結果

問題 No.1324 Approximate the Matrix
ユーザー ああいいああいい
提出日時 2022-04-14 10:48:36
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 2,704 bytes
コンパイル時間 187 ms
コンパイル使用メモリ 81,920 KB
実行使用メモリ 89,728 KB
最終ジャッジ日時 2024-06-06 13:58:57
合計ジャッジ時間 13,682 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 39 ms
52,736 KB
testcase_01 AC 40 ms
52,736 KB
testcase_02 AC 40 ms
53,376 KB
testcase_03 AC 542 ms
83,160 KB
testcase_04 AC 518 ms
83,340 KB
testcase_05 AC 543 ms
83,936 KB
testcase_06 AC 506 ms
82,968 KB
testcase_07 AC 541 ms
83,724 KB
testcase_08 AC 124 ms
77,568 KB
testcase_09 AC 138 ms
77,872 KB
testcase_10 AC 155 ms
78,592 KB
testcase_11 AC 200 ms
79,104 KB
testcase_12 AC 146 ms
78,460 KB
testcase_13 AC 119 ms
77,248 KB
testcase_14 AC 204 ms
79,732 KB
testcase_15 AC 143 ms
77,920 KB
testcase_16 AC 106 ms
76,304 KB
testcase_17 AC 211 ms
78,976 KB
testcase_18 WA -
testcase_19 AC 140 ms
78,084 KB
testcase_20 AC 111 ms
76,880 KB
testcase_21 AC 119 ms
76,888 KB
testcase_22 AC 60 ms
68,352 KB
testcase_23 AC 198 ms
78,728 KB
testcase_24 AC 264 ms
80,428 KB
testcase_25 AC 215 ms
79,520 KB
testcase_26 AC 202 ms
79,276 KB
testcase_27 AC 163 ms
78,584 KB
testcase_28 AC 39 ms
52,480 KB
testcase_29 AC 48 ms
60,672 KB
testcase_30 AC 49 ms
60,160 KB
testcase_31 AC 58 ms
65,280 KB
testcase_32 AC 40 ms
52,992 KB
testcase_33 AC 40 ms
53,376 KB
testcase_34 AC 40 ms
53,120 KB
testcase_35 AC 40 ms
53,248 KB
testcase_36 AC 40 ms
53,248 KB
testcase_37 AC 1,208 ms
89,728 KB
testcase_38 AC 1,130 ms
89,716 KB
testcase_39 AC 1,219 ms
89,264 KB
testcase_40 AC 1,096 ms
89,728 KB
testcase_41 AC 1,058 ms
89,728 KB
testcase_42 AC 56 ms
69,376 KB
testcase_43 AC 56 ms
69,632 KB
testcase_44 AC 56 ms
69,632 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#その2 最初はコストが全部正の場合に使えるダイクストラ
from heapq import heappush,heappop
class MinCostFlow:
    inf = 10 ** 10

    def __init__(self,N):
        self.N = N
        self.G = [[] for _ in range(N)]
        self.H = [0] * N
        self.edge = []

    def add_edge(self,fr,to,cap,cost):
        e = [to,cap,cost,None]
        r = e[3] = [fr,0,-cost,e]
        self.G[fr].append(e)
        self.G[to].append(r)
        self.edge.append(e)
    def get_edge(self,i):
        return self.edge[i]

    def flow(self,s,t,f):
        N = self.N
        G = self.G
        inf = MinCostFlow.inf

        res = 0
        H = self.H  #ポテンシャル、コストが最初は正なので、最初は0でいい
        prev_v = [0] * N
        prev_e = [None] * N

        d0 = [inf] * N
        dist = [inf] * N
        while f:
            dist[:] = d0
            dist[s] = 0
            q = [(0,s)]
            while q:
                c,v = heappop(q)
                if dist[v] < c:continue
                if v == t:break
                r0 = dist[v] + H[v]
                for e in G[v]:
                    w,cap,cost,_ = e
                    if cap > 0 and r0 + cost - H[w] < dist[w]:
                        dist[w] = r = r0 + cost - H[w]
                        prev_v[w] = v
                        prev_e[w] = e
                        heappush(q,(r,w))
            if dist[t] == inf:
                return None
            """
            for i in range(N):
                H[i] += dist[i]
            """
            for i in range(N):
                if dist[i] < inf:
                    H[i] += dist[i]
            d = f
            v = t
            while v != s:
                d = min(d,prev_e[v][1])
                v = prev_v[v]
            f -= d
            res += d * H[t]
            v = t
            while v != s:
                e = prev_e[v]
                e[1] -= d
                e[3][1] += d
                v = prev_v[v]
        return res
import sys
rr = sys.stdin
N,K = map(int,rr.readline().split())
A = list(map(int,rr.readline().split()))
B = list(map(int,rr.readline().split()))
P = [list(map(int,rr.readline().split())) for _ in range(N)]

mincost = MinCostFlow(N + N + 2)
s = N + N
t = N + N + 1
inf = 400
for i in range(N):
    for j in range(N):
        v = N + j
        for k in range(1,min(A[i],B[j])+1):
            mincost.add_edge(i,v,1,inf + (2 * (k - 1) + 1 - 2 * P[i][j]))
for i in range(N):
    mincost.add_edge(s,i,A[i],0)
for j in range(N):
    mincost.add_edge(j + N,t,B[j],0)
ans = 0
for i in range(N):
    for j in range(N):
        ans += P[i][j] ** 2
ans += mincost.flow(s,t,K) - inf * K
print(ans)
0