結果
| 問題 |
No.1900 Don't be Powers of 2
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2022-04-08 23:41:01 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 1,196 ms / 2,000 ms |
| コード長 | 2,878 bytes |
| コンパイル時間 | 281 ms |
| コンパイル使用メモリ | 82,516 KB |
| 実行使用メモリ | 285,636 KB |
| 最終ジャッジ日時 | 2024-11-28 14:57:23 |
| 合計ジャッジ時間 | 28,112 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 42 |
ソースコード
from collections import deque
class MaxFlow:
inf = 10**18
class E:
def __init__(self,to,cap):
self.to = to
self.cap = cap
self.rev = None
def __init__(self,n):
self.n = n
self.graph = [[] for _ in range(n)]
def add_edge(self, fr, to, cap):
graph = self.graph
edge = self.E(to,cap)
edge2 = self.E(fr,0)
edge.rev = edge2
edge2.rev = edge
graph[fr].append(edge)
graph[to].append(edge2)
def bfs(self, s, t):
level = self.level = [self.n]*self.n
q = deque([s])
level[s] = 0
while q:
now = q.popleft()
lw = level[now]+1
for e in self.graph[now]:
if e.cap and level[e.to]> lw:
level[e.to] = lw
if e.to == t:
return True
q.append(e.to)
return False
def dfs(self, s, t, up):
graph = self.graph
it = self.it
level = self.level
st = deque([t])
while st:
v = st[-1]
if v == s:
st.pop()
flow = up
for w in st:
e = graph[w][it[w]].rev
flow = min(flow, e.cap)
for w in st:
e = graph[w][it[w]]
e.cap += flow
e.rev.cap -= flow
return flow
lv = level[v]-1
while it[v] < len(graph[v]):
e = graph[v][it[v]]
re = e.rev
if re.cap == 0 or lv != level[e.to]:
it[v] += 1
continue
st.append(e.to)
break
if it[v] == len(graph[v]):
st.pop()
level[v] = self.n
return 0
def flow(self,s,t,flow_limit=inf):
flow = 0
while flow < flow_limit and self.bfs(s,t):
self.it = [0]*self.n
while flow < flow_limit:
f = self.dfs(s,t,flow_limit-flow)
if f == 0:
break
flow += f
return flow
def min_cut(self,s):
visited = [0]*self.n
q = deque([s])
while q:
v = q.pop()
visited[v] = 1
for e in self.graph[v]:
if e.cap and not visited[e.to]:
q.append(e.to)
return visited
n = int(input())
A = list(map(int,input().split()))
s = n
t = n+1
mf = MaxFlow(t+1)
for i in range(n):
if bin(A[i]).count("1")%2 == 0:
mf.add_edge(i,t,1)
continue
mf.add_edge(s,i,1)
a = A[i]
for j in range(n):
if bin(a^A[j]).count("1") == 1:
mf.add_edge(i,j,1)
ans = n - mf.flow(s,t)
print(ans)