結果

問題 No.1977 Extracting at Constant Intervals
ユーザー xyz2606xyz2606
提出日時 2022-06-10 23:12:53
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 23 ms / 2,000 ms
コード長 5,523 bytes
コンパイル時間 2,345 ms
コンパイル使用メモリ 152,268 KB
実行使用メモリ 9,040 KB
最終ジャッジ日時 2024-10-09 09:43:28
合計ジャッジ時間 3,819 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<vector>
#include<set>
#include<map>
#include<queue>
#include<string>
#include<algorithm>
#include<iostream>
#include<bitset>
#include<functional>
#include<chrono>
#include<numeric>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cassert>
#include<cmath>
#include<iomanip>
#include<random>
#include<ctime>
#include<complex>
#include<type_traits>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long LL;
typedef double D;
#define all(v) (v).begin(), (v).end()
mt19937 gene(chrono::system_clock::now().time_since_epoch().count());
typedef complex<double> Complex;
#define fi first
#define se second
#define ins insert
#define pb push_back
inline char GET_CHAR(){
    const int maxn = 131072;
    static char buf[maxn],*p1=buf,*p2=buf;
    return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++;
}
inline int getInt() {
    int res(0);
    char c = getchar();
    while(c < '0') c = getchar();
    while(c >= '0') {
        res = res * 10 + (c - '0');
        c = getchar();
    }
    return res;
}
inline LL fastpo(LL x, LL n, LL mod) {
    LL res(1);
    while(n) {
        if(n & 1) {
            res = res * (LL)x % mod;
        }
        x = x * (LL) x % mod;
        n /= 2;
    }
    return res;
}
template<LL mod> struct Num {
	LL a;
	Num operator + (const Num & b) { return Num{(a + b.a) % mod}; }
	Num operator - (const Num & b) { return Num{(a - b.a + mod) % mod}; }
	Num operator * (const Num & b) { return Num{a * b.a % mod}; }
	Num operator / (const Num & b) { return Num{a * fastpo(b.a, mod - 2, mod) % mod}; }
	void operator += (const Num & b) {if((a += b.a) >= mod) a -= mod;}
	void operator -= (const Num & b) {if((a -= b.a) < 0) a += mod;}
	void operator *= (const Num & b) { a = a * b.a % mod; }
	void operator /= (const Num & b) { a = a * fastpo(b.a, mod - 2, mod) % mod; }
	void operator = (const Num & b) { a = b.a; }
	void operator = (const LL & b) { a = b; }
};
template<LL mod> ostream & operator << (ostream & os, const Num<mod> & a) {
	os << a.a;
	return os;
}
LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; }

inline string itoa(LL x, int width = 0) {
	string res;
	if(x == 0) res.push_back('0');
	while(x) {
		res.push_back('0' + x % 10);
		x /= 10;
	}
	while((int)res.size() < width) res.push_back('0');
	reverse(res.begin(), res.end());
	return res;
}
const int _B = 131072;
char buf[_B];
int _bl = 0;
inline void flush() {
	fwrite(buf, 1, _bl, stdout);
	_bl = 0;
}
__inline void _putchar(char c) {
	if(_bl == _B) flush();
	buf[_bl++] = c;
}
inline void print(LL x, char c) {
	static char tmp[20];
	int l = 0;
	if(!x) tmp[l++] = '0';
	else {
		while(x) {
			tmp[l++] = x % 10 + '0';
			x /= 10;
		}
	}
	for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]);
	_putchar(c);
}
typedef double C;
struct P {
	C x, y;
	void scan() {
		double _x, _y;
		scanf("%lf%lf", &_x, &_y);
		x = _x; y = _y;
	}
	void print() {
		cout << '(' << x << ' ' << y << ')' << endl;
	}
	P operator + (const P & b) const { return P{x + b.x, y + b.y}; }
	P operator - (const P & b) const { return P{x - b.x, y - b.y}; }
	C operator * (const P & b) const { return x * b.y - y * b.x; }
	C operator % (const P & b) const { return x * b.x + y * b.y; }
};
P operator * (const C & x, const P & b) { return P{x * b.x, x * b.y}; }
const int N = 300033;
const int LOG = 20;
const int mod = 1e9 + 7;
const int inf = 1e9 + 7;
int n, m;
int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};
int rela[N];
int getr(int x) {
    int p = x;
    while(rela[p] != p) p = rela[p];
    int p1 = p; p = x;
    while(rela[p] != p) {
        int p2 = rela[p];
        rela[p] = p1;
        p = p2;
    }
    return p1;
}
int a[N], tp[N], pos[N], vst[N];
vector<vector<int> > tot;
int get_interval(const vector<int> & vec, int s, int len) {
	int n = vec.size();
	if(len == 0) return 0;
	if(s + len - 1 < n) {
		return vec[s + len - 1] - (s == 0 ? 0 : vec[s - 1]);
	}else {
		return vec[n - 1] - vec[s - 1] + vec[len - (n - s) - 1];
	}
}
int main() {
	int n, m;
	LL l;
	scanf("%d%d%lld", &n, &m, &l);
//n = 1e5;
//m = 1e9;
//l = 1;
	for(int i = 0; i < n; i++) {
		scanf("%d", &a[i]);
//a[i] = 1e4;
	}
	LL len = n * (LL)m;
	for(int i = 0; i < n; i++) {
		if(vst[i]) continue;
		tot.pb(vector<int>());
		for(int j = i; ; j = (j + l) % n) {
			vst[j] = true;
			tp[j] = tot.size() - 1;
			pos[j] = tot.back().size();
			tot.back().pb(tot.back().size() == 0 ? a[j] : tot.back().back() + a[j]);
			//cout << j << ' ' << pos[j] << ' ' << tot.back().back() << endl;
			if((j + l) % n == i) break;
		}
	}
	LL ans = inf * (LL)-inf;
	for(LL s = l - 1; s >= l - n && s >= 0; s--) {
		LL k = (len - s + l - 1) / l;
		LL sm = s % n;
		//cout << k << ' ' << sm << endl;
		//cout << "!" << tp[sm] << ' ' << tot[tp[sm]].size() << ' ' << tot[tp[sm]].back() << endl;
		LL tmp = (LL)(k / tot[tp[sm]].size()) * tot[tp[sm]].back();
		tmp = tmp + get_interval(tot[tp[sm]], pos[sm], k % tot[tp[sm]].size());
		ans = max(ans, tmp);
	}
	for(LL s = 0; s < n && s < l; s++) {
		LL k = (len - s + l - 1) / l;
		LL sm = s % n;
		//cout << k << ' ' << sm << endl;
		//cout << "!" << tp[sm] << ' ' << tot[tp[sm]].size() << ' ' << tot[tp[sm]].back() << endl;
		LL tmp = (LL)(k / tot[tp[sm]].size()) * tot[tp[sm]].back();
		tmp = tmp + get_interval(tot[tp[sm]], pos[sm], k % tot[tp[sm]].size());
		ans = max(ans, tmp);
	}
	cout << ans << endl;
}
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