結果

問題 No.737 PopCount
ユーザー eQeeQe
提出日時 2022-03-14 03:11:30
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 3 ms / 1,000 ms
コード長 4,314 bytes
コンパイル時間 4,781 ms
コンパイル使用メモリ 281,004 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-09-19 12:00:21
合計ジャッジ時間 5,184 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,248 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 AC 1 ms
5,376 KB
testcase_05 AC 2 ms
5,376 KB
testcase_06 AC 2 ms
5,376 KB
testcase_07 AC 3 ms
5,376 KB
testcase_08 AC 2 ms
5,376 KB
testcase_09 AC 2 ms
5,376 KB
testcase_10 AC 2 ms
5,376 KB
testcase_11 AC 2 ms
5,376 KB
testcase_12 AC 2 ms
5,376 KB
testcase_13 AC 2 ms
5,376 KB
testcase_14 AC 3 ms
5,376 KB
testcase_15 AC 2 ms
5,376 KB
testcase_16 AC 1 ms
5,376 KB
testcase_17 AC 2 ms
5,376 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <atcoder/all>
using namespace atcoder;
#include <bits/stdc++.h>
#define all(a) (a.begin()),(a.end())
#define rall(a) (a.rbegin()),(a.rend())
#define bitcnt(S) __builtin_popcountll(S)
#define fin(a) {pt(a);return 0;}
using namespace std;
using ll=long long;
using ld=long double;
using pll=pair<ll,ll>;
template<class T>using ascending_priority_queue = priority_queue<T, vector<T>, greater<T>>;
template<class T>using descending_priority_queue = priority_queue<T>;
template<class T>bool chmax(T &a, const T &b) {if(a<b) {a=b; return 1;} return 0;}
template<class T>bool chmin(T &a, const T &b) {if(b<a) {a=b; return 1;} return 0;}
istream& operator >> (istream& is, modint1000000007& x) { unsigned int t; is >> t; x=t; return is; }
istream& operator >> (istream& is, modint998244353& x) { unsigned int t; is >> t; x=t; return is; }
istream& operator >> (istream& is, modint& x) { unsigned int t; is >> t; x=t; return is; }
ostream& operator << (ostream& os, const modint1000000007& x) { os << x.val(); return os; }
ostream& operator << (ostream& os, const modint998244353& x) { os << x.val(); return os; }
ostream& operator << (ostream& os, const modint& x) { os << x.val(); return os; }
template<class T1, class T2>istream& operator >> (istream& is, pair<T1,T2>& p) { is >> p.first >> p.second; return is; }
template<class T1, class T2>ostream& operator << (ostream& os, const pair<T1,T2>& p) { os << p.first << " " << p.second; return os;}
template<class T>istream& operator >> (istream& is, vector<T>& v) { for(T& x:v) is >> x; return is; }
template<class T>ostream& operator << (ostream& os, const vector<T>& v) {for(int i=0;i<(int)v.size();i++) {os << v[i] << (i+1 == v.size() ? "":" ");} return os;}
template<class... A> void pt()      { std::cout << "\n"; }
template<class... A> void pt_rest() { std::cout << "\n"; }
template<class T, class... A> void pt_rest(const T& first, const A&... rest) { std::cout << " " << first; pt_rest(rest...); }
template<class T, class... A> void pt(const T& first, const A&... rest)      { std::cout << first; pt_rest(rest...); }
template<typename V, typename H> void resize(vector<V>& vec, const H head){ vec.resize(head); }
template<typename V, typename H, typename ... T> void resize(vector<V>& vec, const H& head, const T ... tail){ vec.resize(head); for(auto& v: vec) resize(v, tail...); }
template<typename V, typename T> void fill(V& x, const T& val){ x = val; }
template<typename V, typename T> void fill(vector<V>& vec, const T& val){ for(auto& v: vec) fill(v, val); }
template<typename H> void vin(istream& is, const int idx, vector<H>& head){ is >> head[idx]; }
template<typename H, typename ... T> void vin(istream& is, const int idx, vector<H>& head, T& ... tail){ vin(is >> head[idx], idx, tail...); }
template<typename H, typename ... T> void vin(istream& is, vector<H>& head, T& ... tail){ for(int i=0; i<(int)head.size(); i++) vin(is, i, head, tail...); }
template<typename H, typename ... T> void vin(vector<H>& head, T& ... tail){ vin(cin, head, tail...); }
map<ll,ll>divisor(ll n){map<ll,ll>res;for(ll i=1;i*i<=n;i++)if(n%i==0){res[i]++;res[n/i]++;}return res;}
map<ll,ll>factrization(ll n){map<ll,ll>res;for(ll i=2;i*i<=n;i++)while(n%i==0){res[i]++;n/=i;}if(n>1)res[n]++;return res;}
ll inf=1e18+7;
ld pi=acos(-1);
ld eps=1e-10;
using v1=vector<ll>;
using v2=vector<v1>;
using v3=vector<v2>;
using v4=vector<v3>;
using S=ll;
S op(S a,S b){return max(a,b);}
S e(){return 0;}

int main(void){
  cin.tie(nullptr);
  ios::sync_with_stdio(false);
  
  string s;cin>>s;
  s=bitset<60>(stoll(s)).to_string();
  reverse(all(s));
  while(s.back()=='0')s.pop_back();
  reverse(all(s));
  
  ll N=s.size();
  using mint=modint1000000007;
  vector<vector<vector<mint>>>dp;resize(dp,N+1,N+1,2);
  vector<vector<vector<mint>>>sum;resize(sum,N+1,N+1,2);
  dp[0][0][1]=1;
  sum[0][0][0]=0;
  for(ll i=0;i<N;i++){
    for(ll j=0;j<=N;j++){
      for(ll e=0;e<2;e++){
        ll cur=s[i]-'0';
        ll lim=(e?cur:1);
        for(ll x=0;x<=lim;x++){
          ll ne=(x<lim?0:e);
          ll nj=j+x;
          
          if(nj<=N){
            dp[i+1][nj][ne]+=dp[i][j][e];
            sum[i+1][nj][ne]+=sum[i][j][e]*2+dp[i][j][e]*x;
          }
        }
      }
    }
  }
  mint ans=0;
  for(ll j=0;j<=N;j++)for(ll e=0;e<2;e++)ans+=sum[N][j][e]*j;
  pt(ans);
}
0