結果
| 問題 |
No.1973 Divisor Sequence
|
| コンテスト | |
| ユーザー |
hir355
|
| 提出日時 | 2022-06-10 22:14:56 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 208 ms / 2,000 ms |
| コード長 | 1,313 bytes |
| コンパイル時間 | 318 ms |
| コンパイル使用メモリ | 82,660 KB |
| 実行使用メモリ | 76,536 KB |
| 最終ジャッジ日時 | 2024-09-21 07:30:25 |
| 合計ジャッジ時間 | 2,548 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 22 |
ソースコード
from collections import Counter
def prime_factorize(n):
a = []
while n % 2 == 0:
a.append(2)
n //= 2
f = 3
while f * f <= n:
while n % f == 0:
a.append(f)
n //= f
else:
f += 2
if n != 1:
a.append(n)
return a
MOD = 10 ** 9 + 7
n, m = map(int, input().split())
pr = Counter(prime_factorize(m))
res = 1
for x in pr.values():
mat = [[0] * (x + 1) for _ in range(x + 1)]
ans = [[0] * (x + 1) for _ in range(x + 1)]
for i in range(x + 1):
ans[i][i] = 1
for j in range(x + 1 - i):
mat[i][j] = 1
tk = n + 1
while tk > 0:
if tk & 1:
t = [[0] * (x + 1) for _ in range(x + 1)]
for i in range(x + 1):
for j in range(x + 1):
for k in range(x + 1):
t[i][j] += mat[i][k] * ans[k][j] % MOD
for i in range(x + 1):
ans[i] = t[i][:]
t = [[0] * (x + 1) for _ in range(x + 1)]
for i in range(x + 1):
for j in range(x + 1):
for k in range(x + 1):
t[i][j] += mat[i][k] * mat[k][j] % MOD
for i in range(x + 1):
mat[i] = t[i][:]
tk >>= 1
res *= ans[0][0]
print(res % MOD)
hir355