#764338 (Rust) No.1951 消えたAGCT(2)

• 問題: No.1951 消えたAGCT(2)
• ユーザー: koba-e964
• 提出日時: 2022-05-21 00:26:47
• 言語: Rust (1.77.0 + proconio)
• 結果: AC
• 実行時間: 114 ms / 3,000 ms
• コード長: 7,009 bytes
• コンパイル時間: 13,284 ms
• コンパイル使用メモリ: 379,920 KB
• 実行使用メモリ: 14,232 KB
• 最終ジャッジ日時: 2024-09-20 10:45:19
• 合計ジャッジ時間: 16,166 ms
• ジャッジサーバーID （参考情報）: judge5 / judge1

入力	結果	実行時間; 実行使用メモリ
testcase_00	AC	1 ms; 5,248 KB
testcase_01	AC	1 ms; 5,248 KB
testcase_02	AC	1 ms; 5,376 KB
testcase_03	AC	1 ms; 5,376 KB
testcase_04	AC	1 ms; 5,376 KB
testcase_05	AC	1 ms; 5,376 KB
testcase_06	AC	1 ms; 5,376 KB
testcase_07	AC	1 ms; 5,376 KB
testcase_08	AC	36 ms; 14,104 KB
testcase_09	AC	36 ms; 14,100 KB
testcase_10	AC	35 ms; 14,132 KB
testcase_11	AC	35 ms; 14,096 KB
testcase_12	AC	23 ms; 9,344 KB
testcase_13	AC	4 ms; 5,376 KB
testcase_14	AC	104 ms; 13,344 KB
testcase_15	AC	84 ms; 11,096 KB
testcase_16	AC	91 ms; 11,652 KB
testcase_17	AC	113 ms; 14,096 KB
testcase_18	AC	111 ms; 14,104 KB
testcase_19	AC	111 ms; 14,100 KB
testcase_20	AC	112 ms; 14,100 KB
testcase_21	AC	36 ms; 14,100 KB
testcase_22	AC	35 ms; 14,100 KB
testcase_23	AC	35 ms; 13,968 KB
testcase_24	AC	36 ms; 14,228 KB
testcase_25	AC	36 ms; 14,232 KB
testcase_26	AC	112 ms; 14,100 KB
testcase_27	AC	114 ms; 14,104 KB

ソースコード

#[allow(unused_imports)]
use std::cmp::*;
#[allow(unused_imports)]
use std::collections::*;
// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
    ($($r:tt)*) => {
        let stdin = std::io::stdin();
        let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));
        let mut next = move || -> String{
            bytes.by_ref().map(|r|r.unwrap() as char)
                .skip_while(|c|c.is_whitespace())
                .take_while(|c|!c.is_whitespace())
                .collect()
        };
        input_inner!{next, $($r)*}
    };
}

macro_rules! input_inner {
    ($next:expr) => {};
    ($next:expr,) => {};
    ($next:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($next, $t);
        input_inner!{$next $($r)*}
    };
}

macro_rules! read_value {
    ($next:expr, ( $($t:tt),* )) => { ($(read_value!($next, $t)),*) };
    ($next:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()
    };
    ($next:expr, chars) => {
        read_value!($next, String).chars().collect::<Vec<char>>()
    };
    ($next:expr, usize1) => (read_value!($next, usize) - 1);
    ($next:expr, [ $t:tt ]) => {{
        let len = read_value!($next, usize);
        read_value!($next, [$t; len])
    }};
    ($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));
}

/**
 * Segment Tree. This data structure is useful for fast folding on intervals of an array
 * whose elements are elements of monoid I. Note that constructing this tree requires the identity
 * element of I and the operation of I.
 * Verified by: yukicoder No. 259 (http://yukicoder.me/submissions/100581)
 *              AGC015-E (http://agc015.contest.atcoder.jp/submissions/1461001)
 *              yukicoder No. 833 (https://yukicoder.me/submissions/703521)
 */
struct SegTree<I, BiOp> {
    n: usize,
    orign: usize,
    dat: Vec<I>,
    op: BiOp,
    e: I,
}

impl<I, BiOp> SegTree<I, BiOp>
    where BiOp: Fn(I, I) -> I,
          I: Copy {
    pub fn new(n_: usize, op: BiOp, e: I) -> Self {
        let mut n = 1;
        while n < n_ { n *= 2; } // n is a power of 2
        SegTree {n: n, orign: n_, dat: vec![e; 2 * n - 1], op: op, e: e}
    }
    /* ary[k] <- v */
    pub fn update(&mut self, idx: usize, v: I) {
        debug_assert!(idx < self.orign);
        let mut k = idx + self.n - 1;
        self.dat[k] = v;
        while k > 0 {
            k = (k - 1) / 2;
            self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]);
        }
    }
    /* [a, b) (note: half-inclusive)
     * http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ */
    #[allow(unused)]
    pub fn query(&self, mut a: usize, mut b: usize) -> I {
        debug_assert!(a <= b);
        debug_assert!(b <= self.orign);
        let mut left = self.e;
        let mut right = self.e;
        a += self.n - 1;
        b += self.n - 1;
        while a < b {
            if (a & 1) == 0 {
                left = (self.op)(left, self.dat[a]);
            }
            if (b & 1) == 0 {
                right = (self.op)(self.dat[b - 1], right);
            }
            a = a / 2;
            b = (b - 1) / 2;
        }
        (self.op)(left, right)
    }
}

// Depends on: datastr/SegTree.rs
// Verified by: https://yukicoder.me/submissions/717436
impl<I, BiOp> SegTree<I, BiOp>
    where BiOp: Fn(I, I) -> I,
          I: Copy {
    // Port from https://github.com/atcoder/ac-library/blob/master/atcoder/segtree.hpp
    #[allow(unused)]
    fn max_right<F: Fn(I) -> bool>(
        &self, mut l: usize, f: &F,
    ) -> usize {
        assert!(f(self.e));
        if l == self.orign {
            return self.orign;
        }
        l += self.n - 1;
        let mut sm = self.e;
        loop {
            while l % 2 == 1 {
                l = (l - 1) / 2;
            }
            if !f((self.op)(sm, self.dat[l])) {
                while l < self.n - 1 {
                    l = 2 * l + 1;
                    let val = (self.op)(sm, self.dat[l]);
                    if f(val) {
                        sm = val;
                        l += 1;
                    }
                }
                return std::cmp::min(self.orign, l + 1 - self.n);
            }
            sm = (self.op)(sm, self.dat[l]);
            l += 1;
            if (l + 1).is_power_of_two() { break; }
        }
        self.orign
    }
    // Port from https://github.com/atcoder/ac-library/blob/master/atcoder/segtree.hpp
    #[allow(unused)]
    fn min_left<F: Fn(I) -> bool>(
        &self, mut r: usize, f: &F,
    ) -> usize {
        if !f(self.e) {
            return r + 1;
        }
        if r == 0 {
            return 0;
        }
        r += self.n - 1;
        let mut sm = self.e;
        loop {
            r -= 1;
            while r > 0 && r % 2 == 0 {
                r = (r - 1) / 2;
            }
            if !f((self.op)(self.dat[r], sm)) {
                while r < self.n - 1 {
                    r = 2 * r + 2;
                    let val = (self.op)(self.dat[r], sm);
                    if f(val) {
                        sm = val;
                        r -= 1;
                    }
                }
                return r + 2 - self.n;
            }
            sm = (self.op)(self.dat[r], sm);
            if (r + 1).is_power_of_two() { break; }
        }
        0
    }
}

trait Change { fn chmax(&mut self, x: Self); fn chmin(&mut self, x: Self); }
impl<T: PartialOrd> Change for T {
    fn chmax(&mut self, x: T) { if *self < x { *self = x; } }
    fn chmin(&mut self, x: T) { if *self > x { *self = x; } }
}

fn main() {
    // In order to avoid potential stack overflow, spawn a new thread.
    let stack_size = 104_857_600; // 100 MB
    let thd = std::thread::Builder::new().stack_size(stack_size);
    thd.spawn(|| solve()).unwrap().join().unwrap();
}

fn solve() {
    input! {
        n: usize,
        s: chars,
    }
    let s: Vec<usize> = s.into_iter().map(|c| (c as u8 - b'A') as usize)
        .collect();
    let mut freq = [0; 26];
    for &c in &s {
        freq[c] += 1;
    }
    let pat: Vec<_> = b"AGCT".iter().map(|&c| (c - b'A') as usize).collect();
    let mut sh = 0;
    let mut ans = 0;
    let mut alive = vec![true; n];
    let mut st = SegTree::new(n, |x, y| x + y, 0);
    for i in 0..n {
        st.update(i, 1);
    }
    loop {
        if false {
            for i in 0..n {
                if alive[i] {
                    eprint!("{}", (b'A' + ((s[i] + sh) % 26) as u8) as char);
                }
            }
            eprintln!();
        }
        let agct: usize = pat.iter().map(|&idx| freq[(idx + 26 - sh) % 26]).sum();
        if agct == 0 { break; }
        ans += 1;
        let rm = st.max_right(0, &|x| x < agct);
        assert!(alive[rm]);
        alive[rm] = false;
        st.update(rm, 0);
        freq[s[rm]] -= 1;
        let c2 = freq[s[rm]];
        sh = (sh + c2) % 26;
    }
    println!("{}", ans);
}