結果
問題 | No.1935 Water Simulation |
ユーザー | miscalc |
提出日時 | 2022-05-13 21:57:00 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 3,932 bytes |
コンパイル時間 | 4,713 ms |
コンパイル使用メモリ | 272,064 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-07-22 04:34:09 |
合計ジャッジ時間 | 5,358 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 2 ms
5,376 KB |
testcase_16 | AC | 2 ms
5,376 KB |
testcase_17 | AC | 2 ms
5,376 KB |
testcase_18 | AC | 1 ms
5,376 KB |
testcase_19 | AC | 2 ms
5,376 KB |
testcase_20 | AC | 1 ms
5,376 KB |
testcase_21 | AC | 2 ms
5,376 KB |
testcase_22 | AC | 2 ms
5,376 KB |
testcase_23 | AC | 2 ms
5,376 KB |
testcase_24 | AC | 2 ms
5,376 KB |
testcase_25 | AC | 2 ms
5,376 KB |
testcase_26 | AC | 2 ms
5,376 KB |
testcase_27 | AC | 2 ms
5,376 KB |
testcase_28 | AC | 2 ms
5,376 KB |
testcase_29 | AC | 2 ms
5,376 KB |
testcase_30 | AC | 2 ms
5,376 KB |
testcase_31 | AC | 2 ms
5,376 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; //* #include <atcoder/all> using namespace atcoder; //using mint = modint998244353; using mint = modint1000000007; //*/ using ll = long long; using ld = long double; using pll = pair<ll, ll>; using tlll = tuple<ll, ll, ll>; constexpr ll INF = 1LL << 60; template<class T> bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;} template<class T> bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;} ll safemod(ll A, ll M) {return (A % M + M) % M;} ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;} ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);} ll mypowl(ll A, int B) {ll res = 1; for (int i = 0; i < B; i++) {res *= A;} return res;} template<class T> void unique(vector<T> &V) {V.erase(unique(V.begin(), V.end()), V.end());} template<class T> void sortunique(vector<T> &V) {sort(V.begin(), V.end()); V.erase(unique(V.begin(), V.end()), V.end());} #define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false) template<class T> void printvec(const vector<T> &V) {int _n = V.size(); for (int i = 0; i < _n; i++) cout << V[i] << (i == _n - 1 ? "" : " ");cout << '\n';} template<class T> void printvect(const vector<T> &V) {for (auto v : V) cout << v << '\n';} template<class T> void printvec2(const vector<vector<T>> &V) {for (auto &v : V) printvec(v);} void f(ll A, ll B, ll &a, ll &b) { ll x = min(a, B - b); a -= x; b += x; } void nxt(ll t, ll A, ll B, ll C, ll D, ll &a, ll &b, ll &c, ll &d) { if (t == 0) f(A, B, a, b); else if (t == 1) f(B, C, b, c); else if (t == 2) f(C, D, c, d); else if (t == 3) f(D, A, d, a); } /* a_{i + 1} = next_index(a_i) の漸化式が成り立っているとき conversion(a_1) add … add conversion(a_K) を求める t mul a = a add … add a (t 回) 計算量は各クエリ O(周期) add には結合法則と単位元 e を要求 */ template <typename Index, typename Data, Index (*next_index)(Index), Data (*conversion)(Index), Data (*add)(Data, Data), Data (*e)(), Data (*mul)(ll, Data)> struct Period { vector<Index> his; vector<Data> dat; int lambda, mu; Data head, tail; Period(Index start) { Index a = start, b = start; do { his.emplace_back(a); a = next_index(a); b = next_index(next_index(b)); } while (a != b); mu = his.size(); Index c = start; while (a != c) { his.emplace_back(a); a = next_index(a); c = next_index(c); } lambda = (int)his.size() - mu; dat.resize(his.size()); for (int i = 0; i < (int)his.size(); i++) dat[i] = conversion(his[i]); head = range_add(0, lambda); tail = range_add(lambda, lambda + mu); } Data range_add(int l, int r) // 半開区間 { Data res = e(); for (int i = l; i < r; i++) res = add(res, dat[i]); return res; } Data query(ll K) { if (K <= lambda + mu) return range_add(0, K); Data mid = range_add(lambda, lambda + (K - lambda) % mu); return add(add(head, mul((K - lambda) / mu, tail)), mid); } }; ll A, B, C, D; using tl5 = tuple<ll, ll, ll, ll, ll>; tl5 next_index(tl5 tabcd) { auto [t, a, b, c, d] = tabcd; nxt(t, A, B, C, D, a, b, c, d); t++, t %= 4; return {t, a, b, c, d}; } tl5 conversion(tl5 a) { return a; } tl5 e() { return {-1, -1, -1, -1, -1}; } tl5 add(tl5 a, tl5 b) { return b == e() ? a : b; } tl5 mul(ll t, tl5 a) { return a; } int main() { ll N; cin >> A >> B >> C >> D >> N; /* ll a = A, b = 0, c = 0, d = 0; for (ll i = 0; i < N; i++) { nxt(i % 4, A, B, C, D, a, b, c, d); cout << a << " " << b << " " << c << " " << d << endl; } //*/ Period<tl5, tl5, next_index, conversion, add, e, mul> pe({0, A, 0, 0, 0}); auto [t, a2, b2, c2, d2] = pe.query(N + 1); cout << a2 << " " << b2 << " " << c2 << " " << d2 << endl; }