結果
問題 | No.1974 2x2 Flipper |
ユーザー | xyz2606 |
提出日時 | 2022-06-10 21:49:46 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 99 ms / 2,000 ms |
コード長 | 4,504 bytes |
コンパイル時間 | 2,460 ms |
コンパイル使用メモリ | 145,888 KB |
実行使用メモリ | 9,236 KB |
最終ジャッジ日時 | 2024-09-21 07:06:17 |
合計ジャッジ時間 | 5,010 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 13 ms
6,940 KB |
testcase_02 | AC | 3 ms
6,948 KB |
testcase_03 | AC | 67 ms
8,468 KB |
testcase_04 | AC | 31 ms
6,940 KB |
testcase_05 | AC | 19 ms
6,940 KB |
testcase_06 | AC | 47 ms
7,100 KB |
testcase_07 | AC | 33 ms
9,236 KB |
testcase_08 | AC | 8 ms
6,944 KB |
testcase_09 | AC | 50 ms
7,776 KB |
testcase_10 | AC | 9 ms
6,940 KB |
testcase_11 | AC | 38 ms
6,944 KB |
testcase_12 | AC | 65 ms
8,096 KB |
testcase_13 | AC | 41 ms
7,944 KB |
testcase_14 | AC | 26 ms
6,940 KB |
testcase_15 | AC | 76 ms
7,776 KB |
testcase_16 | AC | 9 ms
6,940 KB |
testcase_17 | AC | 62 ms
7,984 KB |
testcase_18 | AC | 8 ms
6,940 KB |
testcase_19 | AC | 9 ms
6,944 KB |
testcase_20 | AC | 31 ms
6,940 KB |
testcase_21 | AC | 98 ms
8,756 KB |
testcase_22 | AC | 97 ms
7,956 KB |
testcase_23 | AC | 98 ms
8,104 KB |
testcase_24 | AC | 99 ms
8,400 KB |
testcase_25 | AC | 2 ms
6,940 KB |
ソースコード
#include<vector> #include<set> #include<map> #include<queue> #include<string> #include<algorithm> #include<iostream> #include<bitset> #include<functional> #include<chrono> #include<numeric> #include<cstdio> #include<cstring> #include<cstdlib> #include<cassert> #include<cmath> #include<iomanip> #include<random> #include<ctime> #include<complex> #include<type_traits> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; typedef long long LL; typedef double D; #define all(v) (v).begin(), (v).end() mt19937 gene(chrono::system_clock::now().time_since_epoch().count()); typedef complex<double> Complex; #define fi first #define se second #define ins insert #define pb push_back inline char GET_CHAR(){ const int maxn = 131072; static char buf[maxn],*p1=buf,*p2=buf; return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++; } inline int getInt() { int res(0); char c = getchar(); while(c < '0') c = getchar(); while(c >= '0') { res = res * 10 + (c - '0'); c = getchar(); } return res; } inline LL fastpo(LL x, LL n, LL mod) { LL res(1); while(n) { if(n & 1) { res = res * (LL)x % mod; } x = x * (LL) x % mod; n /= 2; } return res; } template<LL mod> struct Num { LL a; Num operator + (const Num & b) { return Num{(a + b.a) % mod}; } Num operator - (const Num & b) { return Num{(a - b.a + mod) % mod}; } Num operator * (const Num & b) { return Num{a * b.a % mod}; } Num operator / (const Num & b) { return Num{a * fastpo(b.a, mod - 2, mod) % mod}; } void operator += (const Num & b) {if((a += b.a) >= mod) a -= mod;} void operator -= (const Num & b) {if((a -= b.a) < 0) a += mod;} void operator *= (const Num & b) { a = a * b.a % mod; } void operator /= (const Num & b) { a = a * fastpo(b.a, mod - 2, mod) % mod; } void operator = (const Num & b) { a = b.a; } void operator = (const LL & b) { a = b; } }; template<LL mod> ostream & operator << (ostream & os, const Num<mod> & a) { os << a.a; return os; } LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; } inline string itoa(LL x, int width = 0) { string res; if(x == 0) res.push_back('0'); while(x) { res.push_back('0' + x % 10); x /= 10; } while((int)res.size() < width) res.push_back('0'); reverse(res.begin(), res.end()); return res; } const int _B = 131072; char buf[_B]; int _bl = 0; inline void flush() { fwrite(buf, 1, _bl, stdout); _bl = 0; } __inline void _putchar(char c) { if(_bl == _B) flush(); buf[_bl++] = c; } inline void print(LL x, char c) { static char tmp[20]; int l = 0; if(!x) tmp[l++] = '0'; else { while(x) { tmp[l++] = x % 10 + '0'; x /= 10; } } for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]); _putchar(c); } typedef double C; struct P { C x, y; void scan() { double _x, _y; scanf("%lf%lf", &_x, &_y); x = _x; y = _y; } void print() { cout << '(' << x << ' ' << y << ')' << endl; } P operator + (const P & b) const { return P{x + b.x, y + b.y}; } P operator - (const P & b) const { return P{x - b.x, y - b.y}; } C operator * (const P & b) const { return x * b.y - y * b.x; } C operator % (const P & b) const { return x * b.x + y * b.y; } }; P operator * (const C & x, const P & b) { return P{x * b.x, x * b.y}; } const int N = 300033; const int LOG = 20; const int mod = 1e9 + 7; const int inf = 1e9 + 7; int n, m; int dx[4] = {1, 0, -1, 0}; int dy[4] = {0, 1, 0, -1}; int rela[N]; int getr(int x) { int p = x; while(rela[p] != p) p = rela[p]; int p1 = p; p = x; while(rela[p] != p) { int p2 = rela[p]; rela[p] = p1; p = p2; } return p1; } int a[1111][1111]; int main() { int h, w; scanf("%d%d", &h, &w); int ans = 0; for(int i = 1; i + 1 <= h; i += 2) { for(int j = 1; j + 1 <= w; j += 2) { a[i][j] = a[i + 1][j] = a[i][j + 1] = a[i + 1][j + 1] = 1; ans += 4; } } if(h % 2 == 1 && w % 2 == 1) { ans = h * w - max(h, w); for(int i = 1; i <= h; i++) { for(int j = 1; j <= w; j++) { if(i > w && j == 1 || j > h && i == 1) a[i][j] = 0; else if(i <= w && j <= h && i + j == min(w, h) + 1) a[i][j] = 0; else a[i][j] = 1; } } } printf("%d\n", ans); for(int i = 1; i <= h; i++) { for(int j = 1; j <= w; j++) { printf("%d%c", a[i][j], j == w ? '\n' : ' '); } } }