結果

問題 No.1949 足し算するだけのパズルゲーム(2)
ユーザー KeroruKeroru
提出日時 2022-05-20 23:41:18
言語 PyPy3
(7.3.13)
結果
AC  
実行時間 522 ms / 3,000 ms
コード長 4,130 bytes
コンパイル時間 245 ms
コンパイル使用メモリ 81,840 KB
実行使用メモリ 109,108 KB
最終ジャッジ日時 2023-10-20 14:38:11
合計ジャッジ時間 7,835 ms
ジャッジサーバーID
(参考情報)
judge13 / judge12
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 140 ms
91,904 KB
testcase_01 AC 134 ms
91,900 KB
testcase_02 AC 133 ms
91,904 KB
testcase_03 AC 134 ms
91,900 KB
testcase_04 AC 142 ms
91,908 KB
testcase_05 AC 138 ms
91,900 KB
testcase_06 AC 134 ms
91,904 KB
testcase_07 AC 299 ms
94,264 KB
testcase_08 AC 181 ms
92,476 KB
testcase_09 AC 318 ms
94,504 KB
testcase_10 AC 329 ms
94,632 KB
testcase_11 AC 366 ms
94,752 KB
testcase_12 AC 323 ms
94,416 KB
testcase_13 AC 349 ms
94,816 KB
testcase_14 AC 362 ms
109,108 KB
testcase_15 AC 358 ms
109,080 KB
testcase_16 AC 146 ms
92,440 KB
testcase_17 AC 522 ms
106,000 KB
testcase_18 AC 146 ms
92,444 KB
testcase_19 AC 127 ms
91,908 KB
testcase_20 AC 128 ms
91,904 KB
testcase_21 AC 130 ms
91,852 KB
testcase_22 AC 425 ms
101,764 KB
testcase_23 AC 126 ms
91,896 KB
testcase_24 AC 286 ms
94,860 KB
testcase_25 AC 255 ms
94,116 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys
read=sys.stdin.buffer.read;readline=sys.stdin.buffer.readline;input=lambda:sys.stdin.readline().rstrip()
import bisect,string,math,time,functools,random,fractions
from bisect import*
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
from itertools import permutations,combinations,groupby
rep=range;R=range
def I():return int(input())
def LI():return [int(i) for i in input().split()]
def SLI():return sorted([int(i) for i in input().split()])
def LI_():return [int(i)-1 for i in input().split()]
def S_():return input()
def IS():return input().split()
def LS():return [i for i in input().split()]
def NI(n):return [int(input()) for i in range(n)]
def NI_(n):return [int(input())-1 for i in range(n)]
def NLI(n):return [[int(i) for i in input().split()] for i in range(n)]
def NLI_(n):return [[int(i)-1 for i in input().split()] for i in range(n)]
def StoLI():return [ord(i)-97 for i in input()]
def ItoS(n):return chr(n+97)
def LtoS(ls):return ''.join([chr(i+97) for i in ls])
def RLI(n=8,a=1,b=10):return [random.randint(a,b)for i in range(n)]
def RI(a=1,b=10):return random.randint(a,b)
def INP():
    N=3
    n=random.randint(1,N)
    n=3
    p=4
    mn,mx=1,100000000
    q=[[random.randint(mn,mx) for i in range(p)]for i in range(n)]
    return n,p,q
def Rtest(T):
    case,err=0,0
    for i in range(T):
        inp=INP()
        a1=naive(*inp)
        a2=solve(*inp)
        if a1!=a2:
            print(inp)
            print('naive',a1)
            print('solve',a2)
            err+=1
        case+=1
    print('Tested',case,'case with',err,'errors')
def GI(V,E,ls=None,Directed=False,index=1):
    org_inp=[];g=[[] for i in range(V)]
    FromStdin=True if ls==None else False
    for i in range(E):
        if FromStdin:
            inp=LI()
            org_inp.append(inp)
        else:
            inp=ls[i]
        if len(inp)==2:a,b=inp;c=1
        else:a,b,c=inp
        if index==1:a-=1;b-=1
        aa=a,c,;bb=b,c,;g[a].append(bb)
        if not Directed:g[b].append(aa)
    return g,org_inp
def RE(E):
    rt=[[]for i in range(len(E))]
    for i in range(len(E)):
        for nb,d in E[i]:
            rt[nb]+=(i,d),
    return rt
def GGI(h,w,search=None,replacement_of_found='.',mp_def={'#':1,'.':0},boundary=1):
    #h,w,g,sg=GGI(h,w,search=['S','G'],replacement_of_found='.',mp_def={'#':1,'.':0},boundary=1) # sample usage
    mp=[boundary]*(w+2);found={}
    for i in R(h):
        s=input()
        for char in search:
            if char in s:
                found[char]=((i+1)*(w+2)+s.index(char)+1)
                mp_def[char]=mp_def[replacement_of_found]
        mp+=[boundary]+[mp_def[j] for j in s]+[boundary]
    mp+=[boundary]*(w+2)
    return h+2,w+2,mp,found
def TI(n):return GI(n,n-1)
def accum(ls):
    rt=[0]
    for i in ls:rt+=[rt[-1]+i]
    return rt
def bit_combination(n,base=2):
    rt=[]
    for tb in R(base**n):s=[tb//(base**bt)%base for bt in R(n)];rt+=[s]
    return rt
def gcd(x,y):
    if y==0:return x
    if x%y==0:return y
    while x%y!=0:x,y=y,x%y
    return y
def RLE(it):
    rt=[]
    for i in it:
        if rt and rt[-1][0]==i:rt[-1][1]+=1
        else:rt+=[i,1],
    return rt
def YN(x):print(['NO','YES'][x])
def Yn(x):print(['No','Yes'][x])
def show(*inp,end='\n'):
    if show_flg:print(*inp,end=end)
def gcj(t,*a):
    print('Case #{}:'.format(t+1),*a)

mo=10**9+7
#mo=998244353
inf=float('inf')
FourNb=[(-1,0),(1,0),(0,1),(0,-1)];EightNb=[(-1,0),(1,0),(0,1),(0,-1),(1,1),(-1,-1),(1,-1),(-1,1)];compas=dict(zip('WENS',FourNb));cursol=dict(zip('LRUD',FourNb))
alp=[chr(ord('a')+i)for i in range(26)]
#sys.setrecursionlimit(10**7)


show_flg=False
show_flg=True


ans=0


h,w,y,x=LI()
#x-=1;y-=1
a=[[0]*(w+2)]
for i in range(h):
    a+=[0]+LI()+[0],
a+=[[0]*(w+2)]

t=a[y][x]
a[y][x]=0

q=[(0,(y,x))]
while q:
    e,(r,c)=heappop(q)
    #show(t,e)
    if t<=e:
        print('No')
        exit()
    t+=e
    for dr,dc in FourNb:
        nr,nc=r+dr,c+dc
        
        if a[nr][nc]>0:
            heappush(q,(a[nr][nc],(nr,nc)))
            #show((a[nr][nc],(nr,nc)),q)
            a[nr][nc]=0

print('Yes')
0