結果
問題 | No.1638 Robot Maze |
ユーザー |
|
提出日時 | 2022-03-24 16:47:21 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 875 ms / 2,000 ms |
コード長 | 3,418 bytes |
コンパイル時間 | 3,897 ms |
コンパイル使用メモリ | 234,144 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-10-13 00:56:19 |
合計ジャッジ時間 | 7,655 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 49 |
ソースコード
#include <bits/stdc++.h>#include <atcoder/all>typedef long long int ll;typedef long long int ull;#define MP make_pairusing namespace std;using namespace atcoder;typedef pair<ll, ll> P;// const ll MOD = 998244353;const ll MOD = 1000000007;// using mint = modint998244353;using mint = modint1000000007;const double pi = 3.1415926536;const int MAX = 2000003;long long fac[MAX], finv[MAX], inv[MAX];void COMinit() {fac[0] = fac[1] = 1;finv[0] = finv[1] = 1;inv[1] = 1;for (int i = 2; i < MAX; i++){fac[i] = fac[i - 1] * i % MOD;inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;finv[i] = finv[i - 1] * inv[i] % MOD;}}// 二項係数計算long long COM(int n, int k){if (n < k) return 0;if (n < 0 || k < 0) return 0;return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;}ll gcd(ll x, ll y) {if (y == 0) return x;else if (y > x) {return gcd (y, x);}else return gcd(x % y, y);}ll lcm (ll x, ll y) {return x / gcd(x, y) * y;}ll my_sqrt(ll x) {ll m = 0;ll M = 3000000001;while (M - m > 1) {ll now = (M + m) / 2;if (now * now <= x) {m = now;}else {M = now;}}return m;}ll keta(ll n) {ll ret = 0;while (n) {n /= 10;ret++;}return ret;}ll ceil(ll n, ll m) {// n > 0, m > 0ll ret = n / m;if (n % m) ret++;return ret;}ll pow_ll(ll x, ll n) {if (n == 0) return 1;if (n % 2) {return pow_ll(x, n - 1) * x;}else {ll tmp = pow_ll(x, n / 2);return tmp * tmp;}}int dx[4] = {-1, 1, 0, 0};int dy[4] = {0, 0, 1, -1};ll cost[4];char board[105][105];ll ct[105][105];typedef struct po {int x;int y;ll cst;bool operator>(const po & a) const {return cst > a.cst;}bool operator<(const po & a) const {return cst < a.cst;}bool operator==(const po & a) const {return cst == a.cst;}} point;int main() {int h, w;cin >> h >> w;for (int i = 0; i < 4; i++) cin >> cost[i];ll k, p;cin >> k >> p;int xs, ys, xt, yt;cin >> xs >> ys >> xt >> yt;for (int i = 0; i <= 104; i++) {for (int j = 0; j <= 104; j++) {board[i][j] = '#';ct[i][j] = k + 1;}}for (int i = 1; i <= h; i++) {string s;cin >> s;for (int j = 1; j <= w; j++) {board[i][j] = s[j - 1];}}priority_queue<point> que;point start;start.x = xs;start.y = ys;start.cst = 0;que.push(start);ct[xs][ys] = 0;while (que.size()) {point pos = que.top();que.pop();for (int i = 0; i < 4; i++) {int nx = pos.x + dx[i];int ny = pos.y + dy[i];ll ncst = pos.cst + cost[i];if (board[nx][ny] == '#') continue;if (board[nx][ny] == '@') ncst += p;if (ncst > k) continue;if (ncst >= ct[nx][ny]) continue;ct[nx][ny] = ncst;point npos;npos.x = nx;npos.y = ny;npos.cst = ncst;que.push(npos);}}if (ct[xt][yt] == k + 1) {cout << "No" << endl;}else {cout << "Yes" << endl;}return 0;}