結果
| 問題 |
No.1900 Don't be Powers of 2
|
| コンテスト | |
| ユーザー |
tamato
|
| 提出日時 | 2022-04-08 22:45:27 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 1,577 ms / 2,000 ms |
| コード長 | 3,176 bytes |
| コンパイル時間 | 273 ms |
| コンパイル使用メモリ | 82,168 KB |
| 実行使用メモリ | 323,216 KB |
| 最終ジャッジ日時 | 2024-11-28 13:35:59 |
| 合計ジャッジ時間 | 16,470 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 42 |
ソースコード
mod = 998244353
def main():
import sys
input = sys.stdin.readline
from collections import deque
class Dinic:
def __init__(self, N):
self.N = N
self.adj = [[] for _ in range(N + 1)]
self.lv = None
self.progress = None
self.inf = 1 << 60
def add_edge(self, fr, to, cap):
# [to, cap, rev]
forward = [to, cap, None]
backward = forward[2] = [fr, 0, forward]
self.adj[fr].append(forward)
self.adj[to].append(backward)
def bfs(self, s, t):
que = deque([s])
lv = [-1] * (self.N + 1)
lv[s] = 0
while que:
v = que.popleft()
lvv = lv[v]
for u, cap, _ in self.adj[v]:
if cap and lv[u] == -1:
que.append(u)
lv[u] = lvv + 1
if u == t:
break
self.lv = lv
def dfs(self, s, t, flow):
st = deque([s])
st_f = deque([flow])
while st:
v = st[-1]
f = st_f[-1]
if v == t:
for i in range(len(st) - 1, 0, -1):
p = st[i - 1]
edge = self.adj[p][self.progress[p] - 1]
edge[1] -= f
edge[2][1] += f
return f
if self.progress[v] == len(self.adj[v]):
st.pop()
st_f.pop()
continue
else:
adj_v = self.adj[v]
for i in range(self.progress[v], len(adj_v)):
i = self.progress[v]
self.progress[v] = i + 1
u, cap, rev = adj_v[i]
if not cap or self.lv[u] != self.lv[v] + 1:
continue
else:
st.append(u)
st_f.append(min(st_f[-1], cap))
break
def max_flow(self, s, t):
flow = 0
while True:
self.bfs(s, t)
if self.lv[t] < 0:
return flow
self.progress = [0] * (self.N + 1)
flow_new = self.dfs(s, t, self.inf)
while flow_new:
flow += flow_new
flow_new = self.dfs(s, t, self.inf)
def popcount(n):
res = 0
for i in range(30):
res += n >> i & 1
return res
N = int(input())
A = list(map(int, input().split()))
D = Dinic(N + 2)
s = N + 1
t = s + 1
for i, a in enumerate(A):
k = popcount(a)
if k & 1:
D.add_edge(i + 1, t, 1)
else:
D.add_edge(s, i + 1, 1)
for j, b in enumerate(A):
if popcount(a ^ b) == 1:
D.add_edge(i + 1, j + 1, 1)
print(N - D.max_flow(s, t))
if __name__ == '__main__':
main()
tamato