結果

問題 No.1989 Pairing Multiset
ユーザー milkcoffee
提出日時 2022-03-27 20:19:55
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 13 ms / 2,000 ms
コード長 2,901 bytes
コンパイル時間 3,988 ms
コンパイル使用メモリ 229,984 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-11-06 16:31:58
合計ジャッジ時間 4,876 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 18
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#if __has_include(<atcoder/all>)
#include <atcoder/all>
using namespace atcoder;
#endif
using namespace std;
/*
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
*/
#define ll long long
#define rep(i, n) for (ll i = 0; i < n; ++i)
#define rep_up(i, a, n) for (ll i = a; i < n; ++i)
#define rep_down(i, a, n) for (ll i = a; i >= n; --i)
#define P pair<ll, ll>
#define pb push_back
#define bit_count(x) __builtin_popcountll(x)
#define gcd(a,b) __gcd(a,b)
#define lcm(a,b) a / gcd(a,b) * b
#define endl "\n"
#define all(v) v.begin(), v.end()
#define fi first
#define se second
#define vvvvll vector< vector <vector <vector<ll> > > >
#define vvvll vector< vector< vector<ll> > >
#define vvll vector< vector<ll> >
#define vll vector<ll>
#define pqll priority_queue<ll>
#define pqllg priority_queue<ll, vector<ll>, greater<ll>>
template<class T> inline void vin(vector<T>& v) { rep(i, v.size()) cin >> v.at(i); }
template <class T>
using V = vector<T>;
constexpr ll INF = (1ll << 60);
//constexpr ll mod = 1000000007;
constexpr ll mod = 998244353;
constexpr double pi = 3.14159265358979323846;
template <typename T>
inline bool chmax(T &a, T b)
{
if (a < b)
{
a = b;
return 1;
}
return 0;
}
template <typename T>
inline bool chmin(T &a, T b)
{
if (a > b)
{
a = b;
return 1;
}
return 0;
}
template <typename T>
void pt(T val)
{
cout << val << "\n";
}
template <typename T>
void pt_vll(vector<T> &v)
{
ll vs = v.size();
rep(i, vs)
{
cout << v[i];
if (i == vs - 1)
cout << "\n";
else
cout << " ";
}
}
ll mypow(ll a, ll n)
{
ll ret = 1;
if (n == 0)
return 1;
if (a == 0)
return 0;
rep(i, n)
{
if (ret > (ll)(9e18 + 10) / a)
return -1;
ret *= a;
}
return ret;
}
long long modpow(long long a, long long n, long long mod)
{
long long res = 1;
while (n > 0)
{
if (n & 1)
res = res * a % mod;
a = a * a % mod;
n >>= 1;
}
return res;
}
long long modinv(long long a, long long m)
{
long long b = m, u = 1, v = 0;
while (b)
{
long long t = a / b;
a -= t * b;
swap(a, b);
u -= t * v;
swap(u, v);
}
u %= m;
if (u < 0)
u += m;
return u;
}
void solve(){
ll n, m, k, cnt = 0, sum = 0, ans = 0;
cin>>n>>m;
assert(1<=n<=1000000&&1<=m<=1000000000);
ll x=1,y=1;
rep(i,2*n+1){
x*=2*n+m-i;
x%=mod;
y*=i+1;
y%=mod;
}
ans=x*modinv(y,mod);
ans%=mod;
ans*=n;
ans%=mod;
pt(ans);
}
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr);
//cout << fixed << setprecision(16);
//ll T;
//cin>>T;
//rep(ca,T)
solve();
}
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