結果

問題 No.1865 Make Cycle
ユーザー shobonvipshobonvip
提出日時 2022-03-04 23:20:01
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 2,714 bytes
コンパイル時間 278 ms
コンパイル使用メモリ 87,036 KB
実行使用メモリ 308,048 KB
最終ジャッジ日時 2023-09-26 02:35:41
合計ジャッジ時間 13,232 ms
ジャッジサーバーID
(参考情報)
judge12 / judge13
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 WA -
testcase_01 WA -
testcase_02 WA -
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 AC 73 ms
71,388 KB
testcase_21 WA -
testcase_22 WA -
testcase_23 WA -
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys
sys.setrecursionlimit(200000)


class UnionFind:
	"""
	class UnionFind
	https://note.nkmk.me/python-union-find/

	order O(log(n))

	n = the number of elements
	parents = the list that contains "parents" of x. be careful that it doesn't contain "root" of x.
	"""
	
	def __init__(self, n):
		"""
		make UnionFind
		:param n: the number of elements
		"""
		self.n = n
		self.parents = [-1]*n
		self.rr = [0] * n
	
	def find(self, x):
		"""
		:param x: an element
		:return: the root containing x
		"""
		if self.parents[x] < 0:
			return x
		else:
			self.parents[x] = self.find(self.parents[x])
			return self.parents[x]
	
	def union(self, x, y, r):
		"""
		:param x, y: an element
		"""
		# root
		x = self.find(x)
		y = self.find(y)
		if x == y:
			# already same group so do nothing
			return
		if self.parents[x] > self.parents[y]:
			# the root should be min of group
			x, y = y, x
		# remind that x, y is the root, x < y, then, y unions to x.
		self.parents[x] += self.parents[y]
		self.rr[x] = max([self.rr[x], self.rr[y], r])
		# and then y's parent is x.
		self.parents[y] = x
	
	def size(self, x):
		# return the size of group
		return -self.parents[self.find(x)]
	
	def same(self, x, y):
		# return whether the x, y are in same group
		return self.find(x) == self.find(y)
	
	def members(self, x):
		# return members of group
		root = self.find(x)
		return [i for i in range(self.n) if self.find(i) == root]
	
	def roots(self):
		# return all roots
		return [i for i, x in enumerate(self.parents) if x < 0]
	
	def group_count(self):
		# return how many groups
		return len(self.roots())
	
	def all_group_members(self):
		# return all members of all groups
		return {r:self.members(r) for r in self.roots()}


n, m = map(int, input().split())

ikeru = [[] for i in range(n)]
ikeruinv = [[] for i in range(n)]
for i in range(m):
	a, b = map(int, input().split())
	ikeru[a-1].append((b-1, i))
	ikeruinv[b-1].append((a-1, i))

tansaku = [0 for i in range(n)]
tansakuinv = [0 for i in range(n)]
dat = [0 for i in range(n)]
ichi = 0


def dfs(a):
	global ichi
	if tansaku[a] == 1:
		return
	tansaku[a] = 1
	for i, v in ikeru[a]:
		if tansaku[i] == 0:
			dfs(i)
	dat[a] = ichi
	ichi += 1
	return


def dfsinv(a):
	global ichi
	if tansakuinv[a] == 1:
		return
	tansakuinv[a] = 1
	for i, v in ikeruinv[a]:
		if tansakuinv[i] == 0:
			union.union(i, a, v)
			dfsinv(i)
	return


for i in range(n):
	dfs(i)

# print(dat)

union = UnionFind(n)
u = [(i, dat[i]) for i in range(n)]
u.sort(key=lambda x:-x[1])

for i, d in u:
	dfsinv(i)

# print(union.all_group_members())

ans = 10**18
for i in range(n):
	if union.parents[i] < 0:
		ans = min(ans, union.rr[i])

if ans == 10**18:
	print(-1)
else:
	print(ans)
0