth[a] < depth[b]) {
        swap(a, b);
    }
    int dis = depth[a] - depth[b];
    for (int i = 19; i >= 0; i--) {
        if ((dis >> i) & 1) {
            a = par[i][a];
        }
    }
    if (a == b) {
        return a;
    }
    for (int i = 19; i >= 0; i--) {
        if (par[i][a] != par[i][b]) {
            a = par[i][a];
            b = par[i][b];
        }
    }
    return par[0][a];
}
void dijkstra(const VVi& gr, const VVl& cost, Vl& dist, int s)
{
    ll INF = (ll)1e18;
    dist.assign(gr.size(), INF);
    dist[s] = 0;
    PQmin<Pl> pque;
    pque.push(make_pair(0, s));
    while (!pque.empty()) {
        auto [L, u] = pque.top();
        pque.pop();
        while (L != dist[u] && !pque.empty()) {
            tie(L, u) = pque.top();
            pque.pop();
        }
        for (int i = 0; i < gr[u].size(); i++) {
            int v = gr[u][i];
            ll c = cost[u][i];
            if (dist[v] > c + L) {
                dist[v] = c + L;
                pque.push(make_pair(dist[v], v));
            }
        }
    }
    return;
}
unionfind::unionfind(int N)
{
    par.resize(N + 1);
    siz.assign(N + 1, 1);
    val.assign(N + 1, 0);
    for (int i = 0; i <= N; i++) {
        par[i] = i;
    }
}
unionfind::unionfind()
{
    par.resize(100010);
    siz.assign(100010, 1);
    val.assign(100010, 0);
    for (int i = 0; i <= 100010; i++) {
        par[i] = i;
    }
}
int unionfind::root(int v)
{
    if (v == par[v]) {
        return v;
    }
    return par[v] = root(par[v]);
}
void unionfind::merge(int a, int b)
{
    a = root(a);
    b = root(b);
    if (a == b) {
        return;
    }
    if (siz[a] < siz[b]) {
        int t = a;
        a = b;
        b = t;
    }
    par[b] = a;
    siz[a] += siz[b];
    /*
    ここにvalについての演算処理を書く
    */
}
bool unionfind::same(int a, int b)
{
    a = root(a);
    b = root(b);
    return a == b;
}
int unionfind::value(int a)
{
    return siz[this->root(a)];
}
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