結果
| 問題 |
No.1896 Arrays and XOR Procedure 2
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2022-04-08 22:06:02 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 98 ms / 2,000 ms |
| コード長 | 2,413 bytes |
| コンパイル時間 | 154 ms |
| コンパイル使用メモリ | 82,364 KB |
| 実行使用メモリ | 78,912 KB |
| 最終ジャッジ日時 | 2024-11-28 12:47:10 |
| 合計ジャッジ時間 | 6,410 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 27 |
ソースコード
from collections import deque
class Dinic:
def __init__(self, N):
self.N = N
self.G = [[] for i in range(N)]
def add_edge(self, fr, to, cap):
forward = [to, cap, None]
forward[2] = backward = [fr, 0, forward]
self.G[fr].append(forward)
self.G[to].append(backward)
def add_multi_edge(self, v1, v2, cap1, cap2):
edge1 = [v2, cap1, None]
edge1[2] = edge2 = [v1, cap2, edge1]
self.G[v1].append(edge1)
self.G[v2].append(edge2)
def bfs(self, s, t):
self.level = level = [None]*self.N
deq = deque([s])
level[s] = 0
G = self.G
while deq:
v = deq.popleft()
lv = level[v] + 1
for w, cap, _ in G[v]:
if cap and level[w] is None:
level[w] = lv
deq.append(w)
return level[t] is not None
def dfs(self, v, t, f):
if v == t:
return f
level = self.level
for e in self.it[v]:
w, cap, rev = e
if cap and level[v] < level[w]:
d = self.dfs(w, t, min(f, cap))
if d:
e[1] -= d
rev[1] += d
return d
return 0
def flow(self, s, t):
flow = 0
INF = 10**9 + 7
G = self.G
while self.bfs(s, t):
*self.it, = map(iter, self.G)
f = INF
while f:
f = self.dfs(s, t, INF)
flow += f
return flow
import sys,random,bisect
from collections import deque,defaultdict
from heapq import heapify,heappop,heappush
from itertools import permutations
from math import log,gcd
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
N = int(input())
A = li()
B = li()
for n in range(30)[::-1]:
f = 0
for i in range(N):
if A[i]>>n & 1 or B[i]>>n & 1:
f = 1
if f:
break
res = []
for i in range(N):
if A[i]>>n & 1:
for j in range(N):
if B[j]>>n & 1 == 0:
res.append((2,i,j))
B[j] ^= A[i]
break
else:
exit(print(0))
for i in range(N):
if A[i]>>n & 1:
res.append((1,i,0))
A[i] ^= B[0]
print(len(res))
for t,i,j in res:
print(t,i+1,j+1)
assert max(A) < min(B)