結果
| 問題 | No.1547 [Cherry 2nd Tune *] 偶然の勝利の確率 |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2022-03-15 21:57:04 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 550 ms / 2,000 ms |
| コード長 | 1,577 bytes |
| 記録 | |
| コンパイル時間 | 151 ms |
| コンパイル使用メモリ | 82,452 KB |
| 実行使用メモリ | 77,148 KB |
| 最終ジャッジ日時 | 2024-09-22 14:19:10 |
| 合計ジャッジ時間 | 9,427 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 36 |
ソースコード
P = 998244353
m,n,S = map(int,input().split())
pa = m * pow(n,P-2,P) % P
qa = (1 - pa) % P
m,n,T = map(int,input().split())
pb = m * pow(n,P-2,P) % P
qb = (1 - pb) % P
K = int(input())
C = 205
SA = [0] * C
SB = [0] * C
now = qa
SA[0] = qa
for i in range(1,C):
now = now * pa % P
SA[i] = now
now = qb
SB[0] = now
for i in range(1,C):
now = now * pb % P
SB[i] = now
n = S + T + 1
def seki(x,y):
l = [[0] * n for _ in range(n)]
for i in range(n):
for j in range(n):
for k in range(n):
l[i][j] = (l[i][j] + x[i][k] * y[k][j]) % P
return l
e = [[0] * n for _ in range(n)]
for i in range(n):
e[i][i] = 1
R = [[0] * n for _ in range(n)]
for j in range(-T,S+1):
for i in range(-T,S+1):
if i == S:
if j != S:continue
R[S-j][S-i] = 1
continue
if i == -T:
if j != -T:continue
R[S-j][S-i] = 1
continue
if j == S:
tmp = pow(pa,S - i,P)
R[S-j][S-i] = tmp
continue
if j == -T:
tmp = 0
for k in range(i,S):
tmp += SA[k-i] * pow(pb,k-j,P) % P
tmp %= P
R[S-j][S-i] = tmp
continue
else:
delta = max(i,j)
tmp = 0
for k in range(delta,S):
tmp += SA[k-i] * SB[k - j] % P
tmp %= P
R[S-j][S-i] = tmp
while K:
if K & 1:
e = seki(e,R)
R = seki(R,R)
K >>= 1
a = e[0][S]
b = e[-1][S]
print(a)
print(b)