結果
問題 | No.1973 Divisor Sequence |
ユーザー | xyz2606 |
提出日時 | 2022-06-10 21:39:59 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 129 ms / 2,000 ms |
コード長 | 4,603 bytes |
コンパイル時間 | 2,593 ms |
コンパイル使用メモリ | 155,272 KB |
実行使用メモリ | 81,896 KB |
最終ジャッジ日時 | 2024-09-21 07:27:37 |
合計ジャッジ時間 | 4,431 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 13 ms
6,812 KB |
testcase_01 | AC | 12 ms
6,940 KB |
testcase_02 | AC | 47 ms
79,808 KB |
testcase_03 | AC | 15 ms
9,996 KB |
testcase_04 | AC | 29 ms
48,708 KB |
testcase_05 | AC | 26 ms
43,288 KB |
testcase_06 | AC | 35 ms
66,596 KB |
testcase_07 | AC | 17 ms
14,520 KB |
testcase_08 | AC | 24 ms
37,088 KB |
testcase_09 | AC | 26 ms
42,732 KB |
testcase_10 | AC | 41 ms
54,156 KB |
testcase_11 | AC | 15 ms
11,008 KB |
testcase_12 | AC | 31 ms
54,148 KB |
testcase_13 | AC | 20 ms
18,876 KB |
testcase_14 | AC | 29 ms
23,892 KB |
testcase_15 | AC | 32 ms
58,568 KB |
testcase_16 | AC | 38 ms
68,584 KB |
testcase_17 | AC | 36 ms
43,828 KB |
testcase_18 | AC | 15 ms
6,944 KB |
testcase_19 | AC | 52 ms
58,068 KB |
testcase_20 | AC | 17 ms
12,680 KB |
testcase_21 | AC | 47 ms
81,112 KB |
testcase_22 | AC | 36 ms
57,632 KB |
testcase_23 | AC | 129 ms
81,764 KB |
testcase_24 | AC | 113 ms
81,896 KB |
ソースコード
#include<vector> #include<set> #include<map> #include<queue> #include<string> #include<algorithm> #include<iostream> #include<bitset> #include<functional> #include<chrono> #include<numeric> #include<cstdio> #include<cstring> #include<cstdlib> #include<cassert> #include<cmath> #include<iomanip> #include<random> #include<ctime> #include<complex> #include<type_traits> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; typedef long long LL; typedef double D; #define all(v) (v).begin(), (v).end() mt19937 gene(chrono::system_clock::now().time_since_epoch().count()); typedef complex<double> Complex; #define fi first #define se second #define ins insert #define pb push_back inline char GET_CHAR(){ const int maxn = 131072; static char buf[maxn],*p1=buf,*p2=buf; return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++; } inline int getInt() { int res(0); char c = getchar(); while(c < '0') c = getchar(); while(c >= '0') { res = res * 10 + (c - '0'); c = getchar(); } return res; } inline LL fastpo(LL x, LL n, LL mod) { LL res(1); while(n) { if(n & 1) { res = res * (LL)x % mod; } x = x * (LL) x % mod; n /= 2; } return res; } template<LL mod> struct Num { LL a; Num operator + (const Num & b) { return Num{(a + b.a) % mod}; } Num operator - (const Num & b) { return Num{(a - b.a + mod) % mod}; } Num operator * (const Num & b) { return Num{a * b.a % mod}; } Num operator / (const Num & b) { return Num{a * fastpo(b.a, mod - 2, mod) % mod}; } void operator += (const Num & b) {if((a += b.a) >= mod) a -= mod;} void operator -= (const Num & b) {if((a -= b.a) < 0) a += mod;} void operator *= (const Num & b) { a = a * b.a % mod; } void operator /= (const Num & b) { a = a * fastpo(b.a, mod - 2, mod) % mod; } void operator = (const Num & b) { a = b.a; } void operator = (const LL & b) { a = b; } }; template<LL mod> ostream & operator << (ostream & os, const Num<mod> & a) { os << a.a; return os; } LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; } inline string itoa(LL x, int width = 0) { string res; if(x == 0) res.push_back('0'); while(x) { res.push_back('0' + x % 10); x /= 10; } while((int)res.size() < width) res.push_back('0'); reverse(res.begin(), res.end()); return res; } const int _B = 131072; char buf[_B]; int _bl = 0; inline void flush() { fwrite(buf, 1, _bl, stdout); _bl = 0; } __inline void _putchar(char c) { if(_bl == _B) flush(); buf[_bl++] = c; } inline void print(LL x, char c) { static char tmp[20]; int l = 0; if(!x) tmp[l++] = '0'; else { while(x) { tmp[l++] = x % 10 + '0'; x /= 10; } } for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]); _putchar(c); } typedef double C; struct P { C x, y; void scan() { double _x, _y; scanf("%lf%lf", &_x, &_y); x = _x; y = _y; } void print() { cout << '(' << x << ' ' << y << ')' << endl; } P operator + (const P & b) const { return P{x + b.x, y + b.y}; } P operator - (const P & b) const { return P{x - b.x, y - b.y}; } C operator * (const P & b) const { return x * b.y - y * b.x; } C operator % (const P & b) const { return x * b.x + y * b.y; } }; P operator * (const C & x, const P & b) { return P{x * b.x, x * b.y}; } const int N = 300033; const int LOG = 20; const int mod = 1e9 + 7; const int inf = 1e9 + 7; int n, m; int dx[4] = {1, 0, -1, 0}; int dy[4] = {0, 1, 0, -1}; int rela[N]; int getr(int x) { int p = x; while(rela[p] != p) p = rela[p]; int p1 = p; p = x; while(rela[p] != p) { int p2 = rela[p]; rela[p] = p1; p = p2; } return p1; } int dp[500055][40]; int main() { int n; LL m; map<LL, int> mp, a; scanf("%d%lld", &n, &m); for(int i = 2; i <= 1000000; i++) { while(m % i == 0) { mp[i]++; m /= i; } } if(m > 1) mp[m] = 1; int ans = 1; for(auto t : mp) { if(a.count(t.se)) { ans = (LL)ans * a[t.se] % mod; continue; } for(int i = 0; i <= n; i++) for(int j = 0; j <= t.se; j++) dp[i][j] = 0; dp[0][0] = 1; for(int i = 1; i <= n; i++) { for(int j = 1; j <= t.se; j++) { dp[i - 1][j] = (dp[i - 1][j - 1] + dp[i - 1][j]) % mod; } for(int j = 0; j <= t.se; j++) { dp[i][j] = dp[i - 1][t.se - j]; } } int tmp = 0; for(int j = 0; j <= t.se; j++) tmp = (tmp + dp[n][j]) % mod; a[t.se] = tmp; ans = (LL)ans * tmp % mod; } cout << ans << endl; }